在java.sql实例中使用SQL IN子句的最佳变通方法是什么?由于SQL注入攻击安全问题,不支持多值的PreparedStatement:一个?占位符表示一个值,而不是一个值列表。

考虑下面的SQL语句:

SELECT my_column FROM my_table where search_column IN (?)

使用preparedStatement。setString(1, "'A', 'B', 'C'");本质上是一种无用的尝试,试图解决使用原因?首先。

有什么可行的解决办法?


当前回答

使用嵌套查询是一种令人不快的变通方法,但肯定是可行的。创建一个包含列的临时表MYVALUES。将值列表插入到MYVALUES表中。然后执行

select my_column from my_table where search_column in ( SELECT value FROM MYVALUES )

很丑,但如果你的价值列表非常大,这是一个可行的选择。

如果您的数据库没有缓存准备好的语句,这种技术还有一个额外的好处,那就是可能会从优化器获得更好的查询计划(检查一个页面是否有多个值,表只能检查一次,而不是每个值检查一次,等等),这样可以节省开销。您的“insert”将需要批处理,并且可能需要调整MYVALUES表以使锁定或其他高开销保护最小化。

其他回答

PostgreSQL的解决方案:

final PreparedStatement statement = connection.prepareStatement(
        "SELECT my_column FROM my_table where search_column = ANY (?)"
);
final String[] values = getValues();
statement.setArray(1, connection.createArrayOf("text", values));

try (ResultSet rs = statement.executeQuery()) {
    while(rs.next()) {
        // do some...
    }
}

or

final PreparedStatement statement = connection.prepareStatement(
        "SELECT my_column FROM my_table " + 
        "where search_column IN (SELECT * FROM unnest(?))"
);
final String[] values = getValues();
statement.setArray(1, connection.createArrayOf("text", values));

try (ResultSet rs = statement.executeQuery()) {
    while(rs.next()) {
        // do some...
    }
}

而不是使用

SELECT my_column FROM my_table where search_column IN (?)

使用Sql语句作为

select id, name from users where id in (?, ?, ?)

and

preparedStatement.setString( 1, 'A');
preparedStatement.setString( 2,'B');
preparedStatement.setString( 3, 'C');

或者使用存储过程,这将是最好的解决方案,因为sql语句将被编译并存储在数据库服务器中

遵循亚当的想法。让你的准备语句select my_column from my_table where search_column in (#) 创建一个字符串x,并根据你的值列表用一些“?,?,?”填充它 然后只需更改查询中的#为您的新字符串x填充

在javaranche Journal上Jeanne Boyarsky的JDBC批处理选择语句条目中,有对各种可用选项及其优缺点的分析。

建议的方案是:

Prepare SELECT my_column FROM my_table WHERE search_column = ?, execute it for each value and UNION the results client-side. Requires only one prepared statement. Slow and painful. Prepare SELECT my_column FROM my_table WHERE search_column IN (?,?,?) and execute it. Requires one prepared statement per size-of-IN-list. Fast and obvious. Prepare SELECT my_column FROM my_table WHERE search_column = ? ; SELECT my_column FROM my_table WHERE search_column = ? ; ... and execute it. [Or use UNION ALL in place of those semicolons. --ed] Requires one prepared statement per size-of-IN-list. Stupidly slow, strictly worse than WHERE search_column IN (?,?,?), so I don't know why the blogger even suggested it. Use a stored procedure to construct the result set. Prepare N different size-of-IN-list queries; say, with 2, 10, and 50 values. To search for an IN-list with 6 different values, populate the size-10 query so that it looks like SELECT my_column FROM my_table WHERE search_column IN (1,2,3,4,5,6,6,6,6,6). Any decent server will optimize out the duplicate values before running the query.

这些选择都不理想。

如果您正在使用JDBC4并且服务器支持x = ANY(y),那么最好的选择是使用PreparedStatement。setArray的描述在鲍里斯的回答。

不过,似乎没有任何方法可以使setArray与IN-lists一起工作。


有时SQL语句是在运行时加载的(例如,从属性文件中加载),但需要可变数量的参数。在这种情况下,首先定义查询:

query=SELECT * FROM table t WHERE t.column IN (?)

接下来,加载查询。然后在运行它之前确定参数的数量。一旦参数计数已知,运行:

sql = any( sql, count );

例如:

/**
 * Converts a SQL statement containing exactly one IN clause to an IN clause
 * using multiple comma-delimited parameters.
 *
 * @param sql The SQL statement string with one IN clause.
 * @param params The number of parameters the SQL statement requires.
 * @return The SQL statement with (?) replaced with multiple parameter
 * placeholders.
 */
public static String any(String sql, final int params) {
    // Create a comma-delimited list based on the number of parameters.
    final StringBuilder sb = new StringBuilder(
        String.join(", ", Collections.nCopies(possibleValue.size(), "?")));

    // For more than 1 parameter, replace the single parameter with
    // multiple parameter placeholders.
    if (sb.length() > 1) {
        sql = sql.replace("(?)", "(" + sb + ")");
    }

    // Return the modified comma-delimited list of parameters.
    return sql;
}

对于某些不支持通过JDBC 4规范传递数组的数据库,此方法可以方便地转换缓慢的= ?转换为更快的IN(?)子句条件,然后可以通过调用any方法进行扩展。

这适用于我(伪docode):

public class SqlHelper
{
    public static final ArrayList<String>platformList = new ArrayList<>(Arrays.asList("iOS","Android","Windows","Mac"));

    public static final String testQuery = "select * from devices where platform_nm in (:PLATFORM_NAME)";
}

指定绑定:

public class Test extends NamedParameterJdbcDaoSupport
public List<SampleModelClass> runQuery()
{
    //define rowMapper to insert in object of SampleClass
    final Map<String,Object> map = new HashMap<>();
    map.put("PLATFORM_LIST",DeviceDataSyncQueryConstants.platformList);
    return getNamedParameterJdbcTemplate().query(SqlHelper.testQuery, map, rowMapper)
}