我得到了一个AsyncTask,应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}

当前回答

不要检查WIFI连接或移动数据连接,试着点击任何托管域。以便您可以检查WIFI/Mobile连接是否具有连接公共互联网的能力。

如果您的移动设备能够连接到所提供的公共域,则将返回以下内容。

boolean isReachable()
        {
            boolean connected = false;
            String instanceURL = "Your trusted domain name";
            Socket socket;
            try {
                socket = new Socket();
                SocketAddress socketAddress = new InetSocketAddress(instanceURL, 80);
                socket.connect(socketAddress, 5000);
                if (socket.isConnected()) {
                    connected = true;
                    socket.close();
                }
            } catch (IOException e) {
                e.printStackTrace();
            } finally {
                socket = null;
            }
            return connected;
        }

希望对大家有所帮助。

其他回答

这里有一个简单的解决方案,以确保你的应用程序可以访问互联网:

static final String CHECK_INTERNET_ACCESS_URL = "https://www.google.com";

public static void isInternetAccessWorking(Context context) {

    StringRequest stringRequest = new StringRequest(Request.Method.GET, CHECK_INTERNET_ACCESS_URL,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    // Internet access is OK
                }
            }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            // NO internet access
        }
    });

    Volley.newRequestQueue(context).add(stringRequest);
}

这个解决方案使用Android的Volley库,必须在build.gradle中声明:

implementation 'com.android.volley:volley:1.1.1'

Kotlin和协程

我将函数放置在一个ViewModel中,该ViewModel具有viewModelScope。使用一个可观察的LiveData,我通知一个活动有关连接。

ViewModel

 fun checkInternetConnection(timeoutMs: Int) {
        viewModelScope.launch(Dispatchers.IO) {
            try {
                val socket = Socket()
                val socketAddress = InetSocketAddress("8.8.8.8", 53)

                socket.connect(socketAddress, timeoutMs)
                socket.close()

                _connection.postValue(true)
            }
            catch(ex: IOException) {
                _connection.postValue(false)
            }
        }
    }
 private val _connection = MutableLiveData<Boolean>()
 val connection: LiveData<Boolean> = _connection

活动

 private fun checkInternetConnection() {
     viewModel.connection.observe(this) { hasInternet ->
         if(!hasInternet) {
             //hasn't connection
         }
         else {
            //has connection
         }
     }
  }

Jetpack组成/芬兰湾的科特林

根据Levite的回答,我们可以在Jetpack Compose中使用这个组合:

val DNS_SERVERS = listOf("8.8.8.8", "1.1.1.1", "4.2.2.4")
const val INTERNET_CHECK_DELAY = 3000L
@Composable
fun InternetAwareComposable(
    dnsServers: List<String> = DNS_SERVERS,
    delay: Long = INTERNET_CHECK_DELAY,
    successContent: (@Composable () -> Unit)? = null,
    errorContent: (@Composable () -> Unit)? = null,
    onlineChanged: ((Boolean) -> Unit)? = null
) {
    suspend fun dnsAccessible(
        dnsServer: String
    ) = try {
        withContext(Dispatchers.IO) {
            Runtime.getRuntime().exec("/system/bin/ping -c 1 $dnsServer").waitFor()
        } == 0
    } catch (e: Exception) {
        false
    }

    var isOnline by remember { mutableStateOf(false) }
    LaunchedEffect(Unit) {
        while (true) {
            isOnline = dnsServers.any { dnsAccessible(it) }
            onlineChanged?.invoke(isOnline)
            delay(delay)
        }
    }
    if (isOnline) successContent?.invoke()
    else errorContent?.invoke()
}

正如Android文档建议的那样,之后

getActiveNetworkInfo()在Android 10中已弃用。使用 而不是针对Android 10 (API级别)的应用程序的NetworkCallbacks 29)更高。

下面是我们目前检查网络连接的方法:

val cm = context.getSystemService(Context.CONNECTIVITY_SERVICE) as ConnectivityManager
val activeNetwork: NetworkInfo? = cm.activeNetworkInfo
val isConnected: Boolean = activeNetwork?.isConnectedOrConnecting == true

使用NetworkCallbacks检查网络连接的新方法

步骤1:

    private lateinit var connectivityManager:ConnectivityManager

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        ...
        connectivityManager = getSystemService(Context.CONNECTIVITY_SERVICE) as ConnectivityManager
    }

步骤2:创建回调:

private val callback = object : ConnectivityManager.NetworkCallback() {
    override fun onAvailable(network: Network) {
        super.onAvailable(network)
        Timber.e("Network:onAvailable")
    }

    override fun onLost(network: Network) {
        super.onLost(network)
        Timber.e("Network:onLost")
    }

}

步骤3:注册和取消注册回调:

private fun registerNetworkCallback() {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) {
        connectivityManager.registerDefaultNetworkCallback(callback)
    } else {
        // Old way to check network connection
    }
}

override fun onStop() {
    unRegisterNetworkCallback()
    super.onStop()
}

private fun unRegisterNetworkCallback() {
    connectivityManager.unregisterNetworkCallback(callback)
}

结帐更新详情如下链接:

https://developer.android.com/training/monitoring-device-state/connectivity-status-type

最简单的解决办法是

在大多数情况下,如果他/她想连接到远程服务器,只会检查互联网连接,所以简单和最好的解决方案是ping你的服务器,如下所示。

public boolean isConnected() {
    final String command = "ping -c 1 yourExmapleDomain.com";
    boolean isConnected = false;
    try {
        isConnected = Runtime.getRuntime().exec(command).waitFor() == 0;
    } catch (InterruptedException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return isConnected;
}