在Python中似乎有很多方法来定义单例对象。对Stack Overflow是否有一致的意见?


当前回答

辛格尔顿同父异母的兄弟

我完全同意staale的观点,我在这里留下了一个创建单胎同父异母兄弟的例子:

class void:pass
a = void();
a.__class__ = Singleton

即使看起来不像单例,A现在也会报告为与单例属于同一个类。因此,使用复杂类的单例最终依赖于我们没有过多地干扰它们。

因此,我们可以使用更简单的东西,如变量或模块,以达到同样的效果。尽管如此,如果我们想要使用类来明确,并且因为在Python中类是一个对象,所以我们已经有了对象(不是实例,但它会像)。

class Singleton:
    def __new__(cls): raise AssertionError # Singletons can't have instances

如果我们尝试创建一个实例,我们会有一个很好的断言错误,我们可以在派生上存储静态成员,并在运行时对它们进行更改(我喜欢Python)。这个对象和其他同父异母的兄弟一样好(如果你愿意,你仍然可以创建它们),但是由于简单,它往往会运行得更快。

其他回答

这是我自己对单例对象的实现。你所要做的就是布置课堂;为了获得单例,你必须使用Instance方法。这里有一个例子:

@Singleton
class Foo:
   def __init__(self):
       print 'Foo created'

f = Foo() # Error, this isn't how you get the instance of a singleton

f = Foo.instance() # Good. Being explicit is in line with the Python Zen
g = Foo.instance() # Returns already created instance

print f is g # True

下面是代码:

class Singleton:
    """
    A non-thread-safe helper class to ease implementing singletons.
    This should be used as a decorator -- not a metaclass -- to the
    class that should be a singleton.

    The decorated class can define one `__init__` function that
    takes only the `self` argument. Also, the decorated class cannot be
    inherited from. Other than that, there are no restrictions that apply
    to the decorated class.

    To get the singleton instance, use the `instance` method. Trying
    to use `__call__` will result in a `TypeError` being raised.

    """

    def __init__(self, decorated):
        self._decorated = decorated

    def instance(self):
        """
        Returns the singleton instance. Upon its first call, it creates a
        new instance of the decorated class and calls its `__init__` method.
        On all subsequent calls, the already created instance is returned.

        """
        try:
            return self._instance
        except AttributeError:
            self._instance = self._decorated()
            return self._instance

    def __call__(self):
        raise TypeError('Singletons must be accessed through `instance()`.')

    def __instancecheck__(self, inst):
        return isinstance(inst, self._decorated)

你可以像这样重写__new__方法:

class Singleton(object):
    _instance = None
    def __new__(cls, *args, **kwargs):
        if not cls._instance:
            cls._instance = super(Singleton, cls).__new__(
                                cls, *args, **kwargs)
        return cls._instance


if __name__ == '__main__':
    s1 = Singleton()
    s2 = Singleton()
    if (id(s1) == id(s2)):
        print "Same"
    else:
        print "Different"

Python文档涵盖了这些内容:

class Singleton(object):
    def __new__(cls, *args, **kwds):
        it = cls.__dict__.get("__it__")
        if it is not None:
            return it
        cls.__it__ = it = object.__new__(cls)
        it.init(*args, **kwds)
        return it
    def init(self, *args, **kwds):
        pass

我可能会重写成这样:

class Singleton(object):
    """Use to create a singleton"""
    def __new__(cls, *args, **kwds):
        """
        >>> s = Singleton()
        >>> p = Singleton()
        >>> id(s) == id(p)
        True
        """
        it_id = "__it__"
        # getattr will dip into base classes, so __dict__ must be used
        it = cls.__dict__.get(it_id, None)
        if it is not None:
            return it
        it = object.__new__(cls)
        setattr(cls, it_id, it)
        it.init(*args, **kwds)
        return it

    def init(self, *args, **kwds):
        pass


class A(Singleton):
    pass


class B(Singleton):
    pass


class C(A):
    pass


assert A() is A()
assert B() is B()
assert C() is C()
assert A() is not B()
assert C() is not B()
assert C() is not A()

它应该是相对干净的扩展:

class Bus(Singleton):
    def init(self, label=None, *args, **kwds):
        self.label = label
        self.channels = [Channel("system"), Channel("app")]
        ...

如果你想继续装饰(注释)类,创建一个单例装饰器(又名注释)是一种优雅的方式。然后将@singleton放在类定义之前。

def singleton(cls):
    instances = {}
    def getinstance():
        if cls not in instances:
            instances[cls] = cls()
        return instances[cls]
    return getinstance

@singleton
class MyClass:
    ...

我真的不认为有这个需要,因为一个带有函数(而不是类)的模块可以很好地作为一个单例。它的所有变量都将绑定到模块,无论如何都不能重复实例化。

如果你确实希望使用一个类,在Python中没有办法创建私有类或私有构造函数,所以你不能防止多个实例化,只能通过使用API中的约定。我仍然会将方法放在模块中,并将模块视为单例模块。