#include <iostream>
#include <string>
#include <sstream>
using namespace std;
string itos(int i) // convert int to string
{
    stringstream s;
    s << i;
    return s.str();
}

无耻地从http://www.research.att.com/~bs/bs_faq2.html窃取。

在c++ 20中，你可以做到:

auto result = std::format("{}{}", name, age);

与此同时，你可以使用{fmt}库，std::format基于:

auto result = fmt::format("{}{}", name, age);

声明:我是{fmt}库和c++ 20 std::格式的作者。

如果你有c++ 11，你可以使用std::to_string。

例子:

std::string name = "John";
int age = 21;

name += std::to_string(age);

std::cout << name;

输出:

John21

我写了一个函数，它以int数作为参数，并将其转换为字符串字面量。此函数依赖于另一个函数，该函数将单个数字转换为其char等价:

char intToChar(int num)
{
    if (num < 10 && num >= 0)
    {
        return num + 48;
        //48 is the number that we add to an integer number to have its character equivalent (see the unsigned ASCII table)
    }
    else
    {
        return '*';
    }
}

string intToString(int num)
{
    int digits = 0, process, single;
    string numString;
    process = num;

    // The following process the number of digits in num
    while (process != 0)
    {
        single  = process % 10; // 'single' now holds the rightmost portion of the int
        process = (process - single)/10;
        // Take out the rightmost number of the int (it's a zero in this portion of the int), then divide it by 10
        // The above combination eliminates the rightmost portion of the int
        digits ++;
    }

    process = num;

    // Fill the numString with '*' times digits
    for (int i = 0; i < digits; i++)
    {
        numString += '*';
    }


    for (int i = digits-1; i >= 0; i--)
    {
        single = process % 10;
        numString[i] = intToChar ( single);
        process = (process - single) / 10;
    }

    return numString;
}

作为一行:name += std::to_string(年龄);

您可以使用下面给出的简单技巧将int连接到string，但请注意，这仅适用于integer为个位数时。否则，向该字符串逐位添加整数。

string name = "John";
int age = 5;
char temp = 5 + '0';
name = name + temp;
cout << name << endl;

Output:  John5