Obviously for performance and safety, you'll want to keep the length of a string while you're working with it rather than repeatedly performing strlen or the equivalent on it. However, storing the length in a fixed location just before the string contents is an incredibly bad design. As Jörgen pointed out in the comments on Sanjit's answer, it precludes treating the tail of a string as a string, which for example makes a lot of common operations like path_to_filename or filename_to_extension impossible without allocating new memory (and incurring the possibility of failure and error handling). And then of course there's the issue that nobody can agree how many bytes the string length field should occupy (plenty of bad "Pascal string" languages used 16-bit fields or even 24-bit fields which preclude processing of long strings).

C语言让程序员选择是否/在哪里/如何存储长度的设计更加灵活和强大。当然，程序员必须聪明。C语言惩罚愚蠢的程序崩溃，慢慢停止，或者让你的敌人扎根。

在很多方面，C语言是原始的。我很喜欢。

它比汇编语言高了一步，用一种更容易编写和维护的语言提供了几乎相同的性能。

空结束符很简单，不需要语言的特殊支持。

现在回想起来，似乎并不是那么方便。但我在80年代使用汇编语言，当时它似乎非常方便。我只是认为软件在不断地发展，平台和工具也在不断地变得越来越复杂。

来自马的口

None of BCPL, B, or C supports character data strongly in the language; each treats strings much like vectors of integers and supplements general rules by a few conventions. In both BCPL and B a string literal denotes the address of a static area initialized with the characters of the string, packed into cells. In BCPL, the first packed byte contains the number of characters in the string; in B, there is no count and strings are terminated by a special character, which B spelled *e. This change was made partially to avoid the limitation on the length of a string caused by holding the count in an 8- or 9-bit slot, and partly because maintaining the count seemed, in our experience, less convenient than using a terminator.

Dennis M Ritchie, C语言的开发

我不相信“C没有字符串”的答案。没错，C语言不支持内置的高级类型，但你仍然可以用C语言表示数据结构，这就是字符串。在C语言中，字符串只是一个指针，但这并不意味着前N个字节不能作为长度具有特殊意义。

Windows/COM开发人员将非常熟悉BSTR类型，它就像这样——一个有长度前缀的C字符串，其中实际的字符数据不是从字节0开始的。

因此，使用空终止符的决定似乎只是人们喜欢的，而不是语言的必要。

空终止允许基于快速指针的操作。

懒惰、寄存器节俭和可移植性考虑到任何语言的汇编核心，尤其是C语言，它比汇编高出一步(因此继承了大量汇编遗留代码)。 你会同意null字符在那些ASCII的日子里是无用的，它(可能和EOF控件字符一样好)。

让我们看看伪代码

function readString(string) // 1 parameter: 1 register or 1 stact entries
    pointer=addressOf(string) 
    while(string[pointer]!=CONTROL_CHAR) do
        read(string[pointer])
        increment pointer

共使用1个寄存器

案例2

 function readString(length,string) // 2 parameters: 2 register used or 2 stack entries
     pointer=addressOf(string) 
     while(length>0) do 
         read(string[pointer])
         increment pointer
         decrement length

共使用2个寄存器

这在当时似乎是短视的，但考虑到代码和寄存器的节俭(这在当时是PREMIUM，那时你知道，他们使用穿孔卡)。因此，更快(当处理器速度可以以kHz计)，这个“黑客”是相当不错的，可轻松移植到无寄存器处理器。

为了便于讨论，我将实现2个常见的字符串操作

stringLength(string)
     pointer=addressOf(string)
     while(string[pointer]!=CONTROL_CHAR) do
         increment pointer
     return pointer-addressOf(string)

复杂度O(n)，在大多数情况下PASCAL字符串是O(1)，因为字符串的长度是预先挂起的字符串结构(这也意味着该操作必须在更早的阶段进行)。

concatString(string1,string2)
     length1=stringLength(string1)
     length2=stringLength(string2)
     string3=allocate(string1+string2)
     pointer1=addressOf(string1)
     pointer3=addressOf(string3)
     while(string1[pointer1]!=CONTROL_CHAR) do
         string3[pointer3]=string1[pointer1]
         increment pointer3
         increment pointer1
     pointer2=addressOf(string2)
     while(string2[pointer2]!=CONTROL_CHAR) do
         string3[pointer3]=string2[pointer2]
         increment pointer3
         increment pointer1
     return string3

复杂度O(n)和预先设置字符串长度不会改变操作的复杂性，而我承认它会减少3倍的时间。

另一方面,如果你使用PASCAL字符串将不得不重新设计您的API来考虑在长度和bit-endianness注册,帕斯卡字符串的众所周知的限制255字符(0 xff)因为中存储的长度是1个字节(8位),而且你想要更长的字符串(16位- >任何)你必须考虑在一层的架构代码,这意味着在大多数情况下不相容的字符串API如果你想要更长的字符串。

例子:

One file was written with your prepended string api on an 8 bit computer and then would have to be read on say a 32 bit computer, what would the lazy program do considers that your 4bytes are the length of the string then allocate that lot of memory then attempt to read that many bytes. Another case would be PPC 32 byte string read(little endian) onto a x86 (big endian), of course if you don't know that one is written by the other there would be trouble. 1 byte length (0x00000001) would become 16777216 (0x0100000) that is 16 MB for reading a 1 byte string. Of course you would say that people should agree on one standard but even 16bit unicode got little and big endianness.

当然，C也有它的问题，但它不会受到这里提出的问题的影响。