let d = new Date();
d.setMinutes(d.getMinutes() + 30);

// console.log(d)

其他解决方案:

var dateAv = new Date();
var endTime = new Date(dateAv.getFullYear(), dateAv.getMonth(), dateAv.getDate(), dateAv.getHours(), dateAv.getMinutes() + 30);
          

const MINUTE = 60 * 1000;
new Date(Date.parse(yourDate) + numOfMins * MINUTE)

新日期() var newDateObj =新日期(); (+ 30 * 60 * 1000); 游戏机。log (newDateObj);

也许像这样?

var d = new Date(); var v = new Date(); v.setMinutes (d.getMinutes () + 30); console.log (v)

var d1 = new Date (),
    d2 = new Date ( d1 );
d2.setMinutes ( d1.getMinutes() + 30 );
alert ( d2 );