我想从画廊创建一个图片选择器。我使用代码
intent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
startActivityForResult(intent, TFRequestCodes.GALLERY);
我的问题是在这个活动和视频文件显示。是否有一种方法可以过滤显示的文件,以便在此活动中不显示视频文件?
我想从画廊创建一个图片选择器。我使用代码
intent = new Intent(Intent.ACTION_PICK, android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
startActivityForResult(intent, TFRequestCodes.GALLERY);
我的问题是在这个活动和视频文件显示。是否有一种方法可以过滤显示的文件,以便在此活动中不显示视频文件?
当前回答
下面是kotlin中util方法的工作代码:
fun launchGalleryWithFragment() {
val intent = Intent(Intent.ACTION_PICK, MediaStore.Images.Media.EXTERNAL_CONTENT_URI)
intent.type = "image/*"
startActivityForResult(Intent.createChooser(intent, "Select Picture"), 1001)
}
现在重写onActivityResult方法:
override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
super.onActivityResult(requestCode, resultCode, data)
var path: Uri? = null
if (requestCode == PICK_IMAGE_REQUEST && resultCode == Activity.RESULT_OK) {
if(dataIntent == null || dataIntent.data == null){
return null
}
path = dataIntent.data
}
}
其他回答
public void FromCamera() {
Log.i("camera", "startCameraActivity()");
File file = new File(path);
Uri outputFileUri = Uri.fromFile(file);
Intent intent = new Intent(
android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
intent.putExtra(MediaStore.EXTRA_OUTPUT, outputFileUri);
startActivityForResult(intent, 1);
}
public void FromCard() {
Intent i = new Intent(Intent.ACTION_PICK,
android.provider.MediaStore.Images.Media.EXTERNAL_CONTENT_URI);
startActivityForResult(i, 2);
}
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == 2 && resultCode == RESULT_OK
&& null != data) {
Uri selectedImage = data.getData();
String[] filePathColumn = { MediaStore.Images.Media.DATA };
Cursor cursor = getContentResolver().query(selectedImage,
filePathColumn, null, null, null);
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
String picturePath = cursor.getString(columnIndex);
cursor.close();
bitmap = BitmapFactory.decodeFile(picturePath);
image.setImageBitmap(bitmap);
if (bitmap != null) {
ImageView rotate = (ImageView) findViewById(R.id.rotate);
}
} else {
Log.i("SonaSys", "resultCode: " + resultCode);
switch (resultCode) {
case 0:
Log.i("SonaSys", "User cancelled");
break;
case -1:
onPhotoTaken();
break;
}
}
}
protected void onPhotoTaken() {
// Log message
Log.i("SonaSys", "onPhotoTaken");
taken = true;
imgCapFlag = true;
BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 4;
bitmap = BitmapFactory.decodeFile(path, options);
image.setImageBitmap(bitmap);
}
对于只从本地选择添加这个:
i.putExtra(Intent.EXTRA_LOCAL_ONLY,true)
这个工作得很好:
val i = Intent(Intent.ACTION_GET_CONTENT,MediaStore.Images.Media.EXTERNAL_CONTENT_URI)
i.type = "image/*"
i.putExtra(Intent.EXTRA_LOCAL_ONLY,true)
startActivityForResult(Intent.createChooser(i,"Select Photo"),pickImageRequestCode)
您可以使用此方法从图库中选择图像。只显示图像。
public void pickImage() {
Intent intent = new Intent(Intent.ACTION_PICK,
MediaStore.Images.Media.INTERNAL_CONTENT_URI);
intent.setType("image/*");
intent.putExtra("crop", "true");
intent.putExtra("scale", true);
intent.putExtra("outputX", 256);
intent.putExtra("outputY", 256);
intent.putExtra("aspectX", 1);
intent.putExtra("aspectY", 1);
intent.putExtra("return-data", true);
startActivityForResult(intent, 1);
}
并重写onActivityResult as
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode != RESULT_OK) {
return;
}
if (requestCode == 1) {
final Bundle extras = data.getExtras();
if (extras != null) {
//Get image
Bitmap newProfilePic = extras.getParcelable("data");
}
}
}
我也有同样的问题,我用这个密码
addIntent
Intent intent = new Intent();
intent.setType("image/*");
intent.setAction(Intent.ACTION_GET_CONTENT);
startActivityForResult(Intent.createChooser(intent, "Tack Image"), PICK_PHOTO);
添加onActivityResult
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == PICK_PHOTO && resultCode == Activity.RESULT_OK) {
if (data == null) {
//error
return;
}
try {
Uri uri = data.getData();
File file = FileUtil.from(currentActivity, uri);
} catch (IOException e) {
e.printStackTrace();
}
}
}
FileUtil类
import android.content.Context;
import android.database.Cursor;
import android.net.Uri;
import android.provider.OpenableColumns;
import android.util.Log;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
public class FileUtil {
private static final int EOF = -1;
private static final int DEFAULT_BUFFER_SIZE = 1024 * 4;
private FileUtil() {
}
public static File from(Context context, Uri uri) throws IOException {
InputStream inputStream = context.getContentResolver().openInputStream(uri);
String fileName = getFileName(context, uri);
String[] splitName = splitFileName(fileName);
File tempFile = File.createTempFile(splitName[0], splitName[1]);
tempFile = rename(tempFile, fileName);
tempFile.deleteOnExit();
FileOutputStream out = null;
try {
out = new FileOutputStream(tempFile);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
if (inputStream != null) {
copy(inputStream, out);
inputStream.close();
}
if (out != null) {
out.close();
}
return tempFile;
}
private static String[] splitFileName(String fileName) {
String name = fileName;
String extension = "";
int i = fileName.lastIndexOf(".");
if (i != -1) {
name = fileName.substring(0, i);
extension = fileName.substring(i);
}
return new String[]{name, extension};
}
private static String getFileName(Context context, Uri uri) {
String result = null;
if (uri.getScheme().equals("content")) {
Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
try {
if (cursor != null && cursor.moveToFirst()) {
result = cursor.getString(cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME));
}
} catch (Exception e) {
e.printStackTrace();
} finally {
if (cursor != null) {
cursor.close();
}
}
}
if (result == null) {
result = uri.getPath();
int cut = result.lastIndexOf(File.separator);
if (cut != -1) {
result = result.substring(cut + 1);
}
}
return result;
}
private static File rename(File file, String newName) {
File newFile = new File(file.getParent(), newName);
if (!newFile.equals(file)) {
if (newFile.exists() && newFile.delete()) {
Log.d("FileUtil", "Delete old " + newName + " file");
}
if (file.renameTo(newFile)) {
Log.d("FileUtil", "Rename file to " + newName);
}
}
return newFile;
}
private static long copy(InputStream input, OutputStream output) throws IOException {
long count = 0;
int n;
byte[] buffer = new byte[DEFAULT_BUFFER_SIZE];
while (EOF != (n = input.read(buffer))) {
output.write(buffer, 0, n);
count += n;
}
return count;
}
}
并且必须将provider_paths.xml添加到像image这样的XML文件夹中
provider_paths.xml
<?xml version="1.0" encoding="utf-8"?>
<paths>
<external-path name="external_files" path="."/>
</paths>
最后在AndroidManifest.xml中添加如下内容
<application
...>
...
<provider
android:name="androidx.core.content.FileProvider"
android:authorities="${applicationId}.provider"
android:exported="false"
android:grantUriPermissions="true">
<meta-data
android:name="android.support.FILE_PROVIDER_PATHS"
android:resource="@xml/provider_paths" />
</provider>
...
</application>
我希望我能帮上忙
有时,您无法从所选择的图片中获取文件。 这是因为选择一个来自谷歌+,Drive, Dropbox或任何其他提供商。
最好的解决方案是让系统通过Intent来选择内容。ACTION_GET_CONTENT并使用内容提供程序获取结果。
您可以按照下面的代码或查看我更新的要点。
public void pickImage() {
Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
intent.setType("image/*");
startActivityForResult(intent, PICK_PHOTO_FOR_AVATAR);
}
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == PICK_PHOTO_FOR_AVATAR && resultCode == Activity.RESULT_OK) {
if (data == null) {
//Display an error
return;
}
InputStream inputStream = context.getContentResolver().openInputStream(data.getData());
//Now you can do whatever you want with your inpustream, save it as file, upload to a server, decode a bitmap...
}
}