验证字符串是否是有效的电子邮件地址的最优雅的代码是什么?
当前回答
我写了一个函数来检查电子邮件是否有效。在大多数情况下,这似乎对我很有效。
结果:
dasddas-@.com => FALSE
-asd@das.com => FALSE
as3d@dac.coas- => FALSE
dsq!a?@das.com => FALSE
_dasd@sd.com => FALSE
dad@sds => FALSE
asd-@asd.com => FALSE
dasd_-@jdas.com => FALSE
asd@dasd@asd.cm => FALSE
da23@das..com => FALSE
_dasd_das_@9.com => FALSE
d23d@da9.co9 => TRUE
dasd.dadas@dasd.com => TRUE
dda_das@das-dasd.com => TRUE
dasd-dasd@das.com.das => TRUE
代码:
private bool IsValidEmail(string email)
{
bool valid = false;
try
{
var addr = new System.Net.Mail.MailAddress(email);
valid = true;
}
catch
{
valid = false;
goto End_Func;
}
valid = false;
int pos_at = email.IndexOf('@');
char checker = Convert.ToChar(email.Substring(pos_at + 1, 1));
var chars = "qwertyuiopasdfghjklzxcvbnm0123456789";
foreach (char chr in chars)
{
if (checker == chr)
{
valid = true;
break;
}
}
if (valid == false)
{
goto End_Func;
}
int pos_dot = email.IndexOf('.', pos_at + 1);
if(pos_dot == -1)
{
valid = false;
goto End_Func;
}
valid = false;
try
{
checker = Convert.ToChar(email.Substring(pos_dot + 1, 1));
foreach (char chr in chars)
{
if (checker == chr)
{
valid = true;
break;
}
}
}
catch
{
valid = false;
goto End_Func;
}
Regex valid_checker = new Regex(@"^[a-zA-Z0-9_@.-]*$");
valid = valid_checker.IsMatch(email);
if (valid == false)
{
goto End_Func;
}
List<int> pos_list = new List<int> { };
int pos = 0;
while (email.IndexOf('_', pos) != -1)
{
pos_list.Add(email.IndexOf('_', pos));
pos = email.IndexOf('_', pos) + 1;
}
pos = 0;
while (email.IndexOf('.', pos) != -1)
{
pos_list.Add(email.IndexOf('.', pos));
pos = email.IndexOf('.', pos) + 1;
}
pos = 0;
while (email.IndexOf('-', pos) != -1)
{
pos_list.Add(email.IndexOf('-', pos));
pos = email.IndexOf('-', pos) + 1;
}
int sp_cnt = pos_list.Count();
pos_list.Sort();
for (int i = 0; i < sp_cnt - 1; i++)
{
if (pos_list[i] + 1 == pos_list[i + 1])
{
valid = false;
break;
}
if (pos_list[i]+1 == pos_at || pos_list[i]+1 == pos_dot)
{
valid = false;
break;
}
}
if(valid == false)
{
goto End_Func;
}
if (pos_list[sp_cnt - 1] == email.Length - 1 || pos_list[0] == 0)
{
valid = false;
}
End_Func:;
return valid;
}
其他回答
我总结了以上所有的答案,截至2021年,我在这门课上为自己写的答案:
public static class StringExt {
private const string emailPattern = @"^(?!\.)(""([^""\r\\]|\\[""\r\\])*""|"
+ @"([-a-z0-9!#$%&'*+/=?^_`{|}~]|(?<!\.)\.)*)(?<!\.)"
+ @"@[a-z0-9][\w\.-]*[a-z0-9]\.[a-z][a-z\.]*[a-z]$";
public static bool IsValidMailAddress(this string pThis)
=> pThis is not null
&& Regex.IsMatch(pThis, emailPattern, RegexOptions.IgnoreCase);
}
我发现这个正则表达式在检查@标记以外的东西和接受奇怪的边缘情况之间是一个很好的权衡:
^[^@\s]+@[^@\s]+(\.[^@\s]+)+$
它至少会让你在@标记周围放一些东西,并且至少放一个正常的域。
一般来说,使用正则表达式来验证电子邮件地址并不是一件容易的事情;在撰写本文时,电子邮件地址的语法必须遵循相对较多的标准,在正则表达式中实现所有这些标准实际上是不可行的!
我强烈建议你试试我们的EmailVerify。NET是一个成熟的。NET库,它可以根据当前所有的IETF标准(RFC 1123, RFC 2821, RFC 2822, RFC 3696, RFC 4291, RFC 5321和RFC 5322)验证电子邮件地址,测试相关的DNS记录,检查目标邮箱是否可以接受消息,甚至可以判断给定的地址是否是一次性的。
免责声明:我是这个组件的主要开发人员。
There are a lot of strong answers here. However, I recommend that we take a step back. @Cogwheel answers the question https://stackoverflow.com/a/1374644/388267. Nevertheless, it could be costly in a bulk validation scenario, if many of the email address being validated are invalid. I suggest that we employ a bit of logic before we enter into his try-catch block. I know that the following code could be written using RegEx but that could be costly for new developers to understand. This is my twopence worth:
public static bool IsEmail(this string input)
{
if (string.IsNullOrWhiteSpace(input)) return false;
// MUST CONTAIN ONE AND ONLY ONE @
var atCount = input.Count(c => c == '@');
if (atCount != 1) return false;
// MUST CONTAIN PERIOD
if (!input.Contains(".")) return false;
// @ MUST OCCUR BEFORE LAST PERIOD
var indexOfAt = input.IndexOf("@", StringComparison.Ordinal);
var lastIndexOfPeriod = input.LastIndexOf(".", StringComparison.Ordinal);
var atBeforeLastPeriod = lastIndexOfPeriod > indexOfAt;
if (!atBeforeLastPeriod) return false;
// CODE FROM COGWHEEL'S ANSWER: https://stackoverflow.com/a/1374644/388267
try
{
var addr = new System.Net.Mail.MailAddress(input);
return addr.Address == input;
}
catch
{
return false;
}
}
我将Poyson 1的答案简化如下:
public static bool IsValidEmailAddress(string candidateEmailAddr)
{
string regexExpresion = "\\w+([-+.']\\w+)*@\\w+([-.]\\w+)*\\.\\w+([-.]\\w+)*";
return (Regex.IsMatch(candidateEmailAddr, regexExpresion)) &&
(Regex.Replace(candidateEmailAddr, regexExpresion, string.Empty).Length == 0);
}
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