深度复制和浅复制的区别是什么?
当前回答
char * Source = "Hello, world.";
char * ShallowCopy = Source;
char * DeepCopy = new char(strlen(Source)+1);
strcpy(DeepCopy,Source);
“ShallowCopy”指向与“Source”相同的内存位置。 “DeepCopy”指向内存中的不同位置,但内容是相同的。
其他回答
除了上述所有定义之外,还有一个最常用的深度复制,位于类的复制构造函数(或重载赋值操作符)中。
浅复制——>是当你没有提供复制构造函数时。在这里,只复制对象,但不复制类的所有成员。
深度复制——>是当您决定在类中实现复制构造函数或重载赋值,并允许复制类的所有成员时。
MyClass& MyClass(const MyClass& obj) // copy constructor for MyClass
{
// write your code, to copy all the members and return the new object
}
MyClass& operator=(const MyClass& obj) // overloading assignment operator,
{
// write your code, to copy all the members and return the new object
}
浅拷贝:将成员值从一个对象复制到另一个对象。
深度复制:将成员值从一个对象复制到另一个对象。 任何指针对象复制和复制。
例子:
class String
{
int size;
char* data;
};
String s1("Ace"); // s1.size = 3 s1.data=0x0000F000
String s2 = shallowCopy(s1);
// s2.size =3 s2.data = 0X0000F000
String s3 = deepCopy(s1);
// s3.size =3 s3.data = 0x0000F00F
// (With Ace copied to this location.)
char * Source = "Hello, world.";
char * ShallowCopy = Source;
char * DeepCopy = new char(strlen(Source)+1);
strcpy(DeepCopy,Source);
“ShallowCopy”指向与“Source”相同的内存位置。 “DeepCopy”指向内存中的不同位置,但内容是相同的。
假设有两个数组arr1和arr2。
arr1 = arr2; //shallow copy
arr1 = arr2.clone(); //deep copy
The copy constructor is used to initialize the new object with the previously created object of the same class. By default compiler wrote a shallow copy. Shallow copy works fine when dynamic memory allocation is not involved because when dynamic memory allocation is involved then both objects will points towards the same memory location in a heap, Therefore to remove this problem we wrote deep copy so both objects have their own copy of attributes in a memory. In order to read the details with complete examples and explanations you could see the article C++ constructors.