如果你已经在使用lodash库的选择方法。

var obj = { 'a': 1, 'b': '2', 'c': 3 };

_.pick(object, ['a', 'c']);

// => { 'a': 1, 'c': 3 }

https://lodash.com/docs/4.17.10#pick

值得注意的是，Zod模式在默认情况下会删除未知属性。如果您已经在使用Zod，那么它很可能适合您的开发过程。

https://github.com/colinhacks/zod

import { z } from "zod";

// muppet schema
const muppet = z.object({
  color: z.string(),
  annoying: z.boolean(),
  height: z.string(),
  meta: z.object({ one: z.string(), two: z.string() }),
});

// TypeScript type if you want it
type TMuppet = z.infer<typeof muppet>;

// elmo example
const elmo: TMuppet = {
  color: "red",
  annoying: true,
  height: "unknown",
  meta: { one: "1", two: "2" },
};

// get a subset of the schema (another schema) if you want
const subset = muppet.pick({ color: true, height: true });

// parsing removes unknown properties by default
subset.parse(elmo); // { color: 'red', height: 'unknown' }

将参数转换为数组 使用Array.forEach()来选择属性 Object.prototype.pick = function(…args) { Var obj = {}; arg游戏。forEach(k => obj[k] = this[k]) 返回obj ｝ Var a = {0:"a"，1:"b"，2:"c"} var b = a.pick(' 1 ', ' 2 ') / /输出将{1:“b”,2:“c”}

两种Array.prototype.reduce:

const selectable = {a: null, b: null};
const v = {a: true, b: 'yes', c: 4};

const r = Object.keys(selectable).reduce((a, b) => {
  return (a[b] = v[b]), a;
}, {});

console.log(r);

这个答案使用了神奇的逗号运算符: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Comma_Operator

如果你想要更花哨，这个更紧凑:

const r = Object.keys(selectable).reduce((a, b) => (a[b] = v[b], a), {});

把所有这些放到一个可重用的函数中:

const getSelectable = function (selectable, original) {
  return Object.keys(selectable).reduce((a, b) => (a[b] = original[b], a), {})
};

const r = getSelectable(selectable, v);
console.log(r);

我建议看看Lodash;它有很多实用函数。

例如，pick()就是你要找的东西:

var subset = _.pick(elmo, ['color', 'height']);

小提琴

对象数组

const aListOfObjects = [{
    prop1: 50,
    prop2: "Nothing",
    prop3: "hello",
    prop4: "What's up",
  },
  {
    prop1: 88,
    prop2: "Whatever",
    prop3: "world",
    prop4: "You get it",
  },
]

创建一个或多个对象的子集可以通过这种方式解构对象来实现。

const sections = aListOfObjects.map(({prop1, prop2}) => ({prop1, prop2}));