刚从大学毕业的我渴望亲自动手。我的第一个任务是……“为我注释此代码”。

傻瓜。

过了一段时间我就厌倦了……

// this function doesn't actually calculated the profit, like it says --it really signals the mothership orbiting saturn that the planet is ripe for takeover

[later]

// I don't think anyone is going to read this

[various permutations on that last one]

// TODO: Finish.

options.BatchSize = 300; //Madness? THIS IS SPARTA!

// I don't know why I need this, but it stops the people being upside-down

x = -x;

从《雷神之锤III》的资料中，我在一些随机的帖子中偶然发现了这一点。该文件的完整源代码可以在这里找到。这是一种非常快速的求平方根倒数的方法。至于最好的评论呢?当然，这是一种常见的方法，但考虑到它附着在直线上，它的神奇之处在于它的伟大之处。

float Q_rsqrt( float number )
{
  long i;
  float x2, y;
  const float threehalfs = 1.5F;

  x2 = number * 0.5F;
  y  = number;
  i  = * ( long * ) &y;  // evil floating point bit level hacking
  i  = 0x5f3759df - ( i >> 1 ); // what the fuck?
  y  = * ( float * ) &i;
  y  = y * ( threehalfs - ( x2 * y * y ) ); // 1st iteration
  // y  = y * ( threehalfs - ( x2 * y * y ) ); // 2nd iteration, this can be removed

  #ifndef Q3_VM
  #ifdef __linux__
    assert( !isnan(y) ); // bk010122 - FPE?
  #endif
  #endif
  return y;
}

# To understand recursion, see the bottom of this file 

在文件的底部:

# To understand recursion, see the top of this file