Roslyn在NuGet上的Microsoft.CodeAnalysis.CSharp包中有一个方法:

private static string ToLiteral(string valueTextForCompiler)
{
    return Microsoft.CodeAnalysis.CSharp.SymbolDisplay.FormatLiteral(valueTextForCompiler, false);
}

显然，这在最初的问题时并不存在，但它可能会帮助那些从谷歌搜索到这里的人。

我试图将ToVerbatim添加到Hallgrim公认的答案中:

private static string ToLiteral(string input)
{
    using (var writer = new StringWriter())
    {
        using (var provider = CodeDomProvider.CreateProvider("CSharp"))
        {
            provider.GenerateCodeFromExpression(new CodePrimitiveExpression(input), writer, new CodeGeneratorOptions { IndentString = "\t" });
            var literal = writer.ToString();
            literal = literal.Replace(string.Format("\" +{0}\t\"", Environment.NewLine), "");
            return literal;
        }
    }
}

private static string ToVerbatim(string input)
{
    string literal = ToLiteral(input);
    string verbatim = "@" + literal.Replace(@"\r\n", Environment.NewLine);
    return verbatim;
}

如果JSON约定对于你想要转义的未转义字符串足够，并且你已经使用了JSON。NET (Newtonsoft.Json)在你的项目中(它有一个相当大的开销)，你可以像下面这样使用这个包:

using System;
using Newtonsoft.Json;

public class Program
{
    public static void Main()
    {
        Console.WriteLine(ToLiteral(@"abc\n123"));
    }

    private static string ToLiteral(string input)
    {
        return JsonConvert.DeserializeObject<string>("\"" + input + "\"");
    }
}

有趣的问题。

如果你找不到更好的方法，你可以随时替换。 如果你选择它，你可以使用这个c#转义序列列表:

\' - single quote, needed for character literals \" - double quote, needed for string literals \ - backslash \0 - Unicode character 0 \a - Alert (character 7) \b - Backspace (character 8) \f - Form feed (character 12) \n - New line (character 10) \r - Carriage return (character 13) \t - Horizontal tab (character 9) \v - Vertical quote (character 11) \uxxxx - Unicode escape sequence for character with hex value xxxx \xn[n][n][n] - Unicode escape sequence for character with hex value nnnn (variable length version of \uxxxx) \Uxxxxxxxx - Unicode escape sequence for character with hex value xxxxxxxx (for generating surrogates)

这个列表可以在c#常见问题中找到 有哪些字符转义序列可用?

我提交了自己的实现，它处理空值，并且由于使用数组查找表、手动十六进制转换和避免开关语句，因此性能应该更好。

using System;
using System.Text;
using System.Linq;

public static class StringLiteralEncoding {
  private static readonly char[] HEX_DIGIT_LOWER = "0123456789abcdef".ToCharArray();
  private static readonly char[] LITERALENCODE_ESCAPE_CHARS;

  static StringLiteralEncoding() {
    // Per http://msdn.microsoft.com/en-us/library/h21280bw.aspx
    var escapes = new string[] { "\aa", "\bb", "\ff", "\nn", "\rr", "\tt", "\vv", "\"\"", "\\\\", "??", "\00" };
    LITERALENCODE_ESCAPE_CHARS = new char[escapes.Max(e => e[0]) + 1];
    foreach(var escape in escapes)
      LITERALENCODE_ESCAPE_CHARS[escape[0]] = escape[1];
  }

  /// <summary>
  /// Convert the string to the equivalent C# string literal, enclosing the string in double quotes and inserting
  /// escape sequences as necessary.
  /// </summary>
  /// <param name="s">The string to be converted to a C# string literal.</param>
  /// <returns><paramref name="s"/> represented as a C# string literal.</returns>
  public static string Encode(string s) {
    if(null == s) return "null";

    var sb = new StringBuilder(s.Length + 2).Append('"');
    for(var rp = 0; rp < s.Length; rp++) {
      var c = s[rp];
      if(c < LITERALENCODE_ESCAPE_CHARS.Length && '\0' != LITERALENCODE_ESCAPE_CHARS[c])
        sb.Append('\\').Append(LITERALENCODE_ESCAPE_CHARS[c]);
      else if('~' >= c && c >= ' ')
        sb.Append(c);
      else
        sb.Append(@"\x")
          .Append(HEX_DIGIT_LOWER[c >> 12 & 0x0F])
          .Append(HEX_DIGIT_LOWER[c >>  8 & 0x0F])
          .Append(HEX_DIGIT_LOWER[c >>  4 & 0x0F])
          .Append(HEX_DIGIT_LOWER[c       & 0x0F]);
    }

    return sb.Append('"').ToString();
  }
}

Hallgrim的回答很好，但是“+”，换行和缩进的添加破坏了我的功能。一个简单的解决方法是:

private static string ToLiteral(string input)
{
    using (var writer = new StringWriter())
    {
        using (var provider = CodeDomProvider.CreateProvider("CSharp"))
        {
            provider.GenerateCodeFromExpression(new CodePrimitiveExpression(input), writer, new CodeGeneratorOptions {IndentString = "\t"});
            var literal = writer.ToString();
            literal = literal.Replace(string.Format("\" +{0}\t\"", Environment.NewLine), "");
            return literal;
        }
    }
}