JSON是否有等价的XSLT ?它允许我对JSON进行转换，就像XSLT对XML所做的那样。
当前回答
最近，我围绕着这个写了自己的小库，尽量保持接近
5.1处理模型(XSLT REC) https://www.w3.org/TR/xslt#section-Processing-Model
在几行JavaScript代码中。
这里有一些不完全琐碎的使用示例……
1. JSON-to-some-markup:
小提琴:https://jsfiddle.net/YSharpLanguage/kj9pk8oz/10
(灵感来自D.1文档示例(XSLT REC) https://www.w3.org/TR/xslt#section-Document-Example)
的地方:
var D1document = {
type: "document", title: [ "Document Title" ],
"": [
{ type: "chapter", title: [ "Chapter Title" ],
"": [
{ type: "section", title: [ "Section Title" ],
"": [
{ type: "para", "": [ "This is a test." ] },
{ type: "note", "": [ "This is a note." ] }
] },
{ type: "section", title: [ "Another Section Title" ],
"": [
{ type: "para", "": [ "This is ", { emph: "another" }, " test." ] },
{ type: "note", "": [ "This is another note." ] }
] }
] }
] };
var D1toHTML = { $: [
[ [ function(node) { return node.type === "document"; } ],
function(root) {
return "<html>\r\n\
<head>\r\n\
<title>\r\n\
{title}\r\n".of(root) + "\
</title>\r\n\
</head>\r\n\
<body>\r\n\
{*}".of(root[""].through(this)) + "\
</body>\r\n\
</html>";
}
],
[ [ function(node) { return node.type === "chapter"; } ],
function(chapter) {
return " <h2>{title}</h2>\r\n".of(chapter) + "{*}".of(chapter[""].through(this));
}
],
[ [ function(node) { return node.type === "section"; } ],
function(section) {
return " <h3>{title}</h3>\r\n".of(section) + "{*}".of(section[""].through(this));
}
],
[ [ function(node) { return node.type === "para"; } ],
function(para) {
return " <p>{*}</p>\r\n".of(para[""].through(this));
}
],
[ [ function(node) { return node.type === "note"; } ],
function(note) {
return ' <p class="note"><b>NOTE: </b>{*}</p>\r\n'.of(note[""].through(this));
}
],
[ [ function(node) { return node.emph; } ],
function(emph) {
return "<em>{emph}</em>".of(emph);
}
]
] };
console.log(D1document.through(D1toHTML));
．.． 给:
<html>
<head>
<title>
Document Title
</title>
</head>
<body>
<h2>Chapter Title</h2>
<h3>Section Title</h3>
<p>This is a test.</p>
<p class="note"><b>NOTE: </b>This is a note.</p>
<h3>Another Section Title</h3>
<p>This is <em>another</em> test.</p>
<p class="note"><b>NOTE: </b>This is another note.</p>
</body>
</html>
and
2. JSON-to-JSON:
小提琴:https://jsfiddle.net/YSharpLanguage/ppfmmu15/10
的地方:
// (A "Company" is just an object with a "Team")
function Company(obj) {
return obj.team && Team(obj.team);
}
// (A "Team" is just a non-empty array that contains at least one "Member")
function Team(obj) {
return ({ }.toString.call(obj) === "[object Array]") &&
obj.length &&
obj.find(function(item) { return Member(item); });
}
// (A "Member" must have first and last names, and a gender)
function Member(obj) {
return obj.first && obj.last && obj.sex;
}
function Dude(obj) {
return Member(obj) && (obj.sex === "Male");
}
function Girl(obj) {
return Member(obj) && (obj.sex === "Female");
}
var data = { team: [
{ first: "John", last: "Smith", sex: "Male" },
{ first: "Vaio", last: "Sony" },
{ first: "Anna", last: "Smith", sex: "Female" },
{ first: "Peter", last: "Olsen", sex: "Male" }
] };
var TO_SOMETHING_ELSE = { $: [
[ [ Company ],
function(company) {
return { some_virtual_dom: {
the_dudes: { ul: company.team.select(Dude).through(this) },
the_grrls: { ul: company.team.select(Girl).through(this) }
} }
} ],
[ [ Member ],
function(member) {
return { li: "{first} {last} ({sex})".of(member) };
} ]
] };
console.log(JSON.stringify(data.through(TO_SOMETHING_ELSE), null, 4));
．.． 给:
{
"some_virtual_dom": {
"the_dudes": {
"ul": [
{
"li": "John Smith (Male)"
},
{
"li": "Peter Olsen (Male)"
}
]
},
"the_grrls": {
"ul": [
{
"li": "Anna Smith (Female)"
}
]
}
}
}
3.XSLT与JavaScript:
JavaScript等价于…
XSLT 3.0 REC 14.4示例:基于公共值对节点进行分组
(http://jsfiddle.net/YSharpLanguage/8bqcd0ey/1)
参看https://www.w3.org/TR/xslt-30/ grouping-examples
在那里……
var cities = [
{ name: "Milano", country: "Italia", pop: 5 },
{ name: "Paris", country: "France", pop: 7 },
{ name: "München", country: "Deutschland", pop: 4 },
{ name: "Lyon", country: "France", pop: 2 },
{ name: "Venezia", country: "Italia", pop: 1 }
];
/*
Cf.
XSLT 3.0 REC Section 14.4
Example: Grouping Nodes based on Common Values
https://www.w3.org/TR/xslt-30/#grouping-examples
*/
var output = "<table>\r\n\
<tr>\r\n\
<th>Position</th>\r\n\
<th>Country</th>\r\n\
<th>City List</th>\r\n\
<th>Population</th>\r\n\
</tr>{*}\r\n\
</table>".of
(
cities.select().groupBy("country")(function(byCountry, index) {
var country = byCountry[0],
cities = byCountry[1].select().orderBy("name");
return "\r\n\
<tr>\r\n\
<td>{position}</td>\r\n\
<td>{country}</td>\r\n\
<td>{cities}</td>\r\n\
<td>{population}</td>\r\n\
</tr>".
of({ position: index + 1, country: country,
cities: cities.map(function(city) { return city.name; }).join(", "),
population: cities.reduce(function(sum, city) { return sum += city.pop; }, 0)
});
})
);
．.． 给:
<table>
<tr>
<th>Position</th>
<th>Country</th>
<th>City List</th>
<th>Population</th>
</tr>
<tr>
<td>1</td>
<td>Italia</td>
<td>Milano, Venezia</td>
<td>6</td>
</tr>
<tr>
<td>2</td>
<td>France</td>
<td>Lyon, Paris</td>
<td>9</td>
</tr>
<tr>
<td>3</td>
<td>Deutschland</td>
<td>München</td>
<td>4</td>
</tr>
</table>
4. JSONiq vs. JavaScript:
JavaScript等价于…
JSONiq用例1.1.2节。JSON查询分组
(https://jsfiddle.net/YSharpLanguage/hvo24hmk/3)
参看http://jsoniq.org/docs/JSONiq-usecases/html-single/index.html jsongrouping
在那里……
/*
1.1.2. Grouping Queries for JSON
http://jsoniq.org/docs/JSONiq-usecases/html-single/index.html#jsongrouping
*/
var sales = [
{ "product" : "broiler", "store number" : 1, "quantity" : 20 },
{ "product" : "toaster", "store number" : 2, "quantity" : 100 },
{ "product" : "toaster", "store number" : 2, "quantity" : 50 },
{ "product" : "toaster", "store number" : 3, "quantity" : 50 },
{ "product" : "blender", "store number" : 3, "quantity" : 100 },
{ "product" : "blender", "store number" : 3, "quantity" : 150 },
{ "product" : "socks", "store number" : 1, "quantity" : 500 },
{ "product" : "socks", "store number" : 2, "quantity" : 10 },
{ "product" : "shirt", "store number" : 3, "quantity" : 10 }
];
var products = [
{ "name" : "broiler", "category" : "kitchen", "price" : 100, "cost" : 70 },
{ "name" : "toaster", "category" : "kitchen", "price" : 30, "cost" : 10 },
{ "name" : "blender", "category" : "kitchen", "price" : 50, "cost" : 25 },
{ "name" : "socks", "category" : "clothes", "price" : 5, "cost" : 2 },
{ "name" : "shirt", "category" : "clothes", "price" : 10, "cost" : 3 }
];
var stores = [
{ "store number" : 1, "state" : "CA" },
{ "store number" : 2, "state" : "CA" },
{ "store number" : 3, "state" : "MA" },
{ "store number" : 4, "state" : "MA" }
];
var nestedGroupingAndAggregate = stores.select().orderBy("state").groupBy("state")
( function(byState) {
var state = byState[0],
stateStores = byState[1];
byState = { };
return (
(
byState[state] =
products.select().orderBy("category").groupBy("category")
( function(byCategory) {
var category = byCategory[0],
categoryProducts = byCategory[1],
categorySales = sales.filter(function(sale) {
return stateStores.find(function(store) { return sale["store number"] === store["store number"]; }) &&
categoryProducts.find(function(product) { return sale.product === product.name; });
});
byCategory = { };
return (
(
byCategory[category] =
categorySales.select().orderBy("product").groupBy("product")
( function(byProduct) {
var soldProduct = byProduct[0],
soldQuantities = byProduct[1];
byProduct = { };
return (
(
byProduct[soldProduct] =
soldQuantities.reduce(function(sum, sale) { return sum += sale.quantity; }, 0)
),
byProduct
);
} ) // byProduct()
),
byCategory
);
} ) // byCategory()
),
byState
);
} ); // byState()
．.． 给:
[
{
"CA": [
{
"clothes": [
{
"socks": 510
}
]
},
{
"kitchen": [
{
"broiler": 20
},
{
"toaster": 150
}
]
}
]
},
{
"MA": [
{
"clothes": [
{
"shirt": 10
}
]
},
{
"kitchen": [
{
"blender": 250
},
{
"toaster": 50
}
]
}
]
}
]
它还有助于克服JSONPath wrt的局限性。对祖先轴进行查询，就像这个SO问题(当然还有其他问题)所提出的那样。
例如，如何获得折扣的杂货项目知道其品牌标识，在
{
"prods": [
{
"info": {
"rate": 85
},
"grocery": [
{
"brand": "C",
"brand_id": "984"
},
{
"brand": "D",
"brand_id": "254"
}
],
"discount": "15"
},
{
"info": {
"rate": 100
},
"grocery": [
{
"brand": "A",
"brand_id": "983"
},
{
"brand": "B",
"brand_id": "253"
}
],
"discount": "20"
}
]
}
?
一个可能的解决方案是:
var products = {
"prods": [
{
"info": {
"rate": 85
},
"grocery": [
{
"brand": "C",
"brand_id": "984"
},
{
"brand": "D",
"brand_id": "254"
}
],
"discount": "15"
},
{
"info": {
"rate": 100
},
"grocery": [
{
"brand": "A",
"brand_id": "983"
},
{
"brand": "B",
"brand_id": "253"
}
],
"discount": "20"
}
]
};
function GroceryItem(obj) {
return (typeof obj.brand === "string") && (typeof obj.brand_id === "string");
}
// last parameter set to "true", to grab all the "GroceryItem" instances
// at any depth:
var itemsAndDiscounts = [ products ].nodeset(GroceryItem, true).
map(
function(node) {
var item = node.value, // node.value: the current "GroceryItem" (aka "$.prods[*].grocery[*]")
discount = node.parent. // node.parent: the array of "GroceryItem" (aka "$.prods[*].grocery")
parent. // node.parent.parent: the product (aka "$.prods[*]")
discount; // node.parent.parent.discount: the product discount
// finally, project into an easy-to-filter form:
return { id: item.brand_id, discount: discount };
}
),
discountOfItem983;
discountOfItem983 = itemsAndDiscounts.
filter
(
function(mapped) {
return mapped.id === "983";
}
)
[0].discount;
console.log("Discount of #983: " + discountOfItem983);
．.． 这使:
Discount of #983: 20
“HTH,
其他回答
jq——轻量级灵活的命令行JSON处理器
它不像XSLT那样基于模板，但更简洁。例如，将名称和地址字段提取到数组中:[.name， .address]
本教程介绍了一个转换Twitter JSON API的示例(手册中有很多示例)。
最近，我围绕着这个写了自己的小库，尽量保持接近
5.1处理模型(XSLT REC) https://www.w3.org/TR/xslt#section-Processing-Model
在几行JavaScript代码中。
这里有一些不完全琐碎的使用示例……
1. JSON-to-some-markup:
小提琴:https://jsfiddle.net/YSharpLanguage/kj9pk8oz/10
(灵感来自D.1文档示例(XSLT REC) https://www.w3.org/TR/xslt#section-Document-Example)
的地方:
var D1document = {
type: "document", title: [ "Document Title" ],
"": [
{ type: "chapter", title: [ "Chapter Title" ],
"": [
{ type: "section", title: [ "Section Title" ],
"": [
{ type: "para", "": [ "This is a test." ] },
{ type: "note", "": [ "This is a note." ] }
] },
{ type: "section", title: [ "Another Section Title" ],
"": [
{ type: "para", "": [ "This is ", { emph: "another" }, " test." ] },
{ type: "note", "": [ "This is another note." ] }
] }
] }
] };
var D1toHTML = { $: [
[ [ function(node) { return node.type === "document"; } ],
function(root) {
return "<html>\r\n\
<head>\r\n\
<title>\r\n\
{title}\r\n".of(root) + "\
</title>\r\n\
</head>\r\n\
<body>\r\n\
{*}".of(root[""].through(this)) + "\
</body>\r\n\
</html>";
}
],
[ [ function(node) { return node.type === "chapter"; } ],
function(chapter) {
return " <h2>{title}</h2>\r\n".of(chapter) + "{*}".of(chapter[""].through(this));
}
],
[ [ function(node) { return node.type === "section"; } ],
function(section) {
return " <h3>{title}</h3>\r\n".of(section) + "{*}".of(section[""].through(this));
}
],
[ [ function(node) { return node.type === "para"; } ],
function(para) {
return " <p>{*}</p>\r\n".of(para[""].through(this));
}
],
[ [ function(node) { return node.type === "note"; } ],
function(note) {
return ' <p class="note"><b>NOTE: </b>{*}</p>\r\n'.of(note[""].through(this));
}
],
[ [ function(node) { return node.emph; } ],
function(emph) {
return "<em>{emph}</em>".of(emph);
}
]
] };
console.log(D1document.through(D1toHTML));
．.． 给:
<html>
<head>
<title>
Document Title
</title>
</head>
<body>
<h2>Chapter Title</h2>
<h3>Section Title</h3>
<p>This is a test.</p>
<p class="note"><b>NOTE: </b>This is a note.</p>
<h3>Another Section Title</h3>
<p>This is <em>another</em> test.</p>
<p class="note"><b>NOTE: </b>This is another note.</p>
</body>
</html>
and
2. JSON-to-JSON:
小提琴:https://jsfiddle.net/YSharpLanguage/ppfmmu15/10
的地方:
// (A "Company" is just an object with a "Team")
function Company(obj) {
return obj.team && Team(obj.team);
}
// (A "Team" is just a non-empty array that contains at least one "Member")
function Team(obj) {
return ({ }.toString.call(obj) === "[object Array]") &&
obj.length &&
obj.find(function(item) { return Member(item); });
}
// (A "Member" must have first and last names, and a gender)
function Member(obj) {
return obj.first && obj.last && obj.sex;
}
function Dude(obj) {
return Member(obj) && (obj.sex === "Male");
}
function Girl(obj) {
return Member(obj) && (obj.sex === "Female");
}
var data = { team: [
{ first: "John", last: "Smith", sex: "Male" },
{ first: "Vaio", last: "Sony" },
{ first: "Anna", last: "Smith", sex: "Female" },
{ first: "Peter", last: "Olsen", sex: "Male" }
] };
var TO_SOMETHING_ELSE = { $: [
[ [ Company ],
function(company) {
return { some_virtual_dom: {
the_dudes: { ul: company.team.select(Dude).through(this) },
the_grrls: { ul: company.team.select(Girl).through(this) }
} }
} ],
[ [ Member ],
function(member) {
return { li: "{first} {last} ({sex})".of(member) };
} ]
] };
console.log(JSON.stringify(data.through(TO_SOMETHING_ELSE), null, 4));
．.． 给:
{
"some_virtual_dom": {
"the_dudes": {
"ul": [
{
"li": "John Smith (Male)"
},
{
"li": "Peter Olsen (Male)"
}
]
},
"the_grrls": {
"ul": [
{
"li": "Anna Smith (Female)"
}
]
}
}
}
3.XSLT与JavaScript:
JavaScript等价于…
XSLT 3.0 REC 14.4示例:基于公共值对节点进行分组
(http://jsfiddle.net/YSharpLanguage/8bqcd0ey/1)
参看https://www.w3.org/TR/xslt-30/ grouping-examples
在那里……
var cities = [
{ name: "Milano", country: "Italia", pop: 5 },
{ name: "Paris", country: "France", pop: 7 },
{ name: "München", country: "Deutschland", pop: 4 },
{ name: "Lyon", country: "France", pop: 2 },
{ name: "Venezia", country: "Italia", pop: 1 }
];
/*
Cf.
XSLT 3.0 REC Section 14.4
Example: Grouping Nodes based on Common Values
https://www.w3.org/TR/xslt-30/#grouping-examples
*/
var output = "<table>\r\n\
<tr>\r\n\
<th>Position</th>\r\n\
<th>Country</th>\r\n\
<th>City List</th>\r\n\
<th>Population</th>\r\n\
</tr>{*}\r\n\
</table>".of
(
cities.select().groupBy("country")(function(byCountry, index) {
var country = byCountry[0],
cities = byCountry[1].select().orderBy("name");
return "\r\n\
<tr>\r\n\
<td>{position}</td>\r\n\
<td>{country}</td>\r\n\
<td>{cities}</td>\r\n\
<td>{population}</td>\r\n\
</tr>".
of({ position: index + 1, country: country,
cities: cities.map(function(city) { return city.name; }).join(", "),
population: cities.reduce(function(sum, city) { return sum += city.pop; }, 0)
});
})
);
．.． 给:
<table>
<tr>
<th>Position</th>
<th>Country</th>
<th>City List</th>
<th>Population</th>
</tr>
<tr>
<td>1</td>
<td>Italia</td>
<td>Milano, Venezia</td>
<td>6</td>
</tr>
<tr>
<td>2</td>
<td>France</td>
<td>Lyon, Paris</td>
<td>9</td>
</tr>
<tr>
<td>3</td>
<td>Deutschland</td>
<td>München</td>
<td>4</td>
</tr>
</table>
4. JSONiq vs. JavaScript:
JavaScript等价于…
JSONiq用例1.1.2节。JSON查询分组
(https://jsfiddle.net/YSharpLanguage/hvo24hmk/3)
参看http://jsoniq.org/docs/JSONiq-usecases/html-single/index.html jsongrouping
在那里……
/*
1.1.2. Grouping Queries for JSON
http://jsoniq.org/docs/JSONiq-usecases/html-single/index.html#jsongrouping
*/
var sales = [
{ "product" : "broiler", "store number" : 1, "quantity" : 20 },
{ "product" : "toaster", "store number" : 2, "quantity" : 100 },
{ "product" : "toaster", "store number" : 2, "quantity" : 50 },
{ "product" : "toaster", "store number" : 3, "quantity" : 50 },
{ "product" : "blender", "store number" : 3, "quantity" : 100 },
{ "product" : "blender", "store number" : 3, "quantity" : 150 },
{ "product" : "socks", "store number" : 1, "quantity" : 500 },
{ "product" : "socks", "store number" : 2, "quantity" : 10 },
{ "product" : "shirt", "store number" : 3, "quantity" : 10 }
];
var products = [
{ "name" : "broiler", "category" : "kitchen", "price" : 100, "cost" : 70 },
{ "name" : "toaster", "category" : "kitchen", "price" : 30, "cost" : 10 },
{ "name" : "blender", "category" : "kitchen", "price" : 50, "cost" : 25 },
{ "name" : "socks", "category" : "clothes", "price" : 5, "cost" : 2 },
{ "name" : "shirt", "category" : "clothes", "price" : 10, "cost" : 3 }
];
var stores = [
{ "store number" : 1, "state" : "CA" },
{ "store number" : 2, "state" : "CA" },
{ "store number" : 3, "state" : "MA" },
{ "store number" : 4, "state" : "MA" }
];
var nestedGroupingAndAggregate = stores.select().orderBy("state").groupBy("state")
( function(byState) {
var state = byState[0],
stateStores = byState[1];
byState = { };
return (
(
byState[state] =
products.select().orderBy("category").groupBy("category")
( function(byCategory) {
var category = byCategory[0],
categoryProducts = byCategory[1],
categorySales = sales.filter(function(sale) {
return stateStores.find(function(store) { return sale["store number"] === store["store number"]; }) &&
categoryProducts.find(function(product) { return sale.product === product.name; });
});
byCategory = { };
return (
(
byCategory[category] =
categorySales.select().orderBy("product").groupBy("product")
( function(byProduct) {
var soldProduct = byProduct[0],
soldQuantities = byProduct[1];
byProduct = { };
return (
(
byProduct[soldProduct] =
soldQuantities.reduce(function(sum, sale) { return sum += sale.quantity; }, 0)
),
byProduct
);
} ) // byProduct()
),
byCategory
);
} ) // byCategory()
),
byState
);
} ); // byState()
．.． 给:
[
{
"CA": [
{
"clothes": [
{
"socks": 510
}
]
},
{
"kitchen": [
{
"broiler": 20
},
{
"toaster": 150
}
]
}
]
},
{
"MA": [
{
"clothes": [
{
"shirt": 10
}
]
},
{
"kitchen": [
{
"blender": 250
},
{
"toaster": 50
}
]
}
]
}
]
它还有助于克服JSONPath wrt的局限性。对祖先轴进行查询，就像这个SO问题(当然还有其他问题)所提出的那样。
例如，如何获得折扣的杂货项目知道其品牌标识，在
{
"prods": [
{
"info": {
"rate": 85
},
"grocery": [
{
"brand": "C",
"brand_id": "984"
},
{
"brand": "D",
"brand_id": "254"
}
],
"discount": "15"
},
{
"info": {
"rate": 100
},
"grocery": [
{
"brand": "A",
"brand_id": "983"
},
{
"brand": "B",
"brand_id": "253"
}
],
"discount": "20"
}
]
}
?
一个可能的解决方案是:
var products = {
"prods": [
{
"info": {
"rate": 85
},
"grocery": [
{
"brand": "C",
"brand_id": "984"
},
{
"brand": "D",
"brand_id": "254"
}
],
"discount": "15"
},
{
"info": {
"rate": 100
},
"grocery": [
{
"brand": "A",
"brand_id": "983"
},
{
"brand": "B",
"brand_id": "253"
}
],
"discount": "20"
}
]
};
function GroceryItem(obj) {
return (typeof obj.brand === "string") && (typeof obj.brand_id === "string");
}
// last parameter set to "true", to grab all the "GroceryItem" instances
// at any depth:
var itemsAndDiscounts = [ products ].nodeset(GroceryItem, true).
map(
function(node) {
var item = node.value, // node.value: the current "GroceryItem" (aka "$.prods[*].grocery[*]")
discount = node.parent. // node.parent: the array of "GroceryItem" (aka "$.prods[*].grocery")
parent. // node.parent.parent: the product (aka "$.prods[*]")
discount; // node.parent.parent.discount: the product discount
// finally, project into an easy-to-filter form:
return { id: item.brand_id, discount: discount };
}
),
discountOfItem983;
discountOfItem983 = itemsAndDiscounts.
filter
(
function(mapped) {
return mapped.id === "983";
}
)
[0].discount;
console.log("Discount of #983: " + discountOfItem983);
．.． 这使:
Discount of #983: 20
“HTH,
XSLT支持JSON，见http://www.w3.org/TR/xslt-30/#json
XML uses angular brackets for delimiter tokens, JSON uses braces, square brackets, ... I. e. XML's fewer token recognition comparisons means it's optimized for declarative transformation, whereas more comparisons, being like switch statement, for speed reasons assume speculative branch prediction that imperative code in scripting languages is useful for. As direct consequence, for different mixes of semi-structured data, you may want to benchmark XSLT and javascript engines' performance as part of responsive pages. For negligible data payload, transformations might work just as well with JSON without XML serialization. W3's decision ought to be based on better analysis.
现在有了!我最近创建了一个库，json-transforms，正是为了这个目的:
https://github.com/ColinEberhardt/json-transforms
它结合使用了JSPath(一种模仿XPath的DSL)和一种直接受到XSLT启发的递归模式匹配方法。
这里有一个简单的例子。给定以下JSON对象:
const json = {
"automobiles": [
{ "maker": "Nissan", "model": "Teana", "year": 2011 },
{ "maker": "Honda", "model": "Jazz", "year": 2010 },
{ "maker": "Honda", "model": "Civic", "year": 2007 },
{ "maker": "Toyota", "model": "Yaris", "year": 2008 },
{ "maker": "Honda", "model": "Accord", "year": 2011 }
]
};
这是一个变换:
const jsont = require('json-transforms');
const rules = [
jsont.pathRule(
'.automobiles{.maker === "Honda"}', d => ({
Honda: d.runner()
})
),
jsont.pathRule(
'.{.maker}', d => ({
model: d.match.model,
year: d.match.year
})
),
jsont.identity
];
const transformed = jsont.transform(json, rules);
输出如下:
{
"Honda": [
{ "model": "Jazz", "year": 2010 },
{ "model": "Civic", "year": 2007 },
{ "model": "Accord", "year": 2011 }
]
}
这个转换由三个规则组成。第一个匹配本田制造的任何汽车，发出一个具有Honda属性的对象，然后递归匹配。第二条规则匹配任何具有maker属性的对象，输出模型和年份属性。最后一个是递归匹配的恒等变换。
我最近发现了一个我喜欢的JSON样式工具:https://github.com/twigkit/tempo。非常容易使用的工具——在我看来，使用它比使用XSLT容易得多——不需要XPATH查询。
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