我得到了一个AsyncTask,应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}

当前回答

我做了这个代码,它是最简单的,它只是一个布尔值。 通过询问if(isOnline()){

如果存在连接,并且可以连接到页面,则会得到状态代码200(稳定连接)。

确保添加正确的INTERNET和ACCESS_NETWORK_STATE权限。

public boolean isOnline() {
    ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo netInfo = cm.getActiveNetworkInfo();
    if (netInfo != null && netInfo.isConnected()) {
        try {
            URL url = new URL("http://www.google.com");
            HttpURLConnection urlc = (HttpURLConnection) url.openConnection();
            urlc.setConnectTimeout(3000);
            urlc.connect();
            if (urlc.getResponseCode() == 200) {
                return new Boolean(true);
            }
        } catch (MalformedURLException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
    return false;
}

其他回答

检查这段代码…这对我很有用:)

public static void isNetworkAvailable(final Handler handler, final int timeout) {
    // ask fo message '0' (not connected) or '1' (connected) on 'handler'
    // the answer must be send before before within the 'timeout' (in milliseconds)

    new Thread() {
        private boolean responded = false;   
        @Override
        public void run() { 
            // set 'responded' to TRUE if is able to connect with google mobile (responds fast) 
            new Thread() {      
                @Override
                public void run() {
                    HttpGet requestForTest = new HttpGet("http://m.google.com");
                    try {
                        new DefaultHttpClient().execute(requestForTest); // can last...
                        responded = true;
                    } 
                    catch (Exception e) {
                    }
                } 
            }.start();

            try {
                int waited = 0;
                while(!responded && (waited < timeout)) {
                    sleep(100);
                    if(!responded ) { 
                        waited += 100;
                    }
                }
            } 
            catch(InterruptedException e) {} // do nothing 
            finally { 
                if (!responded) { handler.sendEmptyMessage(0); } 
                else { handler.sendEmptyMessage(1); }
            }
        }
    }.start();
}

然后,我定义处理程序:

Handler h = new Handler() {
    @Override
    public void handleMessage(Message msg) {

        if (msg.what != 1) { // code if not connected

        } else { // code if connected

        }   
    }
};

...并启动测试:

isNetworkAvailable(h,2000); // get the answser within 2000 ms

网络连接/互联网接入

isConnectedOrConnecting()(在大多数回答中使用)检查任何网络连接 要了解这些网络是否有internet接入,请使用以下方法之一

A) Ping服务器(简单)

// ICMP 
public boolean isOnline() {
    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int     exitValue = ipProcess.waitFor();
        return (exitValue == 0);
    }
    catch (IOException e)          { e.printStackTrace(); }
    catch (InterruptedException e) { e.printStackTrace(); }

    return false;
}

+可以在主线程上运行

在一些旧设备上不能工作(Galays S3等),如果没有网络,它会阻塞一段时间。

B)连接到Internet上的Socket(高级)

// TCP/HTTP/DNS (depending on the port, 53=DNS, 80=HTTP, etc.)
public boolean isOnline() {
    try {
        int timeoutMs = 1500;
        Socket sock = new Socket();
        SocketAddress sockaddr = new InetSocketAddress("8.8.8.8", 53);

        sock.connect(sockaddr, timeoutMs);
        sock.close();

        return true;
    } catch (IOException e) { return false; }
}

+非常快(任何一种方式),适用于所有设备,非常可靠

-不能在UI线程上运行

这工作非常可靠,在每个设备上,非常快。它需要在一个单独的任务中运行(例如ScheduledExecutorService或AsyncTask)。

可能的问题

Is it really fast enough? Yes, very fast ;-) Is there no reliable way to check internet, other than testing something on the internet? Not as far as I know, but let me know, and I will edit my answer. What if the DNS is down? Google DNS (e.g. 8.8.8.8) is the largest public DNS in the world. As of 2018 it handled over a trillion queries a day [1]. Let 's just say, your app would probably not be the talk of the day. Which permissions are required? <uses-permission android:name="android.permission.INTERNET" /> Just internet access - surprise ^^ (Btw have you ever thought about, how some of the methods suggested here could even have a remote glue about internet access, without this permission?)

 

额外:一次性RxJava/RxAndroid示例(Kotlin)

fun hasInternetConnection(): Single<Boolean> {
  return Single.fromCallable {
    try {
      // Connect to Google DNS to check for connection
      val timeoutMs = 1500
      val socket = Socket()
      val socketAddress = InetSocketAddress("8.8.8.8", 53)
    
      socket.connect(socketAddress, timeoutMs)
      socket.close()
  
      true
    } catch (e: IOException) {
      false
    }
  }
  .subscribeOn(Schedulers.io())
  .observeOn(AndroidSchedulers.mainThread())
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    hasInternetConnection().subscribe { hasInternet -> /* do something */}

额外:一次性RxJava/RxAndroid示例(Java)

public static Single<Boolean> hasInternetConnection() {
    return Single.fromCallable(() -> {
        try {
            // Connect to Google DNS to check for connection
            int timeoutMs = 1500;
            Socket socket = new Socket();
            InetSocketAddress socketAddress = new InetSocketAddress("8.8.8.8", 53);

            socket.connect(socketAddress, timeoutMs);
            socket.close();

            return true;
        } catch (IOException e) {
            return false;
        }
    }).subscribeOn(Schedulers.io()).observeOn(AndroidSchedulers.mainThread());
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    hasInternetConnection().subscribe((hasInternet) -> {
        if(hasInternet) {

        }else {

        }
    });

额外:一次性AsyncTask示例

注意:这是如何执行请求的另一个示例。然而,由于AsyncTask已弃用,它应该被你的应用程序的线程调度,Kotlin协程,Rx,…

class InternetCheck extends AsyncTask<Void,Void,Boolean> {

    private Consumer mConsumer;
    public  interface Consumer { void accept(Boolean internet); }

    public  InternetCheck(Consumer consumer) { mConsumer = consumer; execute(); }

    @Override protected Boolean doInBackground(Void... voids) { try {
        Socket sock = new Socket();
        sock.connect(new InetSocketAddress("8.8.8.8", 53), 1500);
        sock.close();
        return true;
    } catch (IOException e) { return false; } }

    @Override protected void onPostExecute(Boolean internet) { mConsumer.accept(internet); }
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    new InternetCheck(internet -> { /* do something with boolean response */ });

下面是我使用的方法:

public boolean isNetworkAvailable(final Context context) {
    return ((ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE)).getActiveNetworkInfo() != null;
}

更好的是,检查确保它是“连接”的:

public boolean isNetworkAvailable(final Context context) {
    final ConnectivityManager connectivityManager = ((ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE));
    return connectivityManager.getActiveNetworkInfo() != null && connectivityManager.getActiveNetworkInfo().isConnected();
}

下面是如何使用该方法:

if (isNetworkAvailable(context)) {
    // code here
} else {
    // code
}

需要许可:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

https://stackoverflow.com/a/16124915/950427

不要检查WIFI连接或移动数据连接,试着点击任何托管域。以便您可以检查WIFI/Mobile连接是否具有连接公共互联网的能力。

如果您的移动设备能够连接到所提供的公共域,则将返回以下内容。

boolean isReachable()
        {
            boolean connected = false;
            String instanceURL = "Your trusted domain name";
            Socket socket;
            try {
                socket = new Socket();
                SocketAddress socketAddress = new InetSocketAddress(instanceURL, 80);
                socket.connect(socketAddress, 5000);
                if (socket.isConnected()) {
                    connected = true;
                    socket.close();
                }
            } catch (IOException e) {
                e.printStackTrace();
            } finally {
                socket = null;
            }
            return connected;
        }

希望对大家有所帮助。

我已经经历了所有的答案,我想出了我自己的答案,首先检查互联网是否可用,如果互联网可用,然后检查它是否活跃。

我已经包括了所有必要的方法和类来检查活跃的Internet连接。

NetworkUtils.class

public class NetworkUtils {

    public static final int STATUS_CONNECTED = 0 ;

    public static boolean isInternetAvailable(Context ctx){
        ConnectivityManager cm = (ConnectivityManager)ctx.getSystemService(Context.CONNECTIVITY_SERVICE);
        NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
        return activeNetwork != null && activeNetwork.isConnectedOrConnecting();
    }

    public static int isInternetActiveWithPing() {
        try {
            Runtime runtime = Runtime.getRuntime();
            Process process = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
            int exitValue = process.waitFor();
            return exitValue;
        } catch (Exception ex) {
            return -1;
        }
    }

    public static boolean isInternetActiveWithInetAddress() {
        try {
            InetAddress inetAddress = InetAddress.getByName("www.google.com");
            return inetAddress != null && !inetAddress.toString().equals("");
        } catch (Exception ex) {
            return false;
        }
    }

    public static void displayInternetConnectionMessage(Context ctx){
        Toast.makeText(ctx, "Check Internet Connection", Toast.LENGTH_SHORT).show();
    }
}

你可以使用下面的代码检查互联网是否活跃:

 private void checkInternetConnection() {
        if (NetworkUtils.isInternetAvailable(this)) {
            new Thread(new Runnable() {
                @Override
                public void run() {
                    if (NetworkUtils.isInternetActiveWithPing() == NetworkUtils.STATUS_CONNECTED) {
                        performNetworkingOperations();
                    } else {
                        if (NetworkUtils.isInternetActiveWithInetAddress()) {
                            performNetworkingOperations();
                        } else {
                            displayConnectionMessage();
                        }
                    }
                }
            }).start();

        } else {
            displayConnectionMessage();
        }
    }

    private void performNetworkingOperations() {
        runOnUiThread(new Runnable() {
            @Override
            public void run() {
                Toast.makeText(MainActivity.this, "Internet is Available", Toast.LENGTH_SHORT).show();
            }
        });
    }

    private void displayConnectionMessage() {
        runOnUiThread(new Runnable() {
            @Override
            public void run() {
                NetworkUtils.displayInternetConnectionMessage(MainActivity.this);
            }
        });
    }