验证字符串是否是有效的电子邮件地址的最优雅的代码是什么?
当前回答
我是来偷电子邮件的验证码的。然后我发现答案中的代码不必要地扩展了。我相信我用最短的方式写出了最好的解决方案:
public static bool IsEmail(string email)
{
try
{
return new System.Net.Mail.MailAddress(email).Address == email && !email.Trim().EndsWith(".");
}
catch
{
return false;
}
}
其他回答
我经常用这个来验证电子邮件,它就像一个魅力。这验证了电子邮件必须在@之前至少有一个字符,并且在“”之前至少有一个字符。
public static bool ValidateEmail(string value, bool required, int minLength, int maxLength)
{
value = value.Trim();
if (required == false && value == "") return true;
if (required && value == "") return false;
if (value.Length < minLength || value.Length > maxLength) return false;
//Email must have at least one character before an @, and at least one character before the .
int index = value.IndexOf('@');
if (index < 1 || value.LastIndexOf('.') < index + 2) return false;
return true;
}
Personally, I would say that you should just make sure there is an @ symbol in there, with possibly a . character. There's many regexes you could use of varying correctness, but I think most of these leave out valid email addresses, or let invalid ones through. If people want to put in a fake email address, they will put in a fake one. If you need to verify that the email address is legit, and that the person is in control of that email address, then you will need to send them an email with a special coded link so they can verify that it indeed is a real address.
.net 4.5增加了System.ComponentModel.DataAnnotations.EmailAddressAttribute
你可以浏览EmailAddressAttribute的源代码,这是它内部使用的正则表达式:
const string pattern = @"^((([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+(\.([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+)*)|((\x22)((((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(([\x01-\x08\x0b\x0c\x0e-\x1f\x7f]|\x21|[\x23-\x5b]|[\x5d-\x7e]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(\\([\x01-\x09\x0b\x0c\x0d-\x7f]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF]))))*(((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(\x22)))@((([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.)+(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.?$";
如果您将多个解决方案组合在一起来编写完美的代码呢?
我得到了排名最高的2个解决方案和评论,并结合起来得到更准确的答案。 它的短,快和可爱。
public static bool isValidEmail(string email)
{
try
{
var addr = new System.Net.Mail.MailAddress(email);
if (addr.Address == email)
{
string expression = "\\w+([-+.']\\w+)*@\\w+([-.]\\w+)*\\.\\w+([-.]\\w+)*";
if (Regex.IsMatch(email, expression))
{
if (Regex.Replace(email, expression, string.Empty).Length == 0)
return true;
}
return false;
}
return false;
}
catch
{
return false;
}
}
如果你正在使用FluentValidation,你可以写一些像这样简单的东西:
public cass User
{
public string Email { get; set; }
}
public class UserValidator : AbstractValidator<User>
{
public UserValidator()
{
RuleFor(x => x.Email).EmailAddress().WithMessage("The text entered is not a valid email address.");
}
}
// Validates an user.
var validationResult = new UserValidator().Validate(new User { Email = "açflkdj" });
// This will return false, since the user email is not valid.
bool userIsValid = validationResult.IsValid;
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