有没有一个聪明的方法让用户在隐藏和查看密码之间切换在一个android EditText? 许多基于PC的应用程序都允许用户这样做。
当前回答
这是我的解决方案没有使用TextInputEditText和转换方法。
XML
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="vertical">
<TextView
style="@style/FormLabel"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:text="@string/username" />
<EditText
android:id="@+id/loginUsername"
style="@style/EditTextStyle"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:drawableLeft="@drawable/ic_person_outline_black_24dp"
android:drawableStart="@drawable/ic_person_outline_black_24dp"
android:inputType="textEmailAddress"
android:textColor="@color/black" />
<TextView
style="@style/FormLabel"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginTop="20dp"
android:text="@string/password" />
<EditText
android:id="@+id/loginPassword"
style="@style/EditTextStyle"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:drawableEnd="@drawable/ic_visibility_off_black_24dp"
android:drawableLeft="@drawable/ic_lock_outline_black_24dp"
android:drawableRight="@drawable/ic_visibility_off_black_24dp"
android:drawableStart="@drawable/ic_lock_outline_black_24dp"
android:inputType="textPassword"
android:textColor="@color/black" />
</LinearLayout>
Java代码
boolean VISIBLE_PASSWORD = false; //declare as global variable befor onCreate()
loginPassword = (EditText)findViewById(R.id.loginPassword);
loginPassword.setOnTouchListener(new View.OnTouchListener() {
public boolean onTouch(View v, MotionEvent event) {
final int DRAWABLE_LEFT = 0;
final int DRAWABLE_TOP = 1;
final int DRAWABLE_RIGHT = 2;
final int DRAWABLE_BOTTOM = 3;
if (event.getAction() == MotionEvent.ACTION_UP) {
if (event.getRawX() >= (loginPassword.getRight() - loginPassword.getCompoundDrawables()[DRAWABLE_RIGHT].getBounds().width())) {
// your action here
//Helper.toast(LoginActivity.this, "Toggle visibility");
if (VISIBLE_PASSWORD) {
VISIBLE_PASSWORD = false;
loginPassword.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
loginPassword.setCompoundDrawablesWithIntrinsicBounds(R.drawable.ic_lock_outline_black_24dp, 0, R.drawable.ic_visibility_off_black_24dp, 0);
} else {
VISIBLE_PASSWORD = true;
loginPassword.setInputType(InputType.TYPE_CLASS_TEXT);
loginPassword.setCompoundDrawablesWithIntrinsicBounds(R.drawable.ic_lock_outline_black_24dp, 0, R.drawable.ic_visibility_black_24dp, 0);
}
return false;
}
}
return false;
}
});
其他回答
如果你想要一个简单的解决方案,你可以使用这个扩展的Android的EditText去这个链接了解更多信息:https://github.com/scottyab/showhidepasswordedittext
将此添加到build.gradle中: 实现“com.github.scottyab: showhidepasswordedittext: 0.8”
然后更改XML文件中的EditText。
来自:< EditText
: < com.scottyab.showhidepasswordedittext.ShowHidePasswordEditText
这是所有。
注意:在XML设计中无法看到它,请尝试在模拟器或物理设备中运行它。
非常简单的形式:
private fun updatePasswordVisibility(editText: AppCompatEditText) {
if (editText.transformationMethod is PasswordTransformationMethod) {
editText.transformationMethod = null
} else {
editText.transformationMethod = PasswordTransformationMethod()
}
editText.setSelection(editText.length())
}
希望能有所帮助。
用复选框显示和隐藏密码Edit_Text
XML
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent"
android:layout_height="match_parent">
<EditText
android:inputType="textPassword"
android:id="@+id/edtPass"
android:textSize="20dp"
android:hint="password"
android:padding="20dp"
android:background="#efeaea"
android:layout_width="match_parent"
android:layout_margin="20dp"
android:layout_height="wrap_content" />
<CheckBox
android:background="#ff4"
android:layout_centerInParent="true"
android:textSize="25dp"
android:text="show password"
android:layout_below="@id/edtPass"
android:id="@+id/showPassword"
android:layout_marginTop="20dp"
android:layout_width="wrap_content"
android:gravity="top|right"
android:layout_height="wrap_content" />
</RelativeLayout>
java代码
package com.example.root.sql2;
import android.annotation.SuppressLint;
import android.os.Bundle;
import android.support.design.widget.FloatingActionButton;
import android.support.design.widget.Snackbar;
import android.support.v7.app.AppCompatActivity;
import android.support.v7.widget.AppCompatCheckBox;
import android.support.v7.widget.Toolbar;
import android.text.method.HideReturnsTransformationMethod;
import android.text.method.PasswordTransformationMethod;
import android.view.View;
import android.widget.CheckBox;
import android.widget.CompoundButton;
import android.widget.EditText;
public class password extends AppCompatActivity {
EditText password;
CheckBox show_hide_password;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.hide);
findViewById();
show_hide_pass();
}//end onCreate
public void show_hide_pass(){
show_hide_password.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton compoundButton, boolean b) {
if (!b){
// hide password
password.setTransformationMethod(PasswordTransformationMethod.getInstance());
}else{
// show password
password.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
}
}
});
} // end show_hide_pass
public void findViewById(){ // find ids ui and
password = (EditText) findViewById(R.id.edtPass);
show_hide_password = (CheckBox) findViewById(R.id.showPassword);
}//end findViewById
}// end class
您必须询问当前文本是否已经显示了圆点,函数PasswordTransformationMethod.getInstance()允许您这样做。
这是我在kotlin中的函数:
fun hideAndShowPassword(editText: EditText, indicator: ImageView) {
if (editText.transformationMethod == PasswordTransformationMethod.getInstance()) {
editText.transformationMethod = HideReturnsTransformationMethod.getInstance()
indicator.setImageDrawable(
ContextCompat.getDrawable(
editText.context,
R.drawable.eye
)
)
indicator.imageTintList =
ContextCompat.getColorStateList(editText.context, R.color.colorTintIcons)
} else {
editText.transformationMethod = PasswordTransformationMethod.getInstance()
indicator.setImageDrawable(
ContextCompat.getDrawable(
editText.context,
R.drawable.eye_off
)
)
indicator.imageTintList =
ContextCompat.getColorStateList(editText.context, R.color.colorTintIcons)
}
editText.setSelection(editText.text.length)
}
我可以添加ShowPassword / HidePassword代码,只需几行,在一个块中独立:
protected void onCreate(Bundle savedInstanceState) {
...
etPassword = (EditText)findViewById(R.id.password);
etPassword.setTransformationMethod(new PasswordTransformationMethod()); // Hide password initially
checkBoxShowPwd = (CheckBox)findViewById(R.id.checkBoxShowPwd);
checkBoxShowPwd.setText(getString(R.string.label_show_password)); // Hide initially, but prompting "Show Password"
checkBoxShowPwd.setOnCheckedChangeListener( new CompoundButton.OnCheckedChangeListener() {
public void onCheckedChanged(CompoundButton arg0, boolean isChecked) {
if (isChecked) {
etPassword.setTransformationMethod(null); // Show password when box checked
checkBoxShowPwd.setText(getString(R.string.label_hide_password)); // Prompting "Hide Password"
} else {
etPassword.setTransformationMethod(new PasswordTransformationMethod()); // Hide password when box not checked
checkBoxShowPwd.setText(getString(R.string.label_show_password)); // Prompting "Show Password"
}
}
} );
...
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