我想获得一个日期对象,它比另一个日期对象晚30分钟。我如何用JavaScript做到这一点?


当前回答

var add_minutes =  function (dt, minutes) {
return new Date(dt.getTime() + minutes*60000);
}
 console.log(add_minutes(new Date(2014,10,2), 30).toString());

其他回答

最简单的解决方法是认识到在javascript中日期只是数字。它开始于1969年12月31日星期三18:00:00 GMT-0600 (CST)。每1代表一毫秒。您可以通过获取值并使用该值实例化一个新日期来增加或减少毫秒数。用这种思维,你很容易就能搞定。

const minutesToAdjust = 10;
const millisecondsPerMinute = 60000;
const originalDate = new Date('11/20/2017 10:00 AM');
const modifiedDate1 = new Date(originalDate.valueOf() - (minutesToAdjust * millisecondsPerMinute));
const modifiedDate2 = new Date(originalDate.valueOf() + (minutesToAdjust * millisecondsPerMinute));

console.log(originalDate); // Mon Nov 20 2017 10:00:00 GMT-0600 (CST)
console.log(modifiedDate1); // Mon Nov 20 2017 09:50:00 GMT-0600 (CST)
console.log(modifiedDate2); // Mon Nov 20 2017 10:10:00 GMT-0600 (CST)

使用已知的现有库来处理处理时间计算所涉及的异常。我现在最喜欢的是moment.js。

<script src="//cdnjs.cloudflare.com/ajax/libs/moment.js/2.13.0/moment.js"></script>
<script>
 var now = moment(); // get "now"
 console.log(now.toDate()); // show original date
 var thirty = moment(now).add(30,"minutes"); // clone "now" object and add 30 minutes, taking into account weirdness like crossing DST boundries or leap-days, -minutes, -seconds.
 console.log(thirty.toDate()); // show new date
</script>

事情就是这么简单;

let initial_date = new Date;
let added30Min = new Date(initial_date.getTime() + (30*60*1000));

简单地,你可以在momnet库中使用这段代码:

console.log(moment(moment()).add(30,"minutes").format('MM/DD/YYYY hh:mm:ss'));

你可以这样做:

let 30tyminutes = 30 * 60 * 1000;//将30分钟转换为毫秒 let date1 = new Date(); let date2 = new Date(date1.getTime() + 30tyminutes); console.log (date1); console.log (date2);