我得到了一个AsyncTask,应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}

当前回答

不要检查WIFI连接或移动数据连接,试着点击任何托管域。以便您可以检查WIFI/Mobile连接是否具有连接公共互联网的能力。

如果您的移动设备能够连接到所提供的公共域,则将返回以下内容。

boolean isReachable()
        {
            boolean connected = false;
            String instanceURL = "Your trusted domain name";
            Socket socket;
            try {
                socket = new Socket();
                SocketAddress socketAddress = new InetSocketAddress(instanceURL, 80);
                socket.connect(socketAddress, 5000);
                if (socket.isConnected()) {
                    connected = true;
                    socket.close();
                }
            } catch (IOException e) {
                e.printStackTrace();
            } finally {
                socket = null;
            }
            return connected;
        }

希望对大家有所帮助。

其他回答

看一下ConnectivityManager类。您可以使用这个类来获取主机上活动连接的信息。http://developer.android.com/reference/android/net/ConnectivityManager.html

编辑:你可以使用

Context.getSystemService(Context.CONNECTIVITY_SERVICE)
    .getNetworkInfo(ConnectivityManager.TYPE_MOBILE) 

or

Context.getSystemService(Context.CONNECTIVITY_SERVICE)
    .getNetworkInfo(ConnectivityManager.TYPE_WIFI) 

并解析返回NetworkInfo对象的DetailedState枚举

EDIT EDIT:查看是否可以访问主机

Context.getSystemService(Context.CONNECTIVITY_SERVICE)
    .requestRouteToHost(TYPE_WIFI, int hostAddress)

显然,我使用Context.getSystemService(Context.CONNECTIVITY_SERVICE)作为代理来表示

ConnectivityManager cm = Context.getSystemService(Context.CONNECTIVITY_SERVICE);
cm.yourMethodCallHere();

使用以下方法检查互联网连接,同时ConnectivityManager.getActiveNetworkInfo()在API 28中已弃用

@Suppress("DEPRECATION")
fun isNetworkConnected(context: Context): Boolean {
    val cm = context.getSystemService(Context.CONNECTIVITY_SERVICE) as ConnectivityManager?
    return cm?.run {
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
            cm.getNetworkCapabilities(cm.activeNetwork)?.run {
                when {
                    hasTransport(NetworkCapabilities.TRANSPORT_WIFI) -> true
                    hasTransport(NetworkCapabilities.TRANSPORT_CELLULAR) -> true
                    hasTransport(NetworkCapabilities.TRANSPORT_ETHERNET) -> true
                    else -> false
                }
            }
        } else {
            cm.activeNetworkInfo?.run {
                when (type) {
                    ConnectivityManager.TYPE_WIFI -> true
                    ConnectivityManager.TYPE_MOBILE -> true
                    else -> false
                }
            }
        }
    } ?: false

}

还要向清单添加以下权限

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

hatransport_ethernet (NetworkCapabilities.TRANSPORT_ETHERNET)用于为Android TV开发的应用程序,其中TV可以直接连接到以太网

The other answers that use ConnectivityManager are wrong because having a network connection doesn't mean you have internet access. For example, the user might be connected to a coffee shop's WiFi portal but can't get to the internet. To check that the internet is accessible you have to try to connect to an actual server. Normally when you want to do this you have a specific server in mind that you want to connect to, so go ahead and check if you can connect to that server. Here's a simple method for checking connectivity to a server.

private boolean isOnTheInternet() {
    try {
        URLConnection urlConnection = new URL("http://yourserver").openConnection();
        urlConnection.setConnectTimeout(400);
        urlConnection.connect();
        return true;
    } catch (Exception e) {
        return false;
    }
}

设置ConnectTimeout的原因是,否则它默认为TCP超时,可以有很多秒长。

还要注意的是,Android不允许你在主线程上运行这个程序。

Kotlin和协程

我将函数放置在一个ViewModel中,该ViewModel具有viewModelScope。使用一个可观察的LiveData,我通知一个活动有关连接。

ViewModel

 fun checkInternetConnection(timeoutMs: Int) {
        viewModelScope.launch(Dispatchers.IO) {
            try {
                val socket = Socket()
                val socketAddress = InetSocketAddress("8.8.8.8", 53)

                socket.connect(socketAddress, timeoutMs)
                socket.close()

                _connection.postValue(true)
            }
            catch(ex: IOException) {
                _connection.postValue(false)
            }
        }
    }
 private val _connection = MutableLiveData<Boolean>()
 val connection: LiveData<Boolean> = _connection

活动

 private fun checkInternetConnection() {
     viewModel.connection.observe(this) { hasInternet ->
         if(!hasInternet) {
             //hasn't connection
         }
         else {
            //has connection
         }
     }
  }

检查这段代码…这对我很有用:)

public static void isNetworkAvailable(final Handler handler, final int timeout) {
    // ask fo message '0' (not connected) or '1' (connected) on 'handler'
    // the answer must be send before before within the 'timeout' (in milliseconds)

    new Thread() {
        private boolean responded = false;   
        @Override
        public void run() { 
            // set 'responded' to TRUE if is able to connect with google mobile (responds fast) 
            new Thread() {      
                @Override
                public void run() {
                    HttpGet requestForTest = new HttpGet("http://m.google.com");
                    try {
                        new DefaultHttpClient().execute(requestForTest); // can last...
                        responded = true;
                    } 
                    catch (Exception e) {
                    }
                } 
            }.start();

            try {
                int waited = 0;
                while(!responded && (waited < timeout)) {
                    sleep(100);
                    if(!responded ) { 
                        waited += 100;
                    }
                }
            } 
            catch(InterruptedException e) {} // do nothing 
            finally { 
                if (!responded) { handler.sendEmptyMessage(0); } 
                else { handler.sendEmptyMessage(1); }
            }
        }
    }.start();
}

然后,我定义处理程序:

Handler h = new Handler() {
    @Override
    public void handleMessage(Message msg) {

        if (msg.what != 1) { // code if not connected

        } else { // code if connected

        }   
    }
};

...并启动测试:

isNetworkAvailable(h,2000); // get the answser within 2000 ms