您应该获取当前日期的值以获得日期(ms)，并向其添加(30 * 60 *1000)。现在你有(当前日期+ 30分钟)ms

console.log('with ms'， Date.now() + (30 * 60 * 1000)) console.log('new Date'， new Date(Date.now() + (30 * 60 * 1000)))

新日期() var newDateObj =新日期(); (+ 30 * 60 * 1000); 游戏机。log (newDateObj);

最简单的解决方法是认识到在javascript中日期只是数字。它开始于1969年12月31日星期三18:00:00 GMT-0600 (CST)。每1代表一毫秒。您可以通过获取值并使用该值实例化一个新日期来增加或减少毫秒数。用这种思维，你很容易就能搞定。

const minutesToAdjust = 10;
const millisecondsPerMinute = 60000;
const originalDate = new Date('11/20/2017 10:00 AM');
const modifiedDate1 = new Date(originalDate.valueOf() - (minutesToAdjust * millisecondsPerMinute));
const modifiedDate2 = new Date(originalDate.valueOf() + (minutesToAdjust * millisecondsPerMinute));

console.log(originalDate); // Mon Nov 20 2017 10:00:00 GMT-0600 (CST)
console.log(modifiedDate1); // Mon Nov 20 2017 09:50:00 GMT-0600 (CST)
console.log(modifiedDate2); // Mon Nov 20 2017 10:10:00 GMT-0600 (CST)

var add_minutes =  function (dt, minutes) {
return new Date(dt.getTime() + minutes*60000);
}
 console.log(add_minutes(new Date(2014,10,2), 30).toString());

对于像我这样的懒人:

Kip的答案(从上面)在coffeescript中，使用“enum”，并对同一对象进行操作:

Date.UNIT =
  YEAR: 0
  QUARTER: 1
  MONTH: 2
  WEEK: 3
  DAY: 4
  HOUR: 5
  MINUTE: 6
  SECOND: 7
Date::add = (unit, quantity) ->
  switch unit
    when Date.UNIT.YEAR then @setFullYear(@getFullYear() + quantity)
    when Date.UNIT.QUARTER then @setMonth(@getMonth() + (3 * quantity))
    when Date.UNIT.MONTH then @setMonth(@getMonth() + quantity)
    when Date.UNIT.WEEK then @setDate(@getDate() + (7 * quantity))
    when Date.UNIT.DAY then @setDate(@getDate() + quantity)
    when Date.UNIT.HOUR then @setTime(@getTime() + (3600000 * quantity))
    when Date.UNIT.MINUTE then @setTime(@getTime() + (60000 * quantity))
    when Date.UNIT.SECOND then @setTime(@getTime() + (1000 * quantity))
    else throw new Error "Unrecognized unit provided"
  @ # for chaining

其他解决方案:

var dateAv = new Date();
var endTime = new Date(dateAv.getFullYear(), dateAv.getMonth(), dateAv.getDate(), dateAv.getHours(), dateAv.getMinutes() + 30);