如何在Python中将彩色文本输出到终端?
当前回答
我的两分钱(PyColorTerm):
安装:
sudo apt-get install python-pip
pip install pycolorterm
Python脚本:
from pycolorterm import pycolorterm
with pycolorterm.pretty_output(pycolorterm.FG_GREEN) as out:
out.write('Works OK!')
“工作正常!”显示为绿色。
其他回答
根据乔尔德的回答,这简直太简单了:
class PrintInColor:
RED = '\033[91m'
GREEN = '\033[92m'
YELLOW = '\033[93m'
LIGHT_PURPLE = '\033[94m'
PURPLE = '\033[95m'
END = '\033[0m'
@classmethod
def red(cls, s, **kwargs):
print(cls.RED + s + cls.END, **kwargs)
@classmethod
def green(cls, s, **kwargs):
print(cls.GREEN + s + cls.END, **kwargs)
@classmethod
def yellow(cls, s, **kwargs):
print(cls.YELLOW + s + cls.END, **kwargs)
@classmethod
def lightPurple(cls, s, **kwargs):
print(cls.LIGHT_PURPLE + s + cls.END, **kwargs)
@classmethod
def purple(cls, s, **kwargs):
print(cls.PURPLE + s + cls.END, **kwargs)
那么就
PrintInColor.red('hello', end=' ')
PrintInColor.green('world')
您可以使用curses库的Python实现:curses-字符单元显示的终端处理
此外,运行此程序,您将找到您的盒子:
for i in range(255):
print i, chr(i)
# Pure Python 3.x demo, 256 colors
# Works with bash under Linux and MacOS
fg = lambda text, color: "\33[38;5;" + str(color) + "m" + text + "\33[0m"
bg = lambda text, color: "\33[48;5;" + str(color) + "m" + text + "\33[0m"
def print_six(row, format, end="\n"):
for col in range(6):
color = row*6 + col - 2
if color>=0:
text = "{:3d}".format(color)
print (format(text,color), end=" ")
else:
print(end=" ") # four spaces
print(end=end)
for row in range(0, 43):
print_six(row, fg, " ")
print_six(row, bg)
# Simple usage: print(fg("text", 160))
在线试用
class ColorText:
"""
Use ANSI escape sequences to print colors +/- bold/underline to bash terminal.
Examples
--------
>>> ColorText('HelloWorld').bold()
>>> ColorText('HelloWorld').blue()
>>> ColorText('HelloWorld').bold().custom("#bebebe")
>>> ColorText('HelloWorld').underline().custom('dodgerblue')
>>> ColorText.demo()
Notes
-----
- execute ColorText.demo() for a printout of colors.
"""
@classmethod
def demo(cls):
"""Prints examples of all colors in normal, bold, underline, bold+underline."""
for color in dir(ColorText):
if all([color.startswith("_") is False,
color not in ["bold", "underline", "demo", "custom"],
callable(getattr(ColorText, color))]):
print(getattr(ColorText(color), color)(),
"\t",
getattr(ColorText(f"bold {color}").bold(), color)(),
"\t",
getattr(ColorText(f"underline {color}").underline(), color)(),
"\t",
getattr(ColorText(f"bold underline {color}").underline().bold(), color)())
print(ColorText("Input can also be color hex or R,G,B with ColorText.custom()").bold())
pass
def __init__(self, text: str = ""):
self.text = text
self.ending = "\033[0m"
self.colors = []
pass
def __repr__(self):
return self.text
def __str__(self):
return self.text
def bold(self):
self.text = "\033[1m" + self.text + self.ending
return self
def underline(self):
self.text = "\033[4m" + self.text + self.ending
return self
def green(self):
self.text = "\033[92m" + self.text + self.ending
self.colors.append("green")
return self
def purple(self):
self.text = "\033[95m" + self.text + self.ending
self.colors.append("purple")
return self
def blue(self):
self.text = "\033[94m" + self.text + self.ending
self.colors.append("blue")
return self
def ltblue(self):
self.text = "\033[34m" + self.text + self.ending
self.colors.append("lightblue")
return self
def pink(self):
self.text = "\033[35m" + self.text + self.ending
self.colors.append("pink")
return self
def gray(self):
self.text = "\033[30m" + self.text + self.ending
self.colors.append("gray")
return self
def ltgray(self):
self.text = "\033[37m" + self.text + self.ending
self.colors.append("ltgray")
return self
def warn(self):
self.text = "\033[93m" + self.text + self.ending
self.colors.append("yellow")
return self
def fail(self):
self.text = "\033[91m" + self.text + self.ending
self.colors.append("red")
return self
def ltred(self):
self.text = "\033[31m" + self.text + self.ending
self.colors.append("lightred")
return self
def cyan(self):
self.text = "\033[36m" + self.text + self.ending
self.colors.append("cyan")
return self
def custom(self, *color_hex):
"""Print in custom color, `color_hex` - either actual hex, or tuple(r,g,b)"""
if color_hex != (None, ): # allows printing white on black background, black otherwise
if len(color_hex) == 1:
c = rgb2hex(colorConverter.to_rgb(color_hex[0]))
rgb = ImageColor.getcolor(c, "RGB")
else:
assert (
len(color_hex) == 3
), "If not a color hex, ColorText.custom should have R,G,B as input"
rgb = color_hex
self.text = "\033[{};2;{};{};{}m".format(38, *rgb) + self.text + self.ending
self.colors.append(rgb)
return self
pass
耶!另一个版本
虽然我觉得这个答案很有用,但我做了一些修改。此GitHub Gist是结果
用法
print colors.draw("i'm yellow", bold=True, fg_yellow=True)
此外,还可以包装常用用法:
print colors.error('sorry, ')
https://gist.github.com/Jossef/0ee20314577925b4027f
推荐文章
- 证书验证失败:无法获得本地颁发者证书
- 当使用pip3安装包时,“Python中的ssl模块不可用”
- 无法切换Python与pyenv
- Python if not == vs if !=
- 如何从终端/命令行调用VS代码编辑器
- 如何从scikit-learn决策树中提取决策规则?
- 为什么在Mac OS X v10.9 (Mavericks)的终端中apt-get功能不起作用?
- 将旋转的xtick标签与各自的xtick对齐
- 为什么元组可以包含可变项?
- 如何合并字典的字典?
- 如何创建类属性?
- 不区分大小写的“in”
- 在Python中获取迭代器中的元素个数
- 解析日期字符串并更改格式
- 使用try和。Python中的if