有没有一个聪明的方法让用户在隐藏和查看密码之间切换在一个android EditText? 许多基于PC的应用程序都允许用户这样做。


当前回答

在XML中这样做

    <LinearLayout
          android:layout_height="wrap_content"
          android:layout_width="fill_parent"
          android:orientation="vertical"
          >
          <RelativeLayout
              android:id="@+id/REFReLayTellFriend"
              android:layout_width="match_parent"
              android:layout_height="wrap_content"
              android:orientation="horizontal"
              >
          <EditText
              android:id="@+id/etpass1"
              android:layout_width="fill_parent"
              android:layout_height="wrap_content"
              android:background="@android:color/transparent"
              android:bottomLeftRadius="10dp"
              android:bottomRightRadius="50dp"
              android:fontFamily="@font/frutiger"
              android:gravity="start"
              android:inputType="textPassword"
              android:hint="@string/regpass_pass1"
              android:padding="20dp"
              android:paddingBottom="10dp"
              android:textColor="#000000"
              android:textColorHint="#d3d3d3"
              android:textSize="14sp"
              android:topLeftRadius="10dp"
              android:topRightRadius="10dp"/>
              <ImageButton
                  android:id="@+id/imgshowhide1"
                  android:layout_width="40dp"
                  android:layout_height="20dp"
                  android:layout_marginTop="20dp"
                  android:layout_marginRight="10dp"
                  android:background="@drawable/showpass"
                  android:layout_alignRight="@+id/etpass1"/>
          </RelativeLayout>    

 boolean show=true;
 //on image click inside password do this
 if(show){
                imgshowhide2.setBackgroundResource(0);
                imgshowhide2.setBackgroundResource(R.drawable.hide);
                etpass2.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
                etpass2.setSelection(etpass2.getText().length());

                show=false;
            }else{
                imgshowhide2.setBackgroundResource(0);
                imgshowhide2.setBackgroundResource(R.drawable.showpass);
                //etpass1.setInputType(InputType.TYPE_TEXT);
                etpass2.setInputType(InputType.TYPE_CLASS_TEXT |
                        InputType.TYPE_TEXT_VARIATION_PASSWORD);
                etpass2.setSelection(etpass2.getText().length());
                show=true;
            }

其他回答

private int passwordNotVisible=1; 
  @Override
  protected void onCreate(Bundle savedInstanceState) {
 showPassword = (ImageView) findViewById(R.id.show_password);
    showPassword.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            EditText paswword = (EditText) findViewById(R.id.Password);
            if (passwordNotVisible == 1) {
                paswword.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
                passwordNotVisible = 0;
            } else {

                paswword.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
                passwordNotVisible = 1;
            }


            paswword.setSelection(paswword.length());

        }
    });
}

使用复选框并相应地更改输入类型。

public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
    int start,end;
    Log.i("inside checkbox chnge",""+isChecked);
    if(!isChecked){
        start=passWordEditText.getSelectionStart();
        end=passWordEditText.getSelectionEnd();
        passWordEditText.setTransformationMethod(new PasswordTransformationMethod());;
        passWordEditText.setSelection(start,end);
    }else{
        start=passWordEditText.getSelectionStart();
        end=passWordEditText.getSelectionEnd();
        passWordEditText.setTransformationMethod(null);
        passWordEditText.setSelection(start,end);
    }
}

试试这个:

passwordEditText.setInputType(1);

Or

passwordEditText.setInputType(InputType.TYPE_CLASS_TEXT);

TextInputLayout的更新代码:

   <androidx.cardview.widget.CardView
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    app:layout_constraintBottom_toTopOf="@+id/lg_forget_password"
    app:layout_constraintTop_toBottomOf="@+id/lg_name"
    app:cardElevation="@dimen/dp20"
    android:layout_marginStart="@dimen/dp20"
    app:cardCornerRadius="@dimen/dp10"
    android:layout_marginEnd="@dimen/dp20"
    android:id="@+id/textField">

    <com.google.android.material.textfield.TextInputLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:backgroundTint="@android:color/transparent"
        app:boxStrokeWidth="0dp"
        app:boxStrokeWidthFocused="0dp"
        app:endIconMode="password_toggle"
        app:hintEnabled="false"
      >

        <com.google.android.material.textfield.TextInputEditText
            android:id="@+id/lg_password"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:background="@drawable/input_bg"
            android:drawableStart="@drawable/ic_baseline_lock_24"
            android:drawablePadding="@dimen/dp10"
            android:fontFamily="@font/roboto_flex"
            android:hint="@string/password"
            android:inputType="textPassword"
            android:padding="@dimen/dp15"
            android:singleLine="true" />

    </com.google.android.material.textfield.TextInputLayout>
</androidx.cardview.widget.CardView>

结果:

我使用了一个OnClickListener(),它与我想用作toogle的按钮相关联。

private EditText email_et, contraseña_et;
protected void onCreate(Bundle savedInstanceState) {
....
contraseña_et = (EditText) findViewById(R.id.contraseña_et);
....
vercontra_btn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            int inputType = contraseña_et.getInputType();
            if (inputType == 129){
                contraseña_et.setInputType(1);
            } else {
                contraseña_et.setInputType(129);
            }
            contraseña_et.setSelection(contraseña_et.getText().length());
        }
    });

阅读文档,int值似乎是不同的,所以我调试找到正确的值,它的工作棒极了,这是一个更容易一点的方式。

[顺便说一下,Contraseña是西班牙语的密码]