严格相等运算符将告诉您两个对象类型是否相等。然而,是否有一种方法来判断两个对象是否相等,就像Java中的哈希码值一样?
堆栈溢出问题JavaScript中有hashCode函数吗?类似于这个问题,但需要一个更学术的答案。上面的场景说明了为什么有必要有一个,我想知道是否有等效的解决方案。
严格相等运算符将告诉您两个对象类型是否相等。然而,是否有一种方法来判断两个对象是否相等,就像Java中的哈希码值一样?
堆栈溢出问题JavaScript中有hashCode函数吗?类似于这个问题,但需要一个更学术的答案。上面的场景说明了为什么有必要有一个,我想知道是否有等效的解决方案。
当前回答
我之前添加了一个答案,但它不是完美的,但这个将检查对象的相等性
function equalObjects(myObj1, myObj2){ let firstScore = 0; let secondScore = 0; let index=0; let proprtiesArray = []; let valuesArray = []; let firstLength = 0; let secondLength = 0; for (const key in myObj1) { if (myObj1.hasOwnProperty(key)) { firstLength += 1; proprtiesArray.push(key); valuesArray.push(myObj1[key]); firstScore +=1; } } for (const key in myObj2) { if (myObj2.hasOwnProperty(key)) { secondLength += 1; if (valuesArray[index] === myObj2[key] && proprtiesArray[index] === key) { secondScore +=1; } //console.log(myObj[key]); index += 1; } } if (secondScore == firstScore && firstLength === secondLength) { console.log("true", "equal objects"); return true; } else { console.log("false", "not equal objects"); return false; } } equalObjects({'firstName':'Ada','lastName':'Lovelace'},{'firstName':'Ada','lastName':'Lovelace'}); equalObjects({'firstName':'Ada','lastName':'Lovelace'},{'firstName':'Ada','lastName1':'Lovelace'}); equalObjects({'firstName':'Ada','lastName':'Lovelace'},{'firstName':'Ada','lastName':'Lovelace', 'missing': false});
其他回答
这是我的版本。它正在使用new Object。ES5中引入的keys特性以及+、+和+的想法/测试:
function objectEquals(x, y) { 'use strict'; if (x === null || x === undefined || y === null || y === undefined) { return x === y; } // after this just checking type of one would be enough if (x.constructor !== y.constructor) { return false; } // if they are functions, they should exactly refer to same one (because of closures) if (x instanceof Function) { return x === y; } // if they are regexps, they should exactly refer to same one (it is hard to better equality check on current ES) if (x instanceof RegExp) { return x === y; } if (x === y || x.valueOf() === y.valueOf()) { return true; } if (Array.isArray(x) && x.length !== y.length) { return false; } // if they are dates, they must had equal valueOf if (x instanceof Date) { return false; } // if they are strictly equal, they both need to be object at least if (!(x instanceof Object)) { return false; } if (!(y instanceof Object)) { return false; } // recursive object equality check var p = Object.keys(x); return Object.keys(y).every(function (i) { return p.indexOf(i) !== -1; }) && p.every(function (i) { return objectEquals(x[i], y[i]); }); } /////////////////////////////////////////////////////////////// /// The borrowed tests, run them by clicking "Run code snippet" /////////////////////////////////////////////////////////////// var printResult = function (x) { if (x) { document.write('<div style="color: green;">Passed</div>'); } else { document.write('<div style="color: red;">Failed</div>'); } }; var assert = { isTrue: function (x) { printResult(x); }, isFalse: function (x) { printResult(!x); } } assert.isTrue(objectEquals(null,null)); assert.isFalse(objectEquals(null,undefined)); assert.isFalse(objectEquals(/abc/, /abc/)); assert.isFalse(objectEquals(/abc/, /123/)); var r = /abc/; assert.isTrue(objectEquals(r, r)); assert.isTrue(objectEquals("hi","hi")); assert.isTrue(objectEquals(5,5)); assert.isFalse(objectEquals(5,10)); assert.isTrue(objectEquals([],[])); assert.isTrue(objectEquals([1,2],[1,2])); assert.isFalse(objectEquals([1,2],[2,1])); assert.isFalse(objectEquals([1,2],[1,2,3])); assert.isTrue(objectEquals({},{})); assert.isTrue(objectEquals({a:1,b:2},{a:1,b:2})); assert.isTrue(objectEquals({a:1,b:2},{b:2,a:1})); assert.isFalse(objectEquals({a:1,b:2},{a:1,b:3})); assert.isTrue(objectEquals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}},{1:{name:"mhc",age:28}, 2:{name:"arb",age:26}})); assert.isFalse(objectEquals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}},{1:{name:"mhc",age:28}, 2:{name:"arb",age:27}})); Object.prototype.equals = function (obj) { return objectEquals(this, obj); }; var assertFalse = assert.isFalse, assertTrue = assert.isTrue; assertFalse({}.equals(null)); assertFalse({}.equals(undefined)); assertTrue("hi".equals("hi")); assertTrue(new Number(5).equals(5)); assertFalse(new Number(5).equals(10)); assertFalse(new Number(1).equals("1")); assertTrue([].equals([])); assertTrue([1,2].equals([1,2])); assertFalse([1,2].equals([2,1])); assertFalse([1,2].equals([1,2,3])); assertTrue(new Date("2011-03-31").equals(new Date("2011-03-31"))); assertFalse(new Date("2011-03-31").equals(new Date("1970-01-01"))); assertTrue({}.equals({})); assertTrue({a:1,b:2}.equals({a:1,b:2})); assertTrue({a:1,b:2}.equals({b:2,a:1})); assertFalse({a:1,b:2}.equals({a:1,b:3})); assertTrue({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}}.equals({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}})); assertFalse({1:{name:"mhc",age:28}, 2:{name:"arb",age:26}}.equals({1:{name:"mhc",age:28}, 2:{name:"arb",age:27}})); var a = {a: 'text', b:[0,1]}; var b = {a: 'text', b:[0,1]}; var c = {a: 'text', b: 0}; var d = {a: 'text', b: false}; var e = {a: 'text', b:[1,0]}; var i = { a: 'text', c: { b: [1, 0] } }; var j = { a: 'text', c: { b: [1, 0] } }; var k = {a: 'text', b: null}; var l = {a: 'text', b: undefined}; assertTrue(a.equals(b)); assertFalse(a.equals(c)); assertFalse(c.equals(d)); assertFalse(a.equals(e)); assertTrue(i.equals(j)); assertFalse(d.equals(k)); assertFalse(k.equals(l)); // from comments on stackoverflow post assert.isFalse(objectEquals([1, 2, undefined], [1, 2])); assert.isFalse(objectEquals([1, 2, 3], { 0: 1, 1: 2, 2: 3 })); assert.isFalse(objectEquals(new Date(1234), 1234)); // no two different function is equal really, they capture their context variables // so even if they have same toString(), they won't have same functionality var func = function (x) { return true; }; var func2 = function (x) { return true; }; assert.isTrue(objectEquals(func, func)); assert.isFalse(objectEquals(func, func2)); assert.isTrue(objectEquals({ a: { b: func } }, { a: { b: func } })); assert.isFalse(objectEquals({ a: { b: func } }, { a: { b: func2 } }));
我建议不要使用散列或序列化(正如JSON解决方案所建议的那样)。如果需要测试两个对象是否相等,则需要定义相等的含义。这可能是两个对象中的所有数据成员都匹配,也可能是内存位置必须匹配(意味着两个变量在内存中引用同一个对象),或者每个对象中只有一个数据成员必须匹配。
最近我开发了一个对象,它的构造函数在每次创建实例时都会创建一个新的id(从1开始,加1)。该对象有一个isEqual函数,用于将该id值与另一个对象的id值进行比较,如果匹配则返回true。
在这种情况下,我定义“相等”的意思是id值匹配。假设每个实例都有一个唯一的id,这可以用来加强匹配对象也占用相同内存位置的想法。尽管这是不必要的。
这里有很多好的想法!这是我对深度相等的理解。我把它发布在github上,并围绕它写了一些测试。很难涵盖所有可能的情况,有时也没有必要这样做。
我介绍了NaN !== NaN以及循环依赖关系。
https://github.com/ryancat/simple-deep-equal/blob/master/index.js
只是想利用一些es6的特性来贡献我的对象比较版本。它不考虑订单。在将所有if/else转换为三元后,我带来了以下内容:
function areEqual(obj1, obj2) {
return Object.keys(obj1).every(key => {
return obj2.hasOwnProperty(key) ?
typeof obj1[key] === 'object' ?
areEqual(obj1[key], obj2[key]) :
obj1[key] === obj2[key] :
false;
}
)
}
从我的个人库中取出,我经常用它来工作。下面的函数是一个宽大的递归深度等号,它不检查
阶级平等 继承的值 价值观严格平等
我主要用这个来检查我是否得到了对各种API实现的相等的回复。可能会出现实现差异(如字符串与数字)和额外的空值。
它的实现非常简单(如果去掉所有注释的话)
/** Recursively check if both objects are equal in value *** *** This function is designed to use multiple methods from most probable *** (and in most cases) valid, to the more regid and complex method. *** *** One of the main principles behind the various check is that while *** some of the simpler checks such as == or JSON may cause false negatives, *** they do not cause false positives. As such they can be safely run first. *** *** # !Important Note: *** as this function is designed for simplified deep equal checks it is not designed *** for the following *** *** - Class equality, (ClassA().a = 1) maybe valid to (ClassB().b = 1) *** - Inherited values, this actually ignores them *** - Values being strictly equal, "1" is equal to 1 (see the basic equality check on this) *** - Performance across all cases. This is designed for high performance on the *** most probable cases of == / JSON equality. Consider bench testing, if you have *** more 'complex' requirments *** *** @param objA : First object to compare *** @param objB : 2nd object to compare *** @param .... : Any other objects to compare *** *** @returns true if all equals, or false if invalid *** *** @license Copyright by eugene@picoded.com, 2012. *** Licensed under the MIT license: http://opensource.org/licenses/MIT **/ function simpleRecusiveDeepEqual(objA, objB) { // Multiple comparision check //-------------------------------------------- var args = Array.prototype.slice.call(arguments); if(args.length > 2) { for(var a=1; a<args.length; ++a) { if(!simpleRecusiveDeepEqual(args[a-1], args[a])) { return false; } } return true; } else if(args.length < 2) { throw "simpleRecusiveDeepEqual, requires atleast 2 arguments"; } // basic equality check, //-------------------------------------------- // if this succed the 2 basic values is equal, // such as numbers and string. // // or its actually the same object pointer. Bam // // Note that if string and number strictly equal is required // change the equality from ==, to === // if(objA == objB) { return true; } // If a value is a bsic type, and failed above. This fails var basicTypes = ["boolean", "number", "string"]; if( basicTypes.indexOf(typeof objA) >= 0 || basicTypes.indexOf(typeof objB) >= 0 ) { return false; } // JSON equality check, //-------------------------------------------- // this can fail, if the JSON stringify the objects in the wrong order // for example the following may fail, due to different string order: // // JSON.stringify( {a:1, b:2} ) == JSON.stringify( {b:2, a:1} ) // if(JSON.stringify(objA) == JSON.stringify(objB)) { return true; } // Array equality check //-------------------------------------------- // This is performed prior to iteration check, // Without this check the following would have been considered valid // // simpleRecusiveDeepEqual( { 0:1963 }, [1963] ); // // Note that u may remove this segment if this is what is intended // if( Array.isArray(objA) ) { //objA is array, objB is not an array if( !Array.isArray(objB) ) { return false; } } else if( Array.isArray(objB) ) { //objA is not array, objB is an array return false; } // Nested values iteration //-------------------------------------------- // Scan and iterate all the nested values, and check for non equal values recusively // // Note that this does not check against null equality, remove the various "!= null" // if this is required var i; //reuse var to iterate // Check objA values against objB for (i in objA) { //Protect against inherited properties if(objA.hasOwnProperty(i)) { if(objB.hasOwnProperty(i)) { // Check if deep equal is valid if(!simpleRecusiveDeepEqual( objA[i], objB[i] )) { return false; } } else if(objA[i] != null) { //ignore null values in objA, that objB does not have //else fails return false; } } } // Check if objB has additional values, that objA do not, fail if so for (i in objB) { if(objB.hasOwnProperty(i)) { if(objB[i] != null && !objA.hasOwnProperty(i)) { //ignore null values in objB, that objA does not have //else fails return false; } } } // End of all checks //-------------------------------------------- // By reaching here, all iteration scans have been done. // and should have returned false if it failed return true; } // Sanity checking of simpleRecusiveDeepEqual (function() { if( // Basic checks !simpleRecusiveDeepEqual({}, {}) || !simpleRecusiveDeepEqual([], []) || !simpleRecusiveDeepEqual(['a'], ['a']) || // Not strict checks !simpleRecusiveDeepEqual("1", 1) || // Multiple objects check !simpleRecusiveDeepEqual( { a:[1,2] }, { a:[1,2] }, { a:[1,2] } ) || // Ensure distinction between array and object (the following should fail) simpleRecusiveDeepEqual( [1963], { 0:1963 } ) || // Null strict checks simpleRecusiveDeepEqual( 0, null ) || simpleRecusiveDeepEqual( "", null ) || // Last "false" exists to make the various check above easy to comment in/out false ) { alert("FATAL ERROR: simpleRecusiveDeepEqual failed basic checks"); } else { //added this last line, for SO snippet alert on success alert("simpleRecusiveDeepEqual: Passed all checks, Yays!"); } })();