尽管我很喜欢C和c++,但我还是忍不住对空结尾字符串的选择抓耳挠脑:

Length prefixed (i.e. Pascal) strings existed before C Length prefixed strings make several algorithms faster by allowing constant time length lookup. Length prefixed strings make it more difficult to cause buffer overrun errors. Even on a 32 bit machine, if you allow the string to be the size of available memory, a length prefixed string is only three bytes wider than a null terminated string. On 16 bit machines this is a single byte. On 64 bit machines, 4GB is a reasonable string length limit, but even if you want to expand it to the size of the machine word, 64 bit machines usually have ample memory making the extra seven bytes sort of a null argument. I know the original C standard was written for insanely poor machines (in terms of memory), but the efficiency argument doesn't sell me here. Pretty much every other language (i.e. Perl, Pascal, Python, Java, C#, etc) use length prefixed strings. These languages usually beat C in string manipulation benchmarks because they are more efficient with strings. C++ rectified this a bit with the std::basic_string template, but plain character arrays expecting null terminated strings are still pervasive. This is also imperfect because it requires heap allocation. Null terminated strings have to reserve a character (namely, null), which cannot exist in the string, while length prefixed strings can contain embedded nulls.

其中一些东西比C语言出现得更晚,所以C语言不知道它们是有道理的。然而,在C语言出现之前,有些语言就已经很简单了。为什么会选择空终止字符串,而不是明显更好的长度前缀?

编辑:因为有些人问了关于我上面提到的效率点的事实(他们不喜欢我已经提供的事实),他们源于以下几点:

使用空结尾字符串的Concat需要O(n + m)时间复杂度。长度前缀通常只需要O(m)。 使用空结尾字符串的长度需要O(n)时间复杂度。长度前缀为O(1)。 Length和concat是迄今为止最常见的字符串操作。在一些情况下,以空结尾的字符串可能更有效,但这种情况发生的频率要低得多。

从下面的答案,这些是一些情况下,空终止字符串更有效:

When you need to cut off the start of a string and need to pass it to some method. You can't really do this in constant time with length prefixing even if you are allowed to destroy the original string, because the length prefix probably needs to follow alignment rules. In some cases where you're just looping through the string character by character you might be able to save a CPU register. Note that this works only in the case that you haven't dynamically allocated the string (Because then you'd have to free it, necessitating using that CPU register you saved to hold the pointer you originally got from malloc and friends).

上面这些词都没有length和concat常见。

下面的答案中还有一个断言:

你需要把绳子的一端剪掉

但这个是不正确的——对于以null结尾的字符串和有长度前缀的字符串,它的时间是相同的。(以Null结尾的字符串只是在你想要的新结尾的地方插入一个Null,长度前缀只是从前缀中减去。)


当前回答

懒惰、寄存器节俭和可移植性考虑到任何语言的汇编核心,尤其是C语言,它比汇编高出一步(因此继承了大量汇编遗留代码)。 你会同意null字符在那些ASCII的日子里是无用的,它(可能和EOF控件字符一样好)。

让我们看看伪代码

function readString(string) // 1 parameter: 1 register or 1 stact entries
    pointer=addressOf(string) 
    while(string[pointer]!=CONTROL_CHAR) do
        read(string[pointer])
        increment pointer

共使用1个寄存器

案例2

 function readString(length,string) // 2 parameters: 2 register used or 2 stack entries
     pointer=addressOf(string) 
     while(length>0) do 
         read(string[pointer])
         increment pointer
         decrement length

共使用2个寄存器

这在当时似乎是短视的,但考虑到代码和寄存器的节俭(这在当时是PREMIUM,那时你知道,他们使用穿孔卡)。因此,更快(当处理器速度可以以kHz计),这个“黑客”是相当不错的,可轻松移植到无寄存器处理器。

为了便于讨论,我将实现2个常见的字符串操作

stringLength(string)
     pointer=addressOf(string)
     while(string[pointer]!=CONTROL_CHAR) do
         increment pointer
     return pointer-addressOf(string)

复杂度O(n),在大多数情况下PASCAL字符串是O(1),因为字符串的长度是预先挂起的字符串结构(这也意味着该操作必须在更早的阶段进行)。

concatString(string1,string2)
     length1=stringLength(string1)
     length2=stringLength(string2)
     string3=allocate(string1+string2)
     pointer1=addressOf(string1)
     pointer3=addressOf(string3)
     while(string1[pointer1]!=CONTROL_CHAR) do
         string3[pointer3]=string1[pointer1]
         increment pointer3
         increment pointer1
     pointer2=addressOf(string2)
     while(string2[pointer2]!=CONTROL_CHAR) do
         string3[pointer3]=string2[pointer2]
         increment pointer3
         increment pointer1
     return string3

复杂度O(n)和预先设置字符串长度不会改变操作的复杂性,而我承认它会减少3倍的时间。

另一方面,如果你使用PASCAL字符串将不得不重新设计您的API来考虑在长度和bit-endianness注册,帕斯卡字符串的众所周知的限制255字符(0 xff)因为中存储的长度是1个字节(8位),而且你想要更长的字符串(16位- >任何)你必须考虑在一层的架构代码,这意味着在大多数情况下不相容的字符串API如果你想要更长的字符串。

例子:

One file was written with your prepended string api on an 8 bit computer and then would have to be read on say a 32 bit computer, what would the lazy program do considers that your 4bytes are the length of the string then allocate that lot of memory then attempt to read that many bytes. Another case would be PPC 32 byte string read(little endian) onto a x86 (big endian), of course if you don't know that one is written by the other there would be trouble. 1 byte length (0x00000001) would become 16777216 (0x0100000) that is 16 MB for reading a 1 byte string. Of course you would say that people should agree on one standard but even 16bit unicode got little and big endianness.

当然,C也有它的问题,但它不会受到这里提出的问题的影响。

其他回答

假设C以Pascal的方式实现字符串,通过前缀长度:7字符长字符串与3字符字符串的数据类型相同吗?如果答案是肯定的,那么当我将前者分配给后者时,编译器应该生成什么样的代码?字符串应该被截断,还是自动调整大小?如果调整大小,该操作是否应该被锁保护以使其线程安全?不管你喜不喜欢,C语言的方法回避了所有这些问题。

C语言中没有字符串。C语言中的“string”只是一个指向char的指针。所以也许你问错问题了。

“省略字符串类型的基本原理是什么”可能更相关。对此,我要指出C不是面向对象的语言,只有基本的值类型。字符串是一个更高级别的概念,必须以某种方式组合其他类型的值来实现。C处于较低的抽象级别。

鉴于下面的狂风暴雨

我只是想指出,我并不是想说这是一个愚蠢或糟糕的问题,或者C语言表示字符串的方式是最好的选择。我试图澄清的是,如果考虑到C语言没有区分字符串作为数据类型与字节数组的机制这一事实,那么这个问题就会更简洁。考虑到今天计算机的处理和存储能力,这是最好的选择吗?可能不会。但事后诸葛总是20/20之类的。

还有一点没有提到:当C语言被设计出来的时候,有很多机器的“char”不是8位的(即使是今天的DSP平台也不是8位的)。如果一个人决定字符串是长度前缀,应该使用多少'char'的长度前缀?使用two会人为地限制具有8位字符和32位寻址空间的机器的字符串长度,而在具有16位字符和16位寻址空间的机器上浪费空间。

If one wanted to allow arbitrary-length strings to be stored efficiently, and if 'char' were always 8-bits, one could--for some expense in speed and code size--define a scheme were a string prefixed by an even number N would be N/2 bytes long, a string prefixed by an odd value N and an even value M (reading backward) could be ((N-1) + M*char_max)/2, etc. and require that any buffer which claims to offer a certain amount of space to hold a string must allow enough bytes preceding that space to handle the maximum length. The fact that 'char' isn't always 8 bits, however, would complicate such a scheme, since the number of 'char' required to hold a string's length would vary depending upon the CPU architecture.

即使在32位机器上,如果允许字符串的大小与可用内存相同,带前缀的长度字符串也只比以空结尾的字符串宽3个字节。

首先,对于短字符串来说,额外的3个字节可能是相当大的开销。具体来说,零长度字符串现在占用的内存是原来的4倍。我们中的一些人正在使用64位机器,因此我们要么需要8个字节来存储零长度的字符串,要么字符串格式无法处理平台支持的最长字符串。

可能还需要处理对齐问题。假设我有一个包含7个字符串的内存块,比如“solo\0second\0\0four\0five\0\0seventh”。第二个字符串从偏移量5开始。硬件可能要求32位整数以4的倍数的地址对齐,因此您必须添加填充,从而进一步增加开销。相比之下,C表示非常节省内存。(内存效率很好;例如,它有助于缓存性能。)

与长度前缀相比,null终止的一个优点是字符串比较的简单性,这一点我没有看到任何人提到过。考虑比较标准,它返回小于、等于或大于的有符号结果。对于长度前缀,算法必须遵循以下几行:

Compare the two lengths; record the smaller, and note if they are equal (this last step might be deferred to step 3). Scan the two character sequences, subtracting characters at matching indices (or use a dual pointer scan). Stop either when the difference is nonzero, returning the difference, or when the number of characters scanned is equal to the smaller length. When the smaller length is reached, one string is a prefix of the other. Return negative or positive value according to which is shorter, or zero if of equal length.

将其与null终止算法进行对比:

扫描两个字符序列,在匹配的索引处减去字符[注意,移动指针处理得更好]。当差值非零时停止,返回差值。注意:如果一个字符串是另一个字符串的PROPER前缀,减法中的一个字符将为NUL,即零,比较将自然地停止在那里。 如果差值为零,-only then-检查是否有字符为NUL。如果是,则返回0,否则继续到下一个字符。

以null结尾的情况更简单,并且非常容易用双指针扫描高效地实现。带长度前缀的大小写至少做同样多的工作,几乎总是更多。如果你的算法必须做大量的字符串比较[e。编译器!],以null结尾的情况胜出。现在,这可能不那么重要了,但在过去,是的。