有没有一个聪明的方法让用户在隐藏和查看密码之间切换在一个android EditText? 许多基于PC的应用程序都允许用户这样做。
当前回答
这是我的解决方案没有使用TextInputEditText和转换方法。
XML
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="vertical">
<TextView
style="@style/FormLabel"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:text="@string/username" />
<EditText
android:id="@+id/loginUsername"
style="@style/EditTextStyle"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:drawableLeft="@drawable/ic_person_outline_black_24dp"
android:drawableStart="@drawable/ic_person_outline_black_24dp"
android:inputType="textEmailAddress"
android:textColor="@color/black" />
<TextView
style="@style/FormLabel"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginTop="20dp"
android:text="@string/password" />
<EditText
android:id="@+id/loginPassword"
style="@style/EditTextStyle"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:drawableEnd="@drawable/ic_visibility_off_black_24dp"
android:drawableLeft="@drawable/ic_lock_outline_black_24dp"
android:drawableRight="@drawable/ic_visibility_off_black_24dp"
android:drawableStart="@drawable/ic_lock_outline_black_24dp"
android:inputType="textPassword"
android:textColor="@color/black" />
</LinearLayout>
Java代码
boolean VISIBLE_PASSWORD = false; //declare as global variable befor onCreate()
loginPassword = (EditText)findViewById(R.id.loginPassword);
loginPassword.setOnTouchListener(new View.OnTouchListener() {
public boolean onTouch(View v, MotionEvent event) {
final int DRAWABLE_LEFT = 0;
final int DRAWABLE_TOP = 1;
final int DRAWABLE_RIGHT = 2;
final int DRAWABLE_BOTTOM = 3;
if (event.getAction() == MotionEvent.ACTION_UP) {
if (event.getRawX() >= (loginPassword.getRight() - loginPassword.getCompoundDrawables()[DRAWABLE_RIGHT].getBounds().width())) {
// your action here
//Helper.toast(LoginActivity.this, "Toggle visibility");
if (VISIBLE_PASSWORD) {
VISIBLE_PASSWORD = false;
loginPassword.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
loginPassword.setCompoundDrawablesWithIntrinsicBounds(R.drawable.ic_lock_outline_black_24dp, 0, R.drawable.ic_visibility_off_black_24dp, 0);
} else {
VISIBLE_PASSWORD = true;
loginPassword.setInputType(InputType.TYPE_CLASS_TEXT);
loginPassword.setCompoundDrawablesWithIntrinsicBounds(R.drawable.ic_lock_outline_black_24dp, 0, R.drawable.ic_visibility_black_24dp, 0);
}
return false;
}
}
return false;
}
});
其他回答
这是我的工作。这绝对对你有帮助
showpass.setOnCheckedChangeListener(new OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
if(!isChecked){
// show password
password_login.setTransformationMethod(PasswordTransformationMethod.getInstance());
Log.i("checker", "true");
}
else{
Log.i("checker", "false");
// hide password
password_login.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
}
}
});
显示:
editText.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
隐藏:
editText.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
在这些之后,光标被重置,所以:
editText.setSelection(editText.length());
you can use this
private fun showPasswordSwitch(checked: Boolean) {
registerBinding.registerActivityEditTextPassword.also {
// Password hide-show
it.inputType =
if (checked) TEXT_PASSWORD_SHOW else TEXT_PASSWORD_HIDE
}
}
const val TEXT_PASSWORD_SHOW = InputType.TYPE_CLASS_TEXT or InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD
const val TEXT_PASSWORD_HIDE = InputType.TYPE_CLASS_TEXT or InputType.TYPE_TEXT_VARIATION_PASSWORD
从支持库v24.2.0开始,这真的很容易实现。
你需要做的就是:
Add the design library to your dependencies dependencies { compile "com.android.support:design:24.2.0" } Use TextInputEditText in conjunction with TextInputLayout <android.support.design.widget.TextInputLayout android:id="@+id/etPasswordLayout" android:layout_width="match_parent" android:layout_height="wrap_content" app:passwordToggleEnabled="true" android:layout_marginBottom="@dimen/login_spacing_bottom"> <android.support.design.widget.TextInputEditText android:id="@+id/etPassword" android:layout_width="match_parent" android:layout_height="wrap_content" android:hint="@string/fragment_login_password_hint" android:inputType="textPassword"/> </android.support.design.widget.TextInputLayout>
passwordToggleEnabled属性将完成这项工作!
在你的根布局中,不要忘记添加xmlns:app="http://schemas.android.com/apk/res-auto" 您可以使用以下方法自定义密码切换:
app:passwordToggleDrawable -可绘制的使用作为密码输入可见切换图标。 app:passwordToggleTint -用于密码输入可见切换的图标。 app:passwordToggleTintMode -用于应用背景色调的混合模式。
更多细节在TextInputLayout文档。
对于安卓X
将android. design.widget. textinputlayout替换为com.google.android.material.textfield.TextInputLayout 将android.support.design.widget.TextInputEditText替换为com.google.android.material.textfield.TextInputEditText
TextInputLayout的更新代码:
<androidx.cardview.widget.CardView
android:layout_width="match_parent"
android:layout_height="wrap_content"
app:layout_constraintBottom_toTopOf="@+id/lg_forget_password"
app:layout_constraintTop_toBottomOf="@+id/lg_name"
app:cardElevation="@dimen/dp20"
android:layout_marginStart="@dimen/dp20"
app:cardCornerRadius="@dimen/dp10"
android:layout_marginEnd="@dimen/dp20"
android:id="@+id/textField">
<com.google.android.material.textfield.TextInputLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:backgroundTint="@android:color/transparent"
app:boxStrokeWidth="0dp"
app:boxStrokeWidthFocused="0dp"
app:endIconMode="password_toggle"
app:hintEnabled="false"
>
<com.google.android.material.textfield.TextInputEditText
android:id="@+id/lg_password"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="@drawable/input_bg"
android:drawableStart="@drawable/ic_baseline_lock_24"
android:drawablePadding="@dimen/dp10"
android:fontFamily="@font/roboto_flex"
android:hint="@string/password"
android:inputType="textPassword"
android:padding="@dimen/dp15"
android:singleLine="true" />
</com.google.android.material.textfield.TextInputLayout>
</androidx.cardview.widget.CardView>
结果:
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