问题

我开始看看Swift编程语言,不知为何我不能正确地从特定的UIStoryboard输入一个UIViewController的初始化。

在Objective-C中,我简单地写:

UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"StoryboardName" bundle:nil];
UIViewController *viewController = [storyboard instantiateViewControllerWithIdentifier:@"ViewControllerID"];
[self presentViewController:viewController animated:YES completion:nil];

有人能帮助我如何在斯威夫特上实现这一点吗?


当前回答

斯威夫特4:

    let storyboard = UIStoryboard(name: "Main", bundle: nil)
    let yourVC: YourVC = storyboard.instantiateViewController(withIdentifier: "YourVC") as! YourVC

其他回答

斯威夫特3

let settingStoryboard : UIStoryboard = UIStoryboard(name: "SettingViewController", bundle: nil)
let settingVC = settingStoryboard.instantiateViewController(withIdentifier: "SettingViewController") as! SettingViewController
self.present(settingVC, animated: true, completion: {

})

我想建议一种更简洁的方法。当我们有多个故事板时,这将很有用

1.用你所有的故事板创建一个结构

struct Storyboard {
      static let main = "Main"
      static let login = "login"
      static let profile = "profile" 
      static let home = "home"
    }

2. 创建一个UIStoryboard扩展,如下所示

extension UIStoryboard {
  @nonobjc class var main: UIStoryboard {
    return UIStoryboard(name: Storyboard.main, bundle: nil)
  }
  @nonobjc class var journey: UIStoryboard {
    return UIStoryboard(name: Storyboard.login, bundle: nil)
  }
  @nonobjc class var quiz: UIStoryboard {
    return UIStoryboard(name: Storyboard.profile, bundle: nil)
  }
  @nonobjc class var home: UIStoryboard {
    return UIStoryboard(name: Storyboard.home, bundle: nil)
  }
}

将故事板标识符作为类名,并使用下面的代码进行实例化

let loginVc = UIStoryboard.login.instantiateViewController(withIdentifier: "\(LoginViewController.self)") as! LoginViewController

我创建了一个库,可以用更好的语法更容易地处理这个问题:

https://github.com/Jasperav/Storyboardable

只需改变Storyboard.swift,让ViewControllers符合Storyboardable。

如果你想以模态方式呈现它,你应该有如下所示的东西:

let vc = self.storyboard!.instantiateViewControllerWithIdentifier("YourViewControllerID")
self.showDetailViewController(vc as! YourViewControllerClassName, sender: self)

如果你有一个Viewcontroller没有使用任何storyboard/Xib,你可以像下面这样调用这个特定的VC:

 let vcInstance : UIViewController   = yourViewController()
 self.present(vcInstance, animated: true, completion: nil)