如何在Python中将彩色文本输出到终端?
当前回答
我的两分钱(PyColorTerm):
安装:
sudo apt-get install python-pip
pip install pycolorterm
Python脚本:
from pycolorterm import pycolorterm
with pycolorterm.pretty_output(pycolorterm.FG_GREEN) as out:
out.write('Works OK!')
“工作正常!”显示为绿色。
其他回答
打印一个开始颜色/样式的字符串,然后是字符串,然后以'\x1b[0m'结束颜色/样式更改:
print('\x1b[6;30;42m' + 'Success!' + '\x1b[0m')
使用以下代码获取shell文本的格式选项表:
def print_format_table():
"""
prints table of formatted text format options
"""
for style in range(8):
for fg in range(30,38):
s1 = ''
for bg in range(40,48):
format = ';'.join([str(style), str(fg), str(bg)])
s1 += '\x1b[%sm %s \x1b[0m' % (format, format)
print(s1)
print('\n')
print_format_table()
亮-暗示例(完整)
暗-亮示例(部分)
参考:https://en.wikipedia.org/wiki/ANSI_escape_code#Colors
耶!另一个版本
虽然我觉得这个答案很有用,但我做了一些修改。此GitHub Gist是结果
用法
print colors.draw("i'm yellow", bold=True, fg_yellow=True)
此外,还可以包装常用用法:
print colors.error('sorry, ')
https://gist.github.com/Jossef/0ee20314577925b4027f
定义开始颜色的字符串和结束颜色的字符串。然后打印文本,开始字符串在前面,结束字符串在结尾。
CRED = '\033[91m'
CEND = '\033[0m'
print(CRED + "Error, does not compute!" + CEND)
这将在Bash和urxvt中使用Zenburn风格的配色方案生成以下内容:
通过实验,我们可以获得更多的颜色:
注意:\33[5m和\33[6m闪烁。
这样我们可以创建一个完整的颜色集合:
CEND = '\33[0m'
CBOLD = '\33[1m'
CITALIC = '\33[3m'
CURL = '\33[4m'
CBLINK = '\33[5m'
CBLINK2 = '\33[6m'
CSELECTED = '\33[7m'
CBLACK = '\33[30m'
CRED = '\33[31m'
CGREEN = '\33[32m'
CYELLOW = '\33[33m'
CBLUE = '\33[34m'
CVIOLET = '\33[35m'
CBEIGE = '\33[36m'
CWHITE = '\33[37m'
CBLACKBG = '\33[40m'
CREDBG = '\33[41m'
CGREENBG = '\33[42m'
CYELLOWBG = '\33[43m'
CBLUEBG = '\33[44m'
CVIOLETBG = '\33[45m'
CBEIGEBG = '\33[46m'
CWHITEBG = '\33[47m'
CGREY = '\33[90m'
CRED2 = '\33[91m'
CGREEN2 = '\33[92m'
CYELLOW2 = '\33[93m'
CBLUE2 = '\33[94m'
CVIOLET2 = '\33[95m'
CBEIGE2 = '\33[96m'
CWHITE2 = '\33[97m'
CGREYBG = '\33[100m'
CREDBG2 = '\33[101m'
CGREENBG2 = '\33[102m'
CYELLOWBG2 = '\33[103m'
CBLUEBG2 = '\33[104m'
CVIOLETBG2 = '\33[105m'
CBEIGEBG2 = '\33[106m'
CWHITEBG2 = '\33[107m'
以下是生成测试的代码:
x = 0
for i in range(24):
colors = ""
for j in range(5):
code = str(x+j)
colors = colors + "\33[" + code + "m\\33[" + code + "m\033[0m "
print(colors)
x = x + 5
根据乔尔德的回答,这简直太简单了:
class PrintInColor:
RED = '\033[91m'
GREEN = '\033[92m'
YELLOW = '\033[93m'
LIGHT_PURPLE = '\033[94m'
PURPLE = '\033[95m'
END = '\033[0m'
@classmethod
def red(cls, s, **kwargs):
print(cls.RED + s + cls.END, **kwargs)
@classmethod
def green(cls, s, **kwargs):
print(cls.GREEN + s + cls.END, **kwargs)
@classmethod
def yellow(cls, s, **kwargs):
print(cls.YELLOW + s + cls.END, **kwargs)
@classmethod
def lightPurple(cls, s, **kwargs):
print(cls.LIGHT_PURPLE + s + cls.END, **kwargs)
@classmethod
def purple(cls, s, **kwargs):
print(cls.PURPLE + s + cls.END, **kwargs)
那么就
PrintInColor.red('hello', end=' ')
PrintInColor.green('world')
这里有一个简单的函数,我使用它来打印彩色文本消息,而不必记住ANSI代码,而是使用标准RGB元组来定义前景和背景颜色。
def print_in_color(txt_msg, fore_tuple, back_tuple, ):
# Prints the text_msg in the foreground color specified by fore_tuple with the background specified by back_tuple
# text_msg is the text, fore_tuple is foreground color tuple (r,g,b), back_tuple is background tuple (r,g,b)
rf,bf,gf = fore_tuple
rb,gb,bb = back_tuple
msg = '{0}' + txt_msg
mat = '\33[38;2;' + str(rf) + ';' + str(gf) + ';' + str(bf) + ';48;2;' + str(rb) + ';' +str(gb) + ';' + str(bb) + 'm'
print(msg .format(mat))
print('\33[0m') # Returns default print color to back to black
# Example of use using a message with variables
fore_color = 'cyan'
back_color = 'dark green'
msg = 'foreground color is {0} and the background color is {1}'.format(fore_color, back_color)
print_in_color(msg, (0,255,255), (0,127,127))
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