我想在sql 2008上写一个查询,它将报告所有有权访问特定数据库的用户,或数据库中的对象,如表,视图和存储过程,直接或由于角色等。该报告将用于安全审计目的。不确定是否有人有一个查询,将完全满足我的需求,但希望能给我一个好的开始。无论是sql 2008, 2005或2000将做,我可以根据需要转换。
当前回答
由于低代表不能与此回复的人要求在多个数据库/SQL服务器上运行此。
创建一个注册的服务器组,并查询他们所有的我们以下和只是游标通过数据库:
--Make sure all ' are doubled within the SQL string.
DECLARE @dbname VARCHAR(50)
DECLARE @statement NVARCHAR(max)
DECLARE db_cursor CURSOR
LOCAL FAST_FORWARD
FOR
SELECT name
FROM MASTER.dbo.sysdatabases
where name like '%DBName%'
OPEN db_cursor
FETCH NEXT FROM db_cursor INTO @dbname
WHILE @@FETCH_STATUS = 0
BEGIN
SELECT @statement = 'use '+@dbname +';'+ '
/*
Security Audit Report
1) List all access provisioned to a SQL user or Windows user/group directly
2) List all access provisioned to a SQL user or Windows user/group through a database or application role
3) List all access provisioned to the public role
Columns Returned:
UserType : Value will be either ''SQL User'', ''Windows User'', or ''Windows Group''.
This reflects the type of user/group defined for the SQL Server account.
DatabaseUserName: Name of the associated user as defined in the database user account. The database user may not be the
same as the server user.
LoginName : SQL or Windows/Active Directory user account. This could also be an Active Directory group.
Role : The role name. This will be null if the associated permissions to the object are defined at directly
on the user account, otherwise this will be the name of the role that the user is a member of.
PermissionType : Type of permissions the user/role has on an object. Examples could include CONNECT, EXECUTE, SELECT
DELETE, INSERT, ALTER, CONTROL, TAKE OWNERSHIP, VIEW DEFINITION, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
PermissionState : Reflects the state of the permission type, examples could include GRANT, DENY, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ObjectType : Type of object the user/role is assigned permissions on. Examples could include USER_TABLE,
SQL_SCALAR_FUNCTION, SQL_INLINE_TABLE_VALUED_FUNCTION, SQL_STORED_PROCEDURE, VIEW, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
Schema : Name of the schema the object is in.
ObjectName : Name of the object that the user/role is assigned permissions on.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ColumnName : Name of the column of the object that the user/role is assigned permissions on. This value
is only populated if the object is a table, view or a table value function.
*/
--1) List all access provisioned to a SQL user or Windows user/group directly
SELECT
[UserType] = CASE princ.[type]
WHEN ''S'' THEN ''SQL User''
WHEN ''U'' THEN ''Windows User''
WHEN ''G'' THEN ''Windows Group''
END,
[DatabaseUserName] = princ.[name],
[LoginName] = ulogin.[name],
[Role] = NULL,
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = CASE perm.[class]
WHEN 1 THEN obj.[type_desc] -- Schema-contained objects
ELSE perm.[class_desc] -- Higher-level objects
END,
[Schema] = objschem.[name],
[ObjectName] = CASE perm.[class]
WHEN 3 THEN permschem.[name] -- Schemas
WHEN 4 THEN imp.[name] -- Impersonations
ELSE OBJECT_NAME(perm.[major_id]) -- General objects
END,
[ColumnName] = col.[name]
FROM
--Database user
sys.database_principals AS princ
--Login accounts
LEFT JOIN sys.server_principals AS ulogin ON ulogin.[sid] = princ.[sid]
--Permissions
LEFT JOIN sys.database_permissions AS perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN sys.schemas AS permschem ON permschem.[schema_id] = perm.[major_id]
LEFT JOIN sys.objects AS obj ON obj.[object_id] = perm.[major_id]
LEFT JOIN sys.schemas AS objschem ON objschem.[schema_id] = obj.[schema_id]
--Table columns
LEFT JOIN sys.columns AS col ON col.[object_id] = perm.[major_id]
AND col.[column_id] = perm.[minor_id]
--Impersonations
LEFT JOIN sys.database_principals AS imp ON imp.[principal_id] = perm.[major_id]
WHERE
princ.[type] IN (''S'',''U'',''G'')
-- No need for these system accounts
AND princ.[name] NOT IN (''sys'', ''INFORMATION_SCHEMA'')
UNION
--2) List all access provisioned to a SQL user or Windows user/group through a database or application role
SELECT
[UserType] = CASE membprinc.[type]
WHEN ''S'' THEN ''SQL User''
WHEN ''U'' THEN ''Windows User''
WHEN ''G'' THEN ''Windows Group''
END,
[DatabaseUserName] = membprinc.[name],
[LoginName] = ulogin.[name],
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = CASE perm.[class]
WHEN 1 THEN obj.[type_desc] -- Schema-contained objects
ELSE perm.[class_desc] -- Higher-level objects
END,
[Schema] = objschem.[name],
[ObjectName] = CASE perm.[class]
WHEN 3 THEN permschem.[name] -- Schemas
WHEN 4 THEN imp.[name] -- Impersonations
ELSE OBJECT_NAME(perm.[major_id]) -- General objects
END,
[ColumnName] = col.[name]
FROM
--Role/member associations
sys.database_role_members AS members
--Roles
JOIN sys.database_principals AS roleprinc ON roleprinc.[principal_id] = members.[role_principal_id]
--Role members (database users)
JOIN sys.database_principals AS membprinc ON membprinc.[principal_id] = members.[member_principal_id]
--Login accounts
LEFT JOIN sys.server_principals AS ulogin ON ulogin.[sid] = membprinc.[sid]
--Permissions
LEFT JOIN sys.database_permissions AS perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN sys.schemas AS permschem ON permschem.[schema_id] = perm.[major_id]
LEFT JOIN sys.objects AS obj ON obj.[object_id] = perm.[major_id]
LEFT JOIN sys.schemas AS objschem ON objschem.[schema_id] = obj.[schema_id]
--Table columns
LEFT JOIN sys.columns AS col ON col.[object_id] = perm.[major_id]
AND col.[column_id] = perm.[minor_id]
--Impersonations
LEFT JOIN sys.database_principals AS imp ON imp.[principal_id] = perm.[major_id]
WHERE
membprinc.[type] IN (''S'',''U'',''G'')
-- No need for these system accounts
AND membprinc.[name] NOT IN (''sys'', ''INFORMATION_SCHEMA'')
UNION
--3) List all access provisioned to the public role, which everyone gets by default
SELECT
[UserType] = ''{All Users}'',
[DatabaseUserName] = ''{All Users}'',
[LoginName] = ''{All Users}'',
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = CASE perm.[class]
WHEN 1 THEN obj.[type_desc] -- Schema-contained objects
ELSE perm.[class_desc] -- Higher-level objects
END,
[Schema] = objschem.[name],
[ObjectName] = CASE perm.[class]
WHEN 3 THEN permschem.[name] -- Schemas
WHEN 4 THEN imp.[name] -- Impersonations
ELSE OBJECT_NAME(perm.[major_id]) -- General objects
END,
[ColumnName] = col.[name]
FROM
--Roles
sys.database_principals AS roleprinc
--Role permissions
LEFT JOIN sys.database_permissions AS perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN sys.schemas AS permschem ON permschem.[schema_id] = perm.[major_id]
--All objects
JOIN sys.objects AS obj ON obj.[object_id] = perm.[major_id]
LEFT JOIN sys.schemas AS objschem ON objschem.[schema_id] = obj.[schema_id]
--Table columns
LEFT JOIN sys.columns AS col ON col.[object_id] = perm.[major_id]
AND col.[column_id] = perm.[minor_id]
--Impersonations
LEFT JOIN sys.database_principals AS imp ON imp.[principal_id] = perm.[major_id]
WHERE
roleprinc.[type] = ''R''
AND roleprinc.[name] = ''public''
AND obj.[is_ms_shipped] = 0
ORDER BY
[UserType],
[DatabaseUserName],
[LoginName],
[Role],
[Schema],
[ObjectName],
[ColumnName],
[PermissionType],
[PermissionState],
[ObjectType]
'
exec sp_executesql @statement
FETCH NEXT FROM db_cursor INTO @dbname
END
CLOSE db_cursor
DEALLOCATE db_cursor
这个帖子极大地帮助了我,谢谢大家!
其他回答
从SQL Server 2005开始,您可以使用系统视图来实现这一点。例如,这个查询列出了数据库中的所有用户及其权限:
select princ.name
, princ.type_desc
, perm.permission_name
, perm.state_desc
, perm.class_desc
, object_name(perm.major_id)
from sys.database_principals princ
left join
sys.database_permissions perm
on perm.grantee_principal_id = princ.principal_id
请注意,用户也可以通过角色拥有权限。例如,db_data_reader角色授予对大多数对象的选择权限。
这是我第一次根据安多马的建议回答问题。此查询旨在提供用户直接应用到用户帐户或通过该帐户应用的权限列表 用户拥有的角色。
/*
Security Audit Report
1) List all access provisioned to a sql user or windows user/group directly
2) List all access provisioned to a sql user or windows user/group through a database or application role
3) List all access provisioned to the public role
Columns Returned:
UserName : SQL or Windows/Active Directory user account. This could also be an Active Directory group.
UserType : Value will be either 'SQL User' or 'Windows User'. This reflects the type of user defined for the
SQL Server user account.
DatabaseUserName: Name of the associated user as defined in the database user account. The database user may not be the
same as the server user.
Role : The role name. This will be null if the associated permissions to the object are defined at directly
on the user account, otherwise this will be the name of the role that the user is a member of.
PermissionType : Type of permissions the user/role has on an object. Examples could include CONNECT, EXECUTE, SELECT
DELETE, INSERT, ALTER, CONTROL, TAKE OWNERSHIP, VIEW DEFINITION, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
PermissionState : Reflects the state of the permission type, examples could include GRANT, DENY, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ObjectType : Type of object the user/role is assigned permissions on. Examples could include USER_TABLE,
SQL_SCALAR_FUNCTION, SQL_INLINE_TABLE_VALUED_FUNCTION, SQL_STORED_PROCEDURE, VIEW, etc.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ObjectName : Name of the object that the user/role is assigned permissions on.
This value may not be populated for all roles. Some built in roles have implicit permission
definitions.
ColumnName : Name of the column of the object that the user/role is assigned permissions on. This value
is only populated if the object is a table, view or a table value function.
*/
--List all access provisioned to a sql user or windows user/group directly
SELECT
[UserName] = CASE princ.[type]
WHEN 'S' THEN princ.[name]
WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
END,
[UserType] = CASE princ.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
END,
[DatabaseUserName] = princ.[name],
[Role] = null,
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM
--database user
sys.database_principals princ
LEFT JOIN
--Login accounts
sys.login_token ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
--Table columns
sys.columns col ON col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
WHERE
princ.[type] in ('S','U')
UNION
--List all access provisioned to a sql user or windows user/group through a database or application role
SELECT
[UserName] = CASE memberprinc.[type]
WHEN 'S' THEN memberprinc.[name]
WHEN 'U' THEN ulogin.[name] COLLATE Latin1_General_CI_AI
END,
[UserType] = CASE memberprinc.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
END,
[DatabaseUserName] = memberprinc.[name],
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM
--Role/member associations
sys.database_role_members members
JOIN
--Roles
sys.database_principals roleprinc ON roleprinc.[principal_id] = members.[role_principal_id]
JOIN
--Role members (database users)
sys.database_principals memberprinc ON memberprinc.[principal_id] = members.[member_principal_id]
LEFT JOIN
--Login accounts
sys.login_token ulogin on memberprinc.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
--Table columns
sys.columns col on col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
UNION
--List all access provisioned to the public role, which everyone gets by default
SELECT
[UserName] = '{All Users}',
[UserType] = '{All Users}',
[DatabaseUserName] = '{All Users}',
[Role] = roleprinc.[name],
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = obj.type_desc,--perm.[class_desc],
[ObjectName] = OBJECT_NAME(perm.major_id),
[ColumnName] = col.[name]
FROM
--Roles
sys.database_principals roleprinc
LEFT JOIN
--Role permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = roleprinc.[principal_id]
LEFT JOIN
--Table columns
sys.columns col on col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
JOIN
--All objects
sys.objects obj ON obj.[object_id] = perm.[major_id]
WHERE
--Only roles
roleprinc.[type] = 'R' AND
--Only public role
roleprinc.[name] = 'public' AND
--Only objects of ours, not the MS objects
obj.is_ms_shipped = 0
ORDER BY
princ.[Name],
OBJECT_NAME(perm.major_id),
col.[name],
perm.[permission_name],
perm.[state_desc],
obj.type_desc--perm.[class_desc]
我尝试了几乎所有这些功能,但很快就注意到缺少一些功能,尤其是系统管理员用户。在我们即将进行的审计中,有这样一个洞会很不好看,所以我想出了这个
USE master
GO
SELECT DISTINCT
p.name AS [loginname] ,
--p.type,
p.type_desc ,
p.is_disabled,
s.sysadmin,
sp.permission_name
FROM sys.server_principals p
INNER JOIN sys.syslogins s ON p.sid = s.sid
INNER JOIN sys.server_permissions sp ON p.principal_id = sp.grantee_principal_id
WHERE p.type_desc IN ('SQL_LOGIN', 'WINDOWS_LOGIN', 'WINDOWS_GROUP')
-- Logins that are not process logins
AND p.name NOT LIKE '##%'
ORDER BY p.name
GO
无法评论已接受的答案,所以我将在这里添加一些评论:
I second Brad on schemas issue. From MS reference sys.objects table contains only schema-scoped objects. So to get info about "higher level" objects (i.e. schemas in our case) you need to use sys.schemas table. For [ObjectType] it's better to use obj.type_desc only for OBJECT_OR_COLUMN permission class. For all other cases use perm.[class_desc] Another type of permission which is not handled so well with this query is IMPERSONATE. To get info about impersonations one should LEFT JOIN with sys.database_principals on perm.major_id = imp.principal_id With my experience it's better to replace sys.login_token with sys.server_principals as it will show also SQL Logins, not only Windows ones One should add 'G' to allowed principal types to allow Windows groups Also, one can exclude users sys and INFORMATION_SCHEMA from resulting table, as these users are used only for service
我将发布第一个带有所有建议修复的脚本,其他部分也应该被更改:
SELECT
[UserName] = ulogin.[name],
[UserType] = CASE princ.[type]
WHEN 'S' THEN 'SQL User'
WHEN 'U' THEN 'Windows User'
WHEN 'G' THEN 'Windows Group'
END,
[DatabaseUserName] = princ.[name],
[Role] = null,
[PermissionType] = perm.[permission_name],
[PermissionState] = perm.[state_desc],
[ObjectType] = CASE perm.[class]
WHEN 1 THEN obj.type_desc -- Schema-contained objects
ELSE perm.[class_desc] -- Higher-level objects
END,
[ObjectName] = CASE perm.[class]
WHEN 1 THEN OBJECT_NAME(perm.major_id) -- General objects
WHEN 3 THEN schem.[name] -- Schemas
WHEN 4 THEN imp.[name] -- Impersonations
END,
[ColumnName] = col.[name]
FROM
--database user
sys.database_principals princ
LEFT JOIN
--Login accounts
sys.server_principals ulogin on princ.[sid] = ulogin.[sid]
LEFT JOIN
--Permissions
sys.database_permissions perm ON perm.[grantee_principal_id] = princ.[principal_id]
LEFT JOIN
--Table columns
sys.columns col ON col.[object_id] = perm.major_id
AND col.[column_id] = perm.[minor_id]
LEFT JOIN
sys.objects obj ON perm.[major_id] = obj.[object_id]
LEFT JOIN
sys.schemas schem ON schem.[schema_id] = perm.[major_id]
LEFT JOIN
sys.database_principals imp ON imp.[principal_id] = perm.[major_id]
WHERE
princ.[type] IN ('S','U','G') AND
-- No need for these system accounts
princ.[name] NOT IN ('sys', 'INFORMATION_SCHEMA')
如果你想检查访问数据库的特定登录已经使用这个简单的脚本如下所示:
sys。sp_helpogins @LoginNamePattern = '域\登录'——sysname
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