var myDate= new Date();
var MyNewDate = new Date 
(myDate.getFullYear(),myDate.getMonth(),myDate.getDate(),myDate.getMinutes()+10,01,01)

事情就是这么简单;

let initial_date = new Date;
let added30Min = new Date(initial_date.getTime() + (30*60*1000));

其他解决方案:

var dateAv = new Date();
var endTime = new Date(dateAv.getFullYear(), dateAv.getMonth(), dateAv.getDate(), dateAv.getHours(), dateAv.getMinutes() + 30);
          

下面是我的一句话:

console.log('time: '， new Date(new Date().valueOf() + 60000))

也许像这样?

var d = new Date(); var v = new Date(); v.setMinutes (d.getMinutes () + 30); console.log (v)

新日期() var newDateObj =新日期(); (+ 30 * 60 * 1000); 游戏机。log (newDateObj);