我想获得一个日期对象,它比另一个日期对象晚30分钟。我如何用JavaScript做到这一点?
当前回答
var d1 = new Date (),
d2 = new Date ( d1 );
d2.setMinutes ( d1.getMinutes() + 30 );
alert ( d2 );
其他回答
新日期() var newDateObj =新日期(); (+ 30 * 60 * 1000); 游戏机。log (newDateObj);
您应该获取当前日期的值以获得日期(ms),并向其添加(30 * 60 *1000)。现在你有(当前日期+ 30分钟)ms
console.log('with ms', Date.now() + (30 * 60 * 1000)) console.log('new Date', new Date(Date.now() + (30 * 60 * 1000)))
以下是ES6版本:
let getTimeAfter30Mins = () => {
let timeAfter30Mins = new Date();
timeAfter30Mins = new Date(timeAfter30Mins.setMinutes(timeAfter30Mins.getMinutes() + 30));
};
这样称呼它:
getTimeAfter30Mins();
也许像这样?
var d = new Date(); var v = new Date(); v.setMinutes (d.getMinutes () + 30); console.log (v)
使用已知的现有库来处理处理时间计算所涉及的异常。我现在最喜欢的是moment.js。
<script src="//cdnjs.cloudflare.com/ajax/libs/moment.js/2.13.0/moment.js"></script>
<script>
var now = moment(); // get "now"
console.log(now.toDate()); // show original date
var thirty = moment(now).add(30,"minutes"); // clone "now" object and add 30 minutes, taking into account weirdness like crossing DST boundries or leap-days, -minutes, -seconds.
console.log(thirty.toDate()); // show new date
</script>