我想在sql 2008上写一个查询,它将报告所有有权访问特定数据库的用户,或数据库中的对象,如表,视图和存储过程,直接或由于角色等。该报告将用于安全审计目的。不确定是否有人有一个查询,将完全满足我的需求,但希望能给我一个好的开始。无论是sql 2008, 2005或2000将做,我可以根据需要转换。
当前回答
CREATE PROCEDURE Get_permission
AS
DECLARE @db_name VARCHAR(200),
@sql_text VARCHAR(max)
SET @sql_text='Create table ##db_name (user_name varchar(max),'
DECLARE db_cursor CURSOR FOR
SELECT name
FROM sys.databases
OPEN db_cursor
FETCH next FROM db_cursor INTO @db_name
WHILE @@FETCH_STATUS = 0
BEGIN
SET @sql_text=@sql_text + @db_name + ' varchar(max),'
FETCH next FROM db_cursor INTO @db_name
END
CLOSE db_cursor
SET @sql_text=@sql_text + 'Server_perm varchar(max))'
EXEC (@sql_text)
DEALLOCATE db_cursor
DECLARE @RoleName VARCHAR(50)
DECLARE @UserName VARCHAR(50)
DECLARE @CMD VARCHAR(1000)
CREATE TABLE #permission
(
user_name VARCHAR(50),
databasename VARCHAR(50),
role VARCHAR(50)
)
DECLARE longspcur CURSOR FOR
SELECT name
FROM sys.server_principals
WHERE type IN ( 'S', 'U', 'G' )
AND principal_id > 4
AND name NOT LIKE '##%'
AND name <> 'NT AUTHORITY\SYSTEM'
AND name <> 'ONDEMAND\Administrator'
AND name NOT LIKE 'steel%'
OPEN longspcur
FETCH next FROM longspcur INTO @UserName
WHILE @@FETCH_STATUS = 0
BEGIN
CREATE TABLE #userroles_kk
(
databasename VARCHAR(50),
role VARCHAR(50)
)
CREATE TABLE #rolemember_kk
(
dbrole VARCHAR(100),
membername VARCHAR(100),
membersid VARBINARY(2048)
)
SET @CMD = 'use ? truncate table #RoleMember_kk insert into #RoleMember_kk exec sp_helprolemember insert into #UserRoles_kk (DatabaseName, Role) select db_name(), dbRole from #RoleMember_kk where MemberName = ''' + @UserName + ''''
EXEC Sp_msforeachdb
@CMD
INSERT INTO #permission
SELECT @UserName 'user',
b.name,
u.role
FROM sys.sysdatabases b
LEFT OUTER JOIN #userroles_kk u
ON u.databasename = b.name --and u.Role='db_owner'
ORDER BY 1
DROP TABLE #userroles_kk;
DROP TABLE #rolemember_kk;
FETCH next FROM longspcur INTO @UserName
END
CLOSE longspcur
DEALLOCATE longspcur
TRUNCATE TABLE ##db_name
DECLARE @d1 VARCHAR(max),
@d2 VARCHAR(max),
@d3 VARCHAR(max),
@ss VARCHAR(max)
DECLARE perm_cur CURSOR FOR
SELECT *
FROM #permission
ORDER BY 2 DESC
OPEN perm_cur
FETCH next FROM perm_cur INTO @d1, @d2, @d3
WHILE @@FETCH_STATUS = 0
BEGIN
IF NOT EXISTS(SELECT 1
FROM ##db_name
WHERE user_name = @d1)
BEGIN
SET @ss='insert into ##db_name(user_name) values ('''
+ @d1 + ''')'
EXEC (@ss)
SET @ss='update ##db_name set ' + @d2 + '=''' + @d3
+ ''' where user_name=''' + @d1 + ''''
EXEC (@ss)
END
ELSE
BEGIN
DECLARE @var NVARCHAR(max),
@ParmDefinition NVARCHAR(max),
@var1 NVARCHAR(max)
SET @var = N'select @var1=' + @d2
+ ' from ##db_name where USER_NAME=''' + @d1
+ '''';
SET @ParmDefinition = N'@var1 nvarchar(300) OUTPUT';
EXECUTE Sp_executesql
@var,
@ParmDefinition,
@var1=@var1 output;
SET @var1=Isnull(@var1, ' ')
SET @var= ' update ##db_name set ' + @d2 + '=''' + @var1 + ' '
+ @d3 + ''' where user_name=''' + @d1 + ''' '
EXEC (@var)
END
FETCH next FROM perm_cur INTO @d1, @d2, @d3
END
CLOSE perm_cur
DEALLOCATE perm_cur
SELECT *
FROM ##db_name
DROP TABLE ##db_name
DROP TABLE #permission
其他回答
如果你想检查访问数据库的特定登录已经使用这个简单的脚本如下所示:
sys。sp_helpogins @LoginNamePattern = '域\登录'——sysname
无法评论已接受的答案,所以我将在这里添加一些评论:
I second Brad on schemas issue. From MS reference sys.objects table contains only schema-scoped objects. So to get info about "higher level" objects (i.e. schemas in our case) you need to use sys.schemas table. For [ObjectType] it's better to use obj.type_desc only for OBJECT_OR_COLUMN permission class. For all other cases use perm.[class_desc] Another type of permission which is not handled so well with this query is IMPERSONATE. To get info about impersonations one should LEFT JOIN with sys.database_principals on perm.major_id = imp.principal_id With my experience it's better to replace sys.login_token with sys.server_principals as it will show also SQL Logins, not only Windows ones One should add 'G' to allowed principal types to allow Windows groups Also, one can exclude users sys and INFORMATION_SCHEMA from resulting table, as these users are used only for service
我将发布第一个带有所有建议修复的脚本,其他部分也应该被更改:
SELECT
[UserName] = ulogin.[name],
[UserType] = CASE princ.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
WHEN 'G' THEN 'Windows Group'
END,
[DatabaseUserName] = princ.[name],
[Role] = null,
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = CASE perm.[class]
WHEN 1 THEN obj.type_desc -- Schema-contained objects
ELSE perm.[class_desc] -- Higher-level objects
END,
[ObjectName] = CASE perm.[class]
WHEN 1 THEN OBJECT_NAME(perm.major_id) -- General objects
WHEN 3 THEN schem.[name] -- Schemas
WHEN 4 THEN imp.[name] -- Impersonations
END,
[ColumnName] = col.[name]
FROM
--database user
sys.database_principals princ
LEFT JOIN
--Login accounts
sys.server_principals ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
--Table columns
sys.columns col ON col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
LEFT JOIN
sys.schemas schem ON schem.[schema_id] = perm.[major_id]
LEFT JOIN
sys.database_principals imp ON imp.[principal_id] = perm.[major_id]
WHERE
princ.[type] IN ('S','U','G') AND
-- No need for these system accounts
princ.[name] NOT IN ('sys', 'INFORMATION_SCHEMA')
这是我第一次根据安多马的建议回答问题。此查询旨在提供用户直接应用到用户帐户或通过该帐户应用的权限列表 用户拥有的角色。
/*
Security Audit Report
1) List all access provisioned to a sql user or windows user/group directly
2) List all access provisioned to a sql user or windows user/group through a database or application role
3) List all access provisioned to the public role
Columns Returned:
UserName : SQL or Windows/Active Directory user account. This could also be an Active Directory group.
UserType : Value will be either 'SQL User' or 'Windows User'. This reflects the type of user defined for the
SQL Server user account.
DatabaseUserName: Name of the associated user as defined in the database user account. The database user may not be the
same as the server user.
Role : The role name. This will be null if the associated permissions to the object are defined at directly
on the user account, otherwise this will be the name of the role that the user is a member of.
PermissionType : Type of permissions the user/role has on an object. Examples could include CONNECT, EXECUTE, SELECT
DELETE, INSERT, ALTER, CONTROL, TAKE OWNERSHIP, VIEW DEFINITION, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
PermissionState : Reflects the state of the permission type, examples could include GRANT, DENY, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ObjectType : Type of object the user/role is assigned permissions on. Examples could include USER_TABLE,
SQL_SCALAR_FUNCTION, SQL_INLINE_TABLE_VALUED_FUNCTION, SQL_STORED_PROCEDURE, VIEW, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ObjectName : Name of the object that the user/role is assigned permissions on.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ColumnName : Name of the column of the object that the user/role is assigned permissions on. This value
is only populated if the object is a table, view or a table value function.
*/
--List all access provisioned to a sql user or windows user/group directly
SELECT
[UserName] = CASE princ.[type]
WHEN 'S' THEN princ.[name]
WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
END,
[UserType] = CASE princ.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
END,
[DatabaseUserName] = princ.[name],
[Role] = null,
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM
--database user
sys.database_principals princ
LEFT JOIN
--Login accounts
sys.login_token ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
--Table columns
sys.columns col ON col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
WHERE
princ.[type] in ('S','U')
UNION
--List all access provisioned to a sql user or windows user/group through a database or application role
SELECT
[UserName] = CASE memberprinc.[type]
WHEN 'S' THEN memberprinc.[name]
WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
END,
[UserType] = CASE memberprinc.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
END,
[DatabaseUserName] = memberprinc.[name],
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM
--Role/member associations
sys.database_role_members members
JOIN
--Roles
sys.database_principals roleprinc ON roleprinc.[principal_id] = members.[role_principal_id]
JOIN
--Role members (database users)
sys.database_principals memberprinc ON memberprinc.[principal_id] = members.[member_principal_id]
LEFT JOIN
--Login accounts
sys.login_token ulogin on memberprinc.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
--Table columns
sys.columns col on col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
UNION
--List all access provisioned to the public role, which everyone gets by default
SELECT
[UserName] = '{All Users}',
[UserType] = '{All Users}',
[DatabaseUserName] = '{All Users}',
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM
--Roles
sys.database_principals roleprinc
LEFT JOIN
--Role permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
--Table columns
sys.columns col on col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
JOIN
--All objects
sys.objects obj ON obj.[object_id] = perm.[major_id]
WHERE
--Only roles
roleprinc.[type] = 'R' AND
--Only public role
roleprinc.[name] = 'public' AND
--Only objects of ours, not the MS objects
obj.is_ms_shipped = 0
ORDER BY
princ.[Name],
OBJECT_NAME(perm.major_id),
col.[name],
perm.[permission_name],
perm.[state_desc],
obj.type_desc--perm.[class_desc]
下面是Jeremy提交的最受欢迎的答案,但经过修改,包含了Greg Sipes提到的系统管理员和禁用标志以及log_date_time列。
两全其美?
/*
Source: https://stackoverflow.com/questions/7048839/sql-server-query-to-find-all-permissions-access-for-all-users-in-a-database
Security Audit Report
1) List all access provisioned to a sql user or windows user/group directly
2) List all access provisioned to a sql user or windows user/group through a database or application role
3) List all access provisioned to the public role
Columns Returned:
UserName : SQL or Windows/Active Directory user account. This could also be an Active Directory group.
UserType : Value will be either 'SQL User' or 'Windows User'. This reflects the type of user defined for the
SQL Server user account.
DatabaseUserName: Name of the associated user as defined in the database user account. The database user may not be the
same as the server user.
Role : The role name. This will be null if the associated permissions to the object are defined at directly
on the user account, otherwise this will be the name of the role that the user is a member of.
PermissionType : Type of permissions the user/role has on an object. Examples could include CONNECT, EXECUTE, SELECT
DELETE, INSERT, ALTER, CONTROL, TAKE OWNERSHIP, VIEW DEFINITION, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
PermissionState : Reflects the state of the permission type, examples could include GRANT, DENY, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ObjectType : Type of object the user/role is assigned permissions on. Examples could include USER_TABLE,
SQL_SCALAR_FUNCTION, SQL_INLINE_TABLE_VALUED_FUNCTION, SQL_STORED_PROCEDURE, VIEW, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ObjectName : Name of the object that the user/role is assigned permissions on.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ColumnName : Name of the column of the object that the user/role is assigned permissions on. This value
is only populated if the object is a table, view or a table value function.
*/
--List all access provisioned to a sql user or windows user/group directly
SELECT
[UserName] = CASE princ.[type]
WHEN 'S' THEN princ.[name]
WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
END,
[UserType] = CASE princ.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
END,
[DatabaseUserName] = princ.[name],
[Role] = null,
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name],
sp.is_disabled,
s.sysadmin,
GETDATE() AS [log_date_time]
FROM
--database user
sys.database_principals princ
LEFT JOIN
--Login accounts
sys.login_token ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
--Table columns
sys.columns col ON col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
LEFT JOIN sys.syslogins s ON princ.sid = s.sid
LEFT JOIN sys.server_principals sp ON princ.name = sp.name
WHERE
princ.[type] in ('S','U')
UNION
--List all access provisioned to a sql user or windows user/group through a database or application role
SELECT
[UserName] = CASE memberprinc.[type]
WHEN 'S' THEN memberprinc.[name]
WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
END,
[UserType] = CASE memberprinc.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
END,
[DatabaseUserName] = memberprinc.[name],
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name],
sp.is_disabled,
s.sysadmin,
GETDATE() AS [log_date_time]
FROM
--Role/member associations
sys.database_role_members members
JOIN
--Roles
sys.database_principals roleprinc ON roleprinc.[principal_id] = members.[role_principal_id]
JOIN
--Role members (database users)
sys.database_principals memberprinc ON memberprinc.[principal_id] = members.[member_principal_id]
LEFT JOIN
--Login accounts
sys.login_token ulogin on memberprinc.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
--Table columns
sys.columns col on col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
LEFT JOIN sys.syslogins s ON memberprinc.[sid] = s.sid
LEFT JOIN sys.server_principals sp ON memberprinc.[name] = sp.name
UNION
--List all access provisioned to the public role, which everyone gets by default
SELECT
[UserName] = '{All Users}',
[UserType] = '{All Users}',
[DatabaseUserName] = '{All Users}',
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name],
sp.is_disabled,
s.sysadmin,
GETDATE() AS [log_date_time]
FROM
--Roles
sys.database_principals roleprinc
LEFT JOIN
--Role permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
--Table columns
sys.columns col on col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN sys.syslogins s ON roleprinc.sid = s.sid
LEFT JOIN sys.server_principals sp ON roleprinc.name = sp.name
JOIN
--All objects
sys.objects obj ON obj.[object_id] = perm.[major_id]
WHERE
--Only roles
roleprinc.[type] = 'R' AND
--Only public role
roleprinc.[name] = 'public' AND
--Only objects of ours, not the MS objects
obj.is_ms_shipped = 0
ORDER BY
princ.[Name],
OBJECT_NAME(perm.major_id),
col.[name],
perm.[permission_name],
perm.[state_desc],
obj.type_desc--perm.[class_desc]
以下是Jeremy在2011年8月的查询的完整版本,其中包含了Brad(2011年10月)和iw提出的修改建议。kuchin(2012年5月)注册成立:
Brad:正确的模式[ObjectType]和[ObjectName]。 信息战。kuchin:对于[ObjectType],最好使用obj。type_desc仅用于OBJECT_OR_COLUMN权限类。对于所有其他情况,请使用perm.[class_desc]。 信息战。kuchin:处理IMPERSONATE权限。 信息战。“kuchin”:替换“sys”。Login_token与sys。server_principals,因为它还将显示SQL登录,而不仅仅是Windows登录。 信息战。kuchin:包含Windows组。 信息战。kuchin:排除“sys”和“INFORMATION_SCHEMA”用户。
希望这能为其他人节省一两个小时的生命。:)
/*
Security Audit Report
1) List all access provisioned to a SQL user or Windows user/group directly
2) List all access provisioned to a SQL user or Windows user/group through a database or application role
3) List all access provisioned to the public role
Columns Returned:
UserType : Value will be either 'SQL User', 'Windows User', or 'Windows Group'.
This reflects the type of user/group defined for the SQL Server account.
DatabaseUserName: Name of the associated user as defined in the database user account. The database user may not be the
same as the server user.
LoginName : SQL or Windows/Active Directory user account. This could also be an Active Directory group.
Role : The role name. This will be null if the associated permissions to the object are defined at directly
on the user account, otherwise this will be the name of the role that the user is a member of.
PermissionType : Type of permissions the user/role has on an object. Examples could include CONNECT, EXECUTE, SELECT
DELETE, INSERT, ALTER, CONTROL, TAKE OWNERSHIP, VIEW DEFINITION, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
PermissionState : Reflects the state of the permission type, examples could include GRANT, DENY, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ObjectType : Type of object the user/role is assigned permissions on. Examples could include USER_TABLE,
SQL_SCALAR_FUNCTION, SQL_INLINE_TABLE_VALUED_FUNCTION, SQL_STORED_PROCEDURE, VIEW, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
Schema : Name of the schema the object is in.
ObjectName : Name of the object that the user/role is assigned permissions on.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ColumnName : Name of the column of the object that the user/role is assigned permissions on. This value
is only populated if the object is a table, view or a table value function.
*/
--1) List all access provisioned to a SQL user or Windows user/group directly
SELECT
[UserType] = CASE princ.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
WHEN 'G' THEN 'Windows Group'
END,
[DatabaseUserName] = princ.[name],
[LoginName] = ulogin.[name],
[Role] = NULL,
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = CASE perm.[class]
WHEN 1 THEN obj.[type_desc] -- Schema-contained objects
ELSE perm.[class_desc] -- Higher-level objects
END,
[Schema] = objschem.[name],
[ObjectName] = CASE perm.[class]
WHEN 3 THEN permschem.[name] -- Schemas
WHEN 4 THEN imp.[name] -- Impersonations
ELSE OBJECT_NAME(perm.[major_id]) -- General objects
END,
[ColumnName] = col.[name]
FROM
--Database user
sys.database_principals AS princ
--Login accounts
LEFT JOIN sys.server_principals AS ulogin ON ulogin.[sid] = princ.[sid]
--Permissions
LEFT JOIN sys.database_permissions AS perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN sys.schemas AS permschem ON permschem.[schema_id] = perm.[major_id]
LEFT JOIN sys.objects AS obj ON obj.[object_id] = perm.[major_id]
LEFT JOIN sys.schemas AS objschem ON objschem.[schema_id] = obj.[schema_id]
--Table columns
LEFT JOIN sys.columns AS col ON col.[object_id] = perm.[major_id]
AND col.[column_id] = perm.[minor_id]
--Impersonations
LEFT JOIN sys.database_principals AS imp ON imp.[principal_id] = perm.[major_id]
WHERE
princ.[type] IN ('S','U','G')
-- No need for these system accounts
AND princ.[name] NOT IN ('sys', 'INFORMATION_SCHEMA')
UNION
--2) List all access provisioned to a SQL user or Windows user/group through a database or application role
SELECT
[UserType] = CASE membprinc.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
WHEN 'G' THEN 'Windows Group'
END,
[DatabaseUserName] = membprinc.[name],
[LoginName] = ulogin.[name],
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = CASE perm.[class]
WHEN 1 THEN obj.[type_desc] -- Schema-contained objects
ELSE perm.[class_desc] -- Higher-level objects
END,
[Schema] = objschem.[name],
[ObjectName] = CASE perm.[class]
WHEN 3 THEN permschem.[name] -- Schemas
WHEN 4 THEN imp.[name] -- Impersonations
ELSE OBJECT_NAME(perm.[major_id]) -- General objects
END,
[ColumnName] = col.[name]
FROM
--Role/member associations
sys.database_role_members AS members
--Roles
JOIN sys.database_principals AS roleprinc ON roleprinc.[principal_id] = members.[role_principal_id]
--Role members (database users)
JOIN sys.database_principals AS membprinc ON membprinc.[principal_id] = members.[member_principal_id]
--Login accounts
LEFT JOIN sys.server_principals AS ulogin ON ulogin.[sid] = membprinc.[sid]
--Permissions
LEFT JOIN sys.database_permissions AS perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN sys.schemas AS permschem ON permschem.[schema_id] = perm.[major_id]
LEFT JOIN sys.objects AS obj ON obj.[object_id] = perm.[major_id]
LEFT JOIN sys.schemas AS objschem ON objschem.[schema_id] = obj.[schema_id]
--Table columns
LEFT JOIN sys.columns AS col ON col.[object_id] = perm.[major_id]
AND col.[column_id] = perm.[minor_id]
--Impersonations
LEFT JOIN sys.database_principals AS imp ON imp.[principal_id] = perm.[major_id]
WHERE
membprinc.[type] IN ('S','U','G')
-- No need for these system accounts
AND membprinc.[name] NOT IN ('sys', 'INFORMATION_SCHEMA')
UNION
--3) List all access provisioned to the public role, which everyone gets by default
SELECT
[UserType] = '{All Users}',
[DatabaseUserName] = '{All Users}',
[LoginName] = '{All Users}',
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = CASE perm.[class]
WHEN 1 THEN obj.[type_desc] -- Schema-contained objects
ELSE perm.[class_desc] -- Higher-level objects
END,
[Schema] = objschem.[name],
[ObjectName] = CASE perm.[class]
WHEN 3 THEN permschem.[name] -- Schemas
WHEN 4 THEN imp.[name] -- Impersonations
ELSE OBJECT_NAME(perm.[major_id]) -- General objects
END,
[ColumnName] = col.[name]
FROM
--Roles
sys.database_principals AS roleprinc
--Role permissions
LEFT JOIN sys.database_permissions AS perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN sys.schemas AS permschem ON permschem.[schema_id] = perm.[major_id]
--All objects
JOIN sys.objects AS obj ON obj.[object_id] = perm.[major_id]
LEFT JOIN sys.schemas AS objschem ON objschem.[schema_id] = obj.[schema_id]
--Table columns
LEFT JOIN sys.columns AS col ON col.[object_id] = perm.[major_id]
AND col.[column_id] = perm.[minor_id]
--Impersonations
LEFT JOIN sys.database_principals AS imp ON imp.[principal_id] = perm.[major_id]
WHERE
roleprinc.[type] = 'R'
AND roleprinc.[name] = 'public'
AND obj.[is_ms_shipped] = 0
ORDER BY
[UserType],
[DatabaseUserName],
[LoginName],
[Role],
[Schema],
[ObjectName],
[ColumnName],
[PermissionType],
[PermissionState],
[ObjectType]
推荐文章
- 如何检查SQL Server文本列是否为空?
- 如何创建一个SQL Server函数“连接”多行从一个子查询到一个单独的分隔字段?
- 在SQL中更新多个列
- 如何删除表中特定列的第一个字符?
- 等价的限制和偏移SQL Server?
- 如何从SQL Server中的字符串中剥离所有非字母字符?
- PostgreSQL:角色不允许登录
- 为什么我不能在DELETE语句中使用别名?
- 在SQL Server Management Studio中保存带有标题的结果
- 多语句表值函数vs内联表值函数
- NOLOCK提示在SELECT语句中的作用
- SQL OVER()子句-它什么时候有用,为什么有用?
- 检查SQL Server登录是否已经存在
- 我如何使用ROW_NUMBER()?
- 如何检查表上持有哪些锁