选项1

下面的代码允许用户从任何文件资源管理器应用程序中选择图像

Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent, "Select Picture"), PICK_IMAGE_CODE);

但在某些设备中，上述解决方案不会获取带有EXIF信息(如方向)的图像。因此，在这些设备中，改变图像方向等EXIF处理无法按预期进行。

选项2

下面的代码允许用户从任何图库应用程序中选择图像

Intent intent = new Intent(Intent.ACTION_PICK, MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
intent.setType("image/*");
startActivityForResult ( intent, PICK_IMAGE_CODE );

但在某些设备中，在设置意图类型时，上述解决方案将清除可能阻碍图库打开过程的意图数据(MediaStore.Images.Media.EXTERNAL_CONTENT_URI)。

选项3

最后，我建议使用下面的代码，它允许用户从任何图库应用程序中选择图像，而不会引起任何问题，也不会显示任何警告

Intent intent = new Intent ();
intent.setAction ( Intent.ACTION_PICK );
intent.setDataAndType ( MediaStore.Images.Media.EXTERNAL_CONTENT_URI, "image/*" );
startActivityForResult ( intent, PICK_IMAGE_CODE );

如果你只是寻找图像和多重选择。

看一次https://stackoverflow.com/a/15029515/1136023

这对将来很有帮助。我个人觉得使用MultipleImagePick很棒。

你可以做的比下面的回答更简单:

Uri Selected_Image_Uri = data.getData();
ImageView imageView = (ImageView) findViewById(R.id.loadedimg);
imageView.setImageURI(Selected_Image_Uri);

您可以使用此方法从图库中选择图像。只显示图像。

public void pickImage() {
    Intent intent = new Intent(Intent.ACTION_PICK,
            MediaStore.Images.Media.INTERNAL_CONTENT_URI);
    intent.setType("image/*");
    intent.putExtra("crop", "true");
    intent.putExtra("scale", true);
    intent.putExtra("outputX", 256);
    intent.putExtra("outputY", 256);
    intent.putExtra("aspectX", 1);
    intent.putExtra("aspectY", 1);
    intent.putExtra("return-data", true);
    startActivityForResult(intent, 1);
}

并重写onActivityResult as

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        if (resultCode != RESULT_OK) {
            return;
        }
        if (requestCode == 1) {
            final Bundle extras = data.getExtras();
            if (extras != null) {
                //Get image
                Bitmap newProfilePic = extras.getParcelable("data");
            }
        }
    }

绝对的。试试这个:

Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent, "Select Picture"), PICK_IMAGE);

不要忘记创建常量PICK_IMAGE，这样当用户从图库中返回时，你就可以识别出来:

public static final int PICK_IMAGE = 1;

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data)
{
    if (requestCode == PICK_IMAGE) {
        //TODO: action
    }
}

这就是我对图片库的称呼。把它放进去，看看是否对你有用。

编辑:

这会打开Documents应用程序。允许用户使用他们可能已经安装的任何图库应用程序:

    Intent getIntent = new Intent(Intent.ACTION_GET_CONTENT);
    getIntent.setType("image/*");

    Intent pickIntent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
    pickIntent.setType("image/*");

    Intent chooserIntent = Intent.createChooser(getIntent, "Select Image");
    chooserIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS, new Intent[] {pickIntent});

    startActivityForResult(chooserIntent, PICK_IMAGE);

我也有同样的问题，我用这个密码

addIntent

 Intent intent = new Intent();
        intent.setType("image/*");
        intent.setAction(Intent.ACTION_GET_CONTENT);
        startActivityForResult(Intent.createChooser(intent, "Tack Image"), PICK_PHOTO);

添加onActivityResult

 @Override
  public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == PICK_PHOTO && resultCode == Activity.RESULT_OK) {
      if (data == null) {
      //error
        return;
      }
      try {
        Uri uri = data.getData();
        File file = FileUtil.from(currentActivity, uri);
      } catch (IOException e) {
        e.printStackTrace();
      }
    }
  }

FileUtil类

import android.content.Context;
import android.database.Cursor;
import android.net.Uri;
import android.provider.OpenableColumns;
import android.util.Log;

import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;

public class FileUtil {
  private static final int EOF = -1;
  private static final int DEFAULT_BUFFER_SIZE = 1024 * 4;

  private FileUtil() {

  }

  public static File from(Context context, Uri uri) throws IOException {
    InputStream inputStream = context.getContentResolver().openInputStream(uri);
    String fileName = getFileName(context, uri);
    String[] splitName = splitFileName(fileName);
    File tempFile = File.createTempFile(splitName[0], splitName[1]);
    tempFile = rename(tempFile, fileName);
    tempFile.deleteOnExit();
    FileOutputStream out = null;
    try {
      out = new FileOutputStream(tempFile);
    } catch (FileNotFoundException e) {
      e.printStackTrace();
    }
    if (inputStream != null) {
      copy(inputStream, out);
      inputStream.close();
    }

    if (out != null) {
      out.close();
    }
    return tempFile;
  }

  private static String[] splitFileName(String fileName) {
    String name = fileName;
    String extension = "";
    int i = fileName.lastIndexOf(".");
    if (i != -1) {
      name = fileName.substring(0, i);
      extension = fileName.substring(i);
    }

    return new String[]{name, extension};
  }

  private static String getFileName(Context context, Uri uri) {
    String result = null;
    if (uri.getScheme().equals("content")) {
      Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
      try {
        if (cursor != null && cursor.moveToFirst()) {
          result = cursor.getString(cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME));
        }
      } catch (Exception e) {
        e.printStackTrace();
      } finally {
        if (cursor != null) {
          cursor.close();
        }
      }
    }
    if (result == null) {
      result = uri.getPath();
      int cut = result.lastIndexOf(File.separator);
      if (cut != -1) {
        result = result.substring(cut + 1);
      }
    }
    return result;
  }

  private static File rename(File file, String newName) {
    File newFile = new File(file.getParent(), newName);
    if (!newFile.equals(file)) {
      if (newFile.exists() && newFile.delete()) {
        Log.d("FileUtil", "Delete old " + newName + " file");
      }
      if (file.renameTo(newFile)) {
        Log.d("FileUtil", "Rename file to " + newName);
      }
    }
    return newFile;
  }

  private static long copy(InputStream input, OutputStream output) throws IOException {
    long count = 0;
    int n;
    byte[] buffer = new byte[DEFAULT_BUFFER_SIZE];
    while (EOF != (n = input.read(buffer))) {
      output.write(buffer, 0, n);
      count += n;
    }
    return count;
  }
}

并且必须将provider_paths.xml添加到像image这样的XML文件夹中

provider_paths.xml

<?xml version="1.0" encoding="utf-8"?>
<paths>
    <external-path name="external_files" path="."/>
</paths>

最后在AndroidManifest.xml中添加如下内容

<application
...>

...
      <provider
          android:name="androidx.core.content.FileProvider"
          android:authorities="${applicationId}.provider"
          android:exported="false"
          android:grantUriPermissions="true">
          <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/provider_paths" />
        </provider>
...
</application>

我希望我能帮上忙