我得到了一个AsyncTask，应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?
public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {
private Main main;
public HostAvailabilityTask(Main main) {
this.main = main;
}
protected Boolean doInBackground(String... params) {
Main.Log("doInBackground() isHostAvailable():"+params[0]);
try {
return InetAddress.getByName(params[0]).isReachable(30);
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return false;
}
protected void onPostExecute(Boolean... result) {
Main.Log("onPostExecute()");
if(result[0] == false) {
main.setContentView(R.layout.splash);
return;
}
main.continueAfterHostCheck();
}
}
这是最简单和简单的方法来检查互联网连接的wifi和移动数据。
public static boolean isConnected(Activity _context) {
if (_context != null) {
ConnectivityManager connMgr = (ConnectivityManager) _context.getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo activeInfo = connMgr.getActiveNetworkInfo();
if (activeInfo != null && activeInfo.isConnected()) {
boolean wifiConnected = activeInfo.getType() == ConnectivityManager.TYPE_WIFI;
boolean mobileConnected = activeInfo.getType() == ConnectivityManager.TYPE_MOBILE;
if (wifiConnected || mobileConnected) {
Log.d(TAG, "Wifi Connected ");
return true;
} else {
showAlert(_context,_context.getString(R.string.err_no_internet));
return false;
}
} else {
showAlert(_context,_context.getString(R.string.err_no_internet));
return false;
}
} else {
Log.e(TAG, "networkConnectivity: Context NULL");
}
return false;
}
在芬兰湾的科特林:
class UtilityMethods {
companion object {
fun isConnected(activity: Activity): Boolean {
val connectivityManager: ConnectivityManager =
activity.getSystemService(Context.CONNECTIVITY_SERVICE) as ConnectivityManager
return null != connectivityManager.activeNetworkInfo
}
}}
在Activity类中调用isConnected如下:
UtilityMethods.isConnected(this)
内部片段类如下:
UtilityMethods.isConnected(activity)
检查这段代码…这对我很有用:)
public static void isNetworkAvailable(final Handler handler, final int timeout) {
// ask fo message '0' (not connected) or '1' (connected) on 'handler'
// the answer must be send before before within the 'timeout' (in milliseconds)
new Thread() {
private boolean responded = false;
@Override
public void run() {
// set 'responded' to TRUE if is able to connect with google mobile (responds fast)
new Thread() {
@Override
public void run() {
HttpGet requestForTest = new HttpGet("http://m.google.com");
try {
new DefaultHttpClient().execute(requestForTest); // can last...
responded = true;
}
catch (Exception e) {
}
}
}.start();
try {
int waited = 0;
while(!responded && (waited < timeout)) {
sleep(100);
if(!responded ) {
waited += 100;
}
}
}
catch(InterruptedException e) {} // do nothing
finally {
if (!responded) { handler.sendEmptyMessage(0); }
else { handler.sendEmptyMessage(1); }
}
}
}.start();
}
然后，我定义处理程序:
Handler h = new Handler() {
@Override
public void handleMessage(Message msg) {
if (msg.what != 1) { // code if not connected
} else { // code if connected
}
}
};
.．.并启动测试:
isNetworkAvailable(h,2000); // get the answser within 2000 ms
对我来说，在Activity类中检查连接状态并不是一个好的实践，因为
ConnectivityManager cm =
(ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
应该在那里调用，或者您需要下推您的活动实例(上下文)到连接处理程序类，以能够检查那里的连接状态
当没有可用的连接(wifi，网络)时，我捕捉到UnknownHostException异常:
JSONObject jObj = null;
Boolean responded = false;
HttpGet requestForTest = new HttpGet("http://myserver.com");
try {
new DefaultHttpClient().execute(requestForTest);
responded = true;
} catch (UnknownHostException e) {
jObj = new JSONObject();
try {
jObj.put("answer_code", 1);
jObj.put("answer_text", "No available connection");
} catch (Exception e1) {}
return jObj;
} catch (IOException e) {
e.printStackTrace();
}
通过这种方式，我可以处理这种情况连同其他情况在同一类(我的服务器总是响应回json字符串)
更新29/06/2015
如果你正在使用Xamarin。Android和想要检查连接，你可以使用Nuget包，这将给你在多个平台上的功能。好的候选人在这里和这里。
[更新结束]
The Answers above are quite good, but they are all in Java, and almost all of them check for a connectivity. In my case, I needed to have connectivity with a specific type of connection and I am developing on Xamarin.Android. Moreover, I do not pass a reference to my activities Context in the Hardware layer, I use the Application Context. So here is my solution, in case somebody comes here with similar requirements. I have not done full testing though, will update the answer once I am done with my testing
using Android.App;
using Android.Content;
using Android.Net;
namespace Leopard.Mobile.Hal.Android
{
public class AndroidNetworkHelper
{
public static AndroidNetworkStatus GetWifiConnectivityStatus()
{
return GetConnectivityStatus(ConnectivityType.Wifi);
}
public static AndroidNetworkStatus GetMobileConnectivityStatus()
{
return GetConnectivityStatus(ConnectivityType.Mobile);
}
#region Implementation
private static AndroidNetworkStatus GetConnectivityStatus(ConnectivityType connectivityType)
{
var connectivityManager = (ConnectivityManager)Application.Context.GetSystemService(Context.ConnectivityService);
var wifiNetworkInfo = connectivityManager.GetNetworkInfo(connectivityType);
var result = GetNetworkStatus(wifiNetworkInfo);
return result;
}
private static AndroidNetworkStatus GetNetworkStatus(NetworkInfo wifiNetworkInfo)
{
var result = AndroidNetworkStatus.Unknown;
if (wifiNetworkInfo != null)
{
if (wifiNetworkInfo.IsAvailable && wifiNetworkInfo.IsConnected)
{
result = AndroidNetworkStatus.Connected;
}
else
{
result = AndroidNetworkStatus.Disconnected;
}
}
return result;
}
#endregion
}
public enum AndroidNetworkStatus
{
Connected,
Disconnected,
Unknown
}
下面是我使用的方法:
public boolean isNetworkAvailable(final Context context) {
return ((ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE)).getActiveNetworkInfo() != null;
}
更好的是，检查确保它是“连接”的:
public boolean isNetworkAvailable(final Context context) {
final ConnectivityManager connectivityManager = ((ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE));
return connectivityManager.getActiveNetworkInfo() != null && connectivityManager.getActiveNetworkInfo().isConnected();
}
下面是如何使用该方法:
if (isNetworkAvailable(context)) {
// code here
} else {
// code
}
需要许可:
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
https://stackoverflow.com/a/16124915/950427
