很棒的脚本Jeremy和贡献者!谢谢!

我有很多用户，所以为所有用户运行这个程序简直是一场噩梦。我不能添加评论，所以我发布了整个脚本的变化。我添加了一个变量+ where子句，这样我就可以搜索用户名中匹配最多5个字符的任何内容(或当留空时所有用户)。没什么特别的，但我认为在某些用例中会有帮助。

DECLARE @p_userName NVARCHAR(5) = 'UName' -- Specify up to five characters here (or none for all users)

/*
Security Audit Report
1) List all access provisioned to a sql user or windows user/group directly 
2) List all access provisioned to a sql user or windows user/group through a database or application role
3) List all access provisioned to the public role

Columns Returned:
UserName        : SQL or Windows/Active Directory user cccount.  This could also be an            Active Directory group.
UserType        : Value will be either 'SQL User' or 'Windows User'.  This reflects the type of user defined for the  SQL Server user account.
DatabaseUserName: Name of the associated user as defined in the database user account.  The database user may not be the same as the server user.
Role            : The role name.  This will be null if the associated permissions to the object are defined at directly on the user account, otherwise this will be the name of the role that the user is a member of.
PermissionType  : Type of permissions the user/role has on an object. Examples could include CONNECT, EXECUTE, SELECT, DELETE, INSERT, ALTER, CONTROL, TAKE OWNERSHIP, VIEW DEFINITION, etc. This value may not be populated for all roles.  Some built in roles have implicit permission definitions.
PermissionState : Reflects the state of the permission type, examples could include GRANT, DENY, etc. This value may not be populated for all roles.  Some built in roles have implicit permission definitions.
ObjectType      : Type of object the user/role is assigned permissions on.  Examples could include USER_TABLE, SQL_SCALAR_FUNCTION, SQL_INLINE_TABLE_VALUED_FUNCTION, SQL_STORED_PROCEDURE, VIEW, etc. This value may not be populated for all roles.  Some built in roles have implicit permission definitions.          
ObjectName      : Name of the object that the user/role is assigned permissions on. This value may not be populated for all roles.  Some built in roles have implicit permission definitions.
ColumnName      : Name of the column of the object that the user/role is assigned permissions on. This value is only populated if the object is a table, view or a table value function. 

*/

DECLARE @userName NVARCHAR(4) = @p_UserName + '%'
--List all access provisioned to a sql user or windows user/group directly 

SELECT  
[UserName] = CASE princ.[type] 
                WHEN 'S' THEN princ.[name]
                WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
             END,
[UserType] = CASE princ.[type]
                WHEN 'S' THEN 'SQL User'
                WHEN 'U' THEN 'Windows User'
             END,  
[DatabaseUserName] = princ.[name],       
[Role] = null,      
[PermissionType] = perm.[permission_name],       
[PermissionState] = perm.[state_desc],       
[ObjectType] = obj.type_desc,--perm.[class_desc],       
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM    
--database user
sys.database_principals princ  
LEFT JOIN
--Login accounts
sys.login_token ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN        
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
--Table columns
sys.columns col ON col.[object_id] = perm.major_id 
                AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
WHERE 
princ.[type] in ('S','U')  
AND princ.[name] LIKE @userName  -- Added this line --CSLAGLE
UNION
--List all access provisioned to a sql user or windows user/group through a database or application role
SELECT  
[UserName] = CASE memberprinc.[type] 
                WHEN 'S' THEN memberprinc.[name]
                WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
             END,
[UserType] = CASE memberprinc.[type]
                WHEN 'S' THEN 'SQL User'
                WHEN 'U' THEN 'Windows User'
             END, 
[DatabaseUserName] = memberprinc.[name],   
[Role] = roleprinc.[name],      
[PermissionType] = perm.[permission_name],       
[PermissionState] = perm.[state_desc],       
[ObjectType] = obj.type_desc,--perm.[class_desc],   
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM    
--Role/member associations
sys.database_role_members members
JOIN
--Roles
sys.database_principals roleprinc ON roleprinc.[principal_id] = members.[role_principal_id]
JOIN
--Role members (database users)
sys.database_principals memberprinc ON memberprinc.[principal_id] = members.[member_principal_id]
LEFT JOIN
--Login accounts
sys.login_token ulogin on memberprinc.[sid] = ulogin.[sid]
LEFT JOIN        
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
--Table columns
sys.columns col on col.[object_id] = perm.major_id 
                AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
WHERE memberprinc.[name] LIKE @userName -- Added this line --CSLAGLE
UNION
--List all access provisioned to the public role, which everyone gets by default
SELECT  
[UserName] = '{All Users}', 
[UserType] = '{All Users}', 
[DatabaseUserName] = '{All Users}',       
[Role] = roleprinc.[name],      
[PermissionType] = perm.[permission_name],       
[PermissionState] = perm.[state_desc],       
[ObjectType] = obj.type_desc,--perm.[class_desc],  
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM    
--Roles
sys.database_principals roleprinc
LEFT JOIN        
--Role permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
--Table columns
sys.columns col on col.[object_id] = perm.major_id 
                AND col.[column_id] = perm.[minor_id]                   
JOIN 
--All objects   
sys.objects obj ON obj.[object_id] = perm.[major_id]
WHERE
--Only roles
roleprinc.[type] = 'R' AND
--Only public role
roleprinc.[name] = 'public' AND
--Only objects of ours, not the MS objects
obj.is_ms_shipped = 0
ORDER BY
princ.[Name],
OBJECT_NAME(perm.major_id),
col.[name],
perm.[permission_name],
perm.[state_desc],
obj.type_desc--perm.[class_desc]  

从SQL Server 2005开始，您可以使用系统视图来实现这一点。例如，这个查询列出了数据库中的所有用户及其权限:

select  princ.name
,       princ.type_desc
,       perm.permission_name
,       perm.state_desc
,       perm.class_desc
,       object_name(perm.major_id)
from    sys.database_principals princ
left join
        sys.database_permissions perm
on      perm.grantee_principal_id = princ.principal_id

请注意，用户也可以通过角色拥有权限。例如，db_data_reader角色授予对大多数对象的选择权限。

这是我第一次根据安多马的建议回答问题。此查询旨在提供用户直接应用到用户帐户或通过该帐户应用的权限列表 用户拥有的角色。

/*
Security Audit Report
1) List all access provisioned to a sql user or windows user/group directly 
2) List all access provisioned to a sql user or windows user/group through a database or application role
3) List all access provisioned to the public role

Columns Returned:
UserName        : SQL or Windows/Active Directory user account.  This could also be an Active Directory group.
UserType        : Value will be either 'SQL User' or 'Windows User'.  This reflects the type of user defined for the 
                  SQL Server user account.
DatabaseUserName: Name of the associated user as defined in the database user account.  The database user may not be the
                  same as the server user.
Role            : The role name.  This will be null if the associated permissions to the object are defined at directly
                  on the user account, otherwise this will be the name of the role that the user is a member of.
PermissionType  : Type of permissions the user/role has on an object. Examples could include CONNECT, EXECUTE, SELECT
                  DELETE, INSERT, ALTER, CONTROL, TAKE OWNERSHIP, VIEW DEFINITION, etc.
                  This value may not be populated for all roles.  Some built in roles have implicit permission
                  definitions.
PermissionState : Reflects the state of the permission type, examples could include GRANT, DENY, etc.
                  This value may not be populated for all roles.  Some built in roles have implicit permission
                  definitions.
ObjectType      : Type of object the user/role is assigned permissions on.  Examples could include USER_TABLE, 
                  SQL_SCALAR_FUNCTION, SQL_INLINE_TABLE_VALUED_FUNCTION, SQL_STORED_PROCEDURE, VIEW, etc.   
                  This value may not be populated for all roles.  Some built in roles have implicit permission
                  definitions.          
ObjectName      : Name of the object that the user/role is assigned permissions on.  
                  This value may not be populated for all roles.  Some built in roles have implicit permission
                  definitions.
ColumnName      : Name of the column of the object that the user/role is assigned permissions on. This value
                  is only populated if the object is a table, view or a table value function.                 
*/

--List all access provisioned to a sql user or windows user/group directly 
SELECT  
    [UserName] = CASE princ.[type] 
                    WHEN 'S' THEN princ.[name]
                    WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
                 END,
    [UserType] = CASE princ.[type]
                    WHEN 'S' THEN 'SQL User'
                    WHEN 'U' THEN 'Windows User'
                 END,  
    [DatabaseUserName] = princ.[name],       
    [Role] = null,      
    [PermissionType] = perm.[permission_name],       
    [PermissionState] = perm.[state_desc],       
    [ObjectType] = obj.type_desc,--perm.[class_desc],       
    [ObjectName] = OBJECT_NAME(perm.major_id),
    [ColumnName] = col.[name]
FROM    
    --database user
    sys.database_principals princ  
LEFT JOIN
    --Login accounts
    sys.login_token ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN        
    --Permissions
    sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
    --Table columns
    sys.columns col ON col.[object_id] = perm.major_id 
                    AND col.[column_id] = perm.[minor_id]
LEFT JOIN
    sys.objects obj ON perm.[major_id] = obj.[object_id]
WHERE 
    princ.[type] in ('S','U')
UNION
--List all access provisioned to a sql user or windows user/group through a database or application role
SELECT  
    [UserName] = CASE memberprinc.[type] 
                    WHEN 'S' THEN memberprinc.[name]
                    WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
                 END,
    [UserType] = CASE memberprinc.[type]
                    WHEN 'S' THEN 'SQL User'
                    WHEN 'U' THEN 'Windows User'
                 END, 
    [DatabaseUserName] = memberprinc.[name],   
    [Role] = roleprinc.[name],      
    [PermissionType] = perm.[permission_name],       
    [PermissionState] = perm.[state_desc],       
    [ObjectType] = obj.type_desc,--perm.[class_desc],   
    [ObjectName] = OBJECT_NAME(perm.major_id),
    [ColumnName] = col.[name]
FROM    
    --Role/member associations
    sys.database_role_members members
JOIN
    --Roles
    sys.database_principals roleprinc ON roleprinc.[principal_id] = members.[role_principal_id]
JOIN
    --Role members (database users)
    sys.database_principals memberprinc ON memberprinc.[principal_id] = members.[member_principal_id]
LEFT JOIN
    --Login accounts
    sys.login_token ulogin on memberprinc.[sid] = ulogin.[sid]
LEFT JOIN        
    --Permissions
    sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
    --Table columns
    sys.columns col on col.[object_id] = perm.major_id 
                    AND col.[column_id] = perm.[minor_id]
LEFT JOIN
    sys.objects obj ON perm.[major_id] = obj.[object_id]
UNION
--List all access provisioned to the public role, which everyone gets by default
SELECT  
    [UserName] = '{All Users}',
    [UserType] = '{All Users}', 
    [DatabaseUserName] = '{All Users}',       
    [Role] = roleprinc.[name],      
    [PermissionType] = perm.[permission_name],       
    [PermissionState] = perm.[state_desc],       
    [ObjectType] = obj.type_desc,--perm.[class_desc],  
    [ObjectName] = OBJECT_NAME(perm.major_id),
    [ColumnName] = col.[name]
FROM    
    --Roles
    sys.database_principals roleprinc
LEFT JOIN        
    --Role permissions
    sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
    --Table columns
    sys.columns col on col.[object_id] = perm.major_id 
                    AND col.[column_id] = perm.[minor_id]                   
JOIN 
    --All objects   
    sys.objects obj ON obj.[object_id] = perm.[major_id]
WHERE
    --Only roles
    roleprinc.[type] = 'R' AND
    --Only public role
    roleprinc.[name] = 'public' AND
    --Only objects of ours, not the MS objects
    obj.is_ms_shipped = 0
ORDER BY
    princ.[Name],
    OBJECT_NAME(perm.major_id),
    col.[name],
    perm.[permission_name],
    perm.[state_desc],
    obj.type_desc--perm.[class_desc] 

一个简单的查询，只显示你是否是系统管理员:

IF IS_SRVROLEMEMBER ('sysadmin') = 1  
   print 'Current user''s login is a member of the sysadmin role'  
ELSE IF IS_SRVROLEMEMBER ('sysadmin') = 0  
   print 'Current user''s login is NOT a member of the sysadmin role'  
ELSE IF IS_SRVROLEMEMBER ('sysadmin') IS NULL  
   print 'ERROR: The server role specified is not valid.';

非常感谢出色的审计脚本。

我强烈建议审计用户使用很棒的Kenneth Fisher (b | t)存储过程:

sp_DBPermissions sp_SrvPermissions

无法评论已接受的答案，所以我将在这里添加一些评论:

I second Brad on schemas issue. From MS reference sys.objects table contains only schema-scoped objects. So to get info about "higher level" objects (i.e. schemas in our case) you need to use sys.schemas table. For [ObjectType] it's better to use obj.type_desc only for OBJECT_OR_COLUMN permission class. For all other cases use perm.[class_desc] Another type of permission which is not handled so well with this query is IMPERSONATE. To get info about impersonations one should LEFT JOIN with sys.database_principals on perm.major_id = imp.principal_id With my experience it's better to replace sys.login_token with sys.server_principals as it will show also SQL Logins, not only Windows ones One should add 'G' to allowed principal types to allow Windows groups Also, one can exclude users sys and INFORMATION_SCHEMA from resulting table, as these users are used only for service

我将发布第一个带有所有建议修复的脚本，其他部分也应该被更改:

SELECT  
    [UserName] = ulogin.[name],
    [UserType] = CASE princ.[type]
                    WHEN 'S' THEN 'SQL User'
                    WHEN 'U' THEN 'Windows User'
                    WHEN 'G' THEN 'Windows Group'
                 END,  
    [DatabaseUserName] = princ.[name],       
    [Role] = null,      
    [PermissionType] = perm.[permission_name],       
    [PermissionState] = perm.[state_desc],       
    [ObjectType] = CASE perm.[class] 
                        WHEN 1 THEN obj.type_desc               -- Schema-contained objects
                        ELSE perm.[class_desc]                  -- Higher-level objects
                   END,       
    [ObjectName] = CASE perm.[class] 
                        WHEN 1 THEN OBJECT_NAME(perm.major_id)  -- General objects
                        WHEN 3 THEN schem.[name]                -- Schemas
                        WHEN 4 THEN imp.[name]                  -- Impersonations
                   END,
    [ColumnName] = col.[name]
FROM    
    --database user
    sys.database_principals princ  
LEFT JOIN
    --Login accounts
    sys.server_principals ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN        
    --Permissions
    sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
    --Table columns
    sys.columns col ON col.[object_id] = perm.major_id 
                    AND col.[column_id] = perm.[minor_id]
LEFT JOIN
    sys.objects obj ON perm.[major_id] = obj.[object_id]
LEFT JOIN
    sys.schemas schem ON schem.[schema_id] = perm.[major_id]
LEFT JOIN
    sys.database_principals imp ON imp.[principal_id] = perm.[major_id]
WHERE 
    princ.[type] IN ('S','U','G') AND
    -- No need for these system accounts
    princ.[name] NOT IN ('sys', 'INFORMATION_SCHEMA')