// TODO: Delete

Fix problem where Nulls don't work properly.  Stupid Microsoft!

代码以迂回的方式一行一行地将null转换为零长度的字符串，因为愚蠢的程序员不理解null是什么，也从未听说过Nz()函数。

我在COBOL程序中看到的一些东西让我感到恐惧

* All comments pertain to the lines which follow.

这是什么意思?

有人对评论感到不舒服，以至于不得不写一个元评论? 有人习惯将注释放在相关代码的下面，而被告知要将注释放在上面?这是怎么发生的?

场景一:

return 0; // Happy ending

场景二:

int32_t Interpolate1DSignal(
  Array1D<float64>::Handle hfInputSamples,         // samples to be interpolated
  Array1D<float64>::Handle hfInterpolationFilter,  // polyphase filter coefficients,
  int32_t iFilterInterpolationFactor,              // # of "rows" in polyphase filter
  int32_t iFilterLength,                           // Length of each row in filter
  float64 fInterpolationFactor,                    // Factor to interpolate the
                                                   // signal by
  float64 fTimingOffset,                           // Offset into the signal (units   
                                                   // of samples)
  Array1D<float64>::Handle hfOutputSamples         // left as an exercise for the reader
);

//marco 2007.1.23
//I didn't do it

/*现在，让所有这些看 半得体的弱智步 哥哥 浏览器家族中的一员，互联网 该死的探险家*/