懒惰、寄存器节俭和可移植性考虑到任何语言的汇编核心，尤其是C语言，它比汇编高出一步(因此继承了大量汇编遗留代码)。 你会同意null字符在那些ASCII的日子里是无用的，它(可能和EOF控件字符一样好)。

让我们看看伪代码

function readString(string) // 1 parameter: 1 register or 1 stact entries
    pointer=addressOf(string) 
    while(string[pointer]!=CONTROL_CHAR) do
        read(string[pointer])
        increment pointer

共使用1个寄存器

案例2

 function readString(length,string) // 2 parameters: 2 register used or 2 stack entries
     pointer=addressOf(string) 
     while(length>0) do 
         read(string[pointer])
         increment pointer
         decrement length

共使用2个寄存器

这在当时似乎是短视的，但考虑到代码和寄存器的节俭(这在当时是PREMIUM，那时你知道，他们使用穿孔卡)。因此，更快(当处理器速度可以以kHz计)，这个“黑客”是相当不错的，可轻松移植到无寄存器处理器。

为了便于讨论，我将实现2个常见的字符串操作

stringLength(string)
     pointer=addressOf(string)
     while(string[pointer]!=CONTROL_CHAR) do
         increment pointer
     return pointer-addressOf(string)

复杂度O(n)，在大多数情况下PASCAL字符串是O(1)，因为字符串的长度是预先挂起的字符串结构(这也意味着该操作必须在更早的阶段进行)。

concatString(string1,string2)
     length1=stringLength(string1)
     length2=stringLength(string2)
     string3=allocate(string1+string2)
     pointer1=addressOf(string1)
     pointer3=addressOf(string3)
     while(string1[pointer1]!=CONTROL_CHAR) do
         string3[pointer3]=string1[pointer1]
         increment pointer3
         increment pointer1
     pointer2=addressOf(string2)
     while(string2[pointer2]!=CONTROL_CHAR) do
         string3[pointer3]=string2[pointer2]
         increment pointer3
         increment pointer1
     return string3

复杂度O(n)和预先设置字符串长度不会改变操作的复杂性，而我承认它会减少3倍的时间。

另一方面,如果你使用PASCAL字符串将不得不重新设计您的API来考虑在长度和bit-endianness注册,帕斯卡字符串的众所周知的限制255字符(0 xff)因为中存储的长度是1个字节(8位),而且你想要更长的字符串(16位- >任何)你必须考虑在一层的架构代码,这意味着在大多数情况下不相容的字符串API如果你想要更长的字符串。

例子:

One file was written with your prepended string api on an 8 bit computer and then would have to be read on say a 32 bit computer, what would the lazy program do considers that your 4bytes are the length of the string then allocate that lot of memory then attempt to read that many bytes. Another case would be PPC 32 byte string read(little endian) onto a x86 (big endian), of course if you don't know that one is written by the other there would be trouble. 1 byte length (0x00000001) would become 16777216 (0x0100000) that is 16 MB for reading a 1 byte string. Of course you would say that people should agree on one standard but even 16bit unicode got little and big endianness.

当然，C也有它的问题，但它不会受到这里提出的问题的影响。

Obviously for performance and safety, you'll want to keep the length of a string while you're working with it rather than repeatedly performing strlen or the equivalent on it. However, storing the length in a fixed location just before the string contents is an incredibly bad design. As Jörgen pointed out in the comments on Sanjit's answer, it precludes treating the tail of a string as a string, which for example makes a lot of common operations like path_to_filename or filename_to_extension impossible without allocating new memory (and incurring the possibility of failure and error handling). And then of course there's the issue that nobody can agree how many bytes the string length field should occupy (plenty of bad "Pascal string" languages used 16-bit fields or even 24-bit fields which preclude processing of long strings).

C语言让程序员选择是否/在哪里/如何存储长度的设计更加灵活和强大。当然，程序员必须聪明。C语言惩罚愚蠢的程序崩溃，慢慢停止，或者让你的敌人扎根。

来自马的口

None of BCPL, B, or C supports character data strongly in the language; each treats strings much like vectors of integers and supplements general rules by a few conventions. In both BCPL and B a string literal denotes the address of a static area initialized with the characters of the string, packed into cells. In BCPL, the first packed byte contains the number of characters in the string; in B, there is no count and strings are terminated by a special character, which B spelled *e. This change was made partially to avoid the limitation on the length of a string caused by holding the count in an 8- or 9-bit slot, and partly because maintaining the count seemed, in our experience, less convenient than using a terminator.

Dennis M Ritchie, C语言的开发

根据Joel Spolsky在这篇博文中的说法，

这是因为发明了UNIX和C编程语言的PDP-7微处理器有一个ascii字符串类型。ASCIZ的意思是“以Z(零)结尾的ASCII”。

在看到这里所有其他的答案后，我相信即使这是真的，这也只是C具有以空结束的“字符串”的部分原因。这篇文章很有启发性，因为像字符串这样简单的东西实际上是相当困难的。

还有一点没有提到:当C语言被设计出来的时候，有很多机器的“char”不是8位的(即使是今天的DSP平台也不是8位的)。如果一个人决定字符串是长度前缀，应该使用多少'char'的长度前缀?使用two会人为地限制具有8位字符和32位寻址空间的机器的字符串长度，而在具有16位字符和16位寻址空间的机器上浪费空间。

If one wanted to allow arbitrary-length strings to be stored efficiently, and if 'char' were always 8-bits, one could--for some expense in speed and code size--define a scheme were a string prefixed by an even number N would be N/2 bytes long, a string prefixed by an odd value N and an even value M (reading backward) could be ((N-1) + M*char_max)/2, etc. and require that any buffer which claims to offer a certain amount of space to hold a string must allow enough bytes preceding that space to handle the maximum length. The fact that 'char' isn't always 8 bits, however, would complicate such a scheme, since the number of 'char' required to hold a string's length would vary depending upon the CPU architecture.

假设C以Pascal的方式实现字符串，通过前缀长度:7字符长字符串与3字符字符串的数据类型相同吗?如果答案是肯定的，那么当我将前者分配给后者时，编译器应该生成什么样的代码?字符串应该被截断，还是自动调整大小?如果调整大小，该操作是否应该被锁保护以使其线程安全?不管你喜不喜欢，C语言的方法回避了所有这些问题。