Hallgrim的回答很好，但是“+”，换行和缩进的添加破坏了我的功能。一个简单的解决方法是:

private static string ToLiteral(string input)
{
    using (var writer = new StringWriter())
    {
        using (var provider = CodeDomProvider.CreateProvider("CSharp"))
        {
            provider.GenerateCodeFromExpression(new CodePrimitiveExpression(input), writer, new CodeGeneratorOptions {IndentString = "\t"});
            var literal = writer.ToString();
            literal = literal.Replace(string.Format("\" +{0}\t\"", Environment.NewLine), "");
            return literal;
        }
    }
}

Try:

var t = HttpUtility.JavaScriptStringEncode(s);

public static class StringHelpers
{
    private static Dictionary<string, string> escapeMapping = new Dictionary<string, string>()
    {
        {"\"", @"\\\"""},
        {"\\\\", @"\\"},
        {"\a", @"\a"},
        {"\b", @"\b"},
        {"\f", @"\f"},
        {"\n", @"\n"},
        {"\r", @"\r"},
        {"\t", @"\t"},
        {"\v", @"\v"},
        {"\0", @"\0"},
    };

    private static Regex escapeRegex = new Regex(string.Join("|", escapeMapping.Keys.ToArray()));

    public static string Escape(this string s)
    {
        return escapeRegex.Replace(s, EscapeMatchEval);
    }

    private static string EscapeMatchEval(Match m)
    {
        if (escapeMapping.ContainsKey(m.Value))
        {
            return escapeMapping[m.Value];
        }
        return escapeMapping[Regex.Escape(m.Value)];
    }
}

以下是对Smilediver的回答的一点改进。它不会转义所有的no-ASCII字符，但只有这些是真正需要的。

using System;
using System.Globalization;
using System.Text;

public static class CodeHelper
{
    public static string ToLiteral(this string input)
    {
        var literal = new StringBuilder(input.Length + 2);
        literal.Append("\"");
        foreach (var c in input)
        {
            switch (c)
            {
                case '\'': literal.Append(@"\'"); break;
                case '\"': literal.Append("\\\""); break;
                case '\\': literal.Append(@"\\"); break;
                case '\0': literal.Append(@"\0"); break;
                case '\a': literal.Append(@"\a"); break;
                case '\b': literal.Append(@"\b"); break;
                case '\f': literal.Append(@"\f"); break;
                case '\n': literal.Append(@"\n"); break;
                case '\r': literal.Append(@"\r"); break;
                case '\t': literal.Append(@"\t"); break;
                case '\v': literal.Append(@"\v"); break;
                default:
                    if (Char.GetUnicodeCategory(c) != UnicodeCategory.Control)
                    {
                        literal.Append(c);
                    }
                    else
                    {
                        literal.Append(@"\u");
                        literal.Append(((ushort)c).ToString("x4"));
                    }
                    break;
            }
        }
        literal.Append("\"");
        return literal.ToString();
    }
}

如果JSON约定对于你想要转义的未转义字符串足够，并且你已经使用了JSON。NET (Newtonsoft.Json)在你的项目中(它有一个相当大的开销)，你可以像下面这样使用这个包:

using System;
using Newtonsoft.Json;

public class Program
{
    public static void Main()
    {
        Console.WriteLine(ToLiteral(@"abc\n123"));
    }

    private static string ToLiteral(string input)
    {
        return JsonConvert.DeserializeObject<string>("\"" + input + "\"");
    }
}

有趣的问题。

如果你找不到更好的方法，你可以随时替换。 如果你选择它，你可以使用这个c#转义序列列表:

\' - single quote, needed for character literals \" - double quote, needed for string literals \ - backslash \0 - Unicode character 0 \a - Alert (character 7) \b - Backspace (character 8) \f - Form feed (character 12) \n - New line (character 10) \r - Carriage return (character 13) \t - Horizontal tab (character 9) \v - Vertical quote (character 11) \uxxxx - Unicode escape sequence for character with hex value xxxx \xn[n][n][n] - Unicode escape sequence for character with hex value nnnn (variable length version of \uxxxx) \Uxxxxxxxx - Unicode escape sequence for character with hex value xxxxxxxx (for generating surrogates)

这个列表可以在c#常见问题中找到 有哪些字符转义序列可用?