考虑一个包含名称的数据库表,其中有三行:
Peter
Paul
Mary
有没有一种简单的方法可以把它变成彼得、保罗、玛丽的一串?
考虑一个包含名称的数据库表,其中有三行:
Peter
Paul
Mary
有没有一种简单的方法可以把它变成彼得、保罗、玛丽的一串?
当前回答
在SQL Server中实现这一点的一种方法是将表内容返回为XML(对于XML原始),将结果转换为字符串,然后用“,”替换标记。
其他回答
我们可以使用RECUSRSIVITY、WITH CTE、union ALL,如下所示
declare @mytable as table(id int identity(1,1), str nvarchar(100))
insert into @mytable values('Peter'),('Paul'),('Mary')
declare @myresult as table(id int,str nvarchar(max),ind int, R# int)
;with cte as(select id,cast(str as nvarchar(100)) as str, cast(0 as int) ind from @mytable
union all
select t2.id,cast(t1.str+',' +t2.str as nvarchar(100)) ,t1.ind+1 from cte t1 inner join @mytable t2 on t2.id=t1.id+1)
insert into @myresult select *,row_number() over(order by ind) R# from cte
select top 1 str from @myresult order by R# desc
如果您使用的是SQL Server 2017或Azure,请参阅Mathieu Renda的回答。
当我试图连接两个具有一对多关系的表时,我也遇到了类似的问题。在SQL2005中,我发现XMLPATH方法可以非常容易地处理行的连接。
如果有一个名为STUDENTS的表
SubjectID StudentName
---------- -------------
1 Mary
1 John
1 Sam
2 Alaina
2 Edward
我期望的结果是:
SubjectID StudentName
---------- -------------
1 Mary, John, Sam
2 Alaina, Edward
我使用了以下T-SQL:
SELECT Main.SubjectID,
LEFT(Main.Students,Len(Main.Students)-1) As "Students"
FROM
(
SELECT DISTINCT ST2.SubjectID,
(
SELECT ST1.StudentName + ',' AS [text()]
FROM dbo.Students ST1
WHERE ST1.SubjectID = ST2.SubjectID
ORDER BY ST1.SubjectID
FOR XML PATH (''), TYPE
).value('text()[1]','nvarchar(max)') [Students]
FROM dbo.Students ST2
) [Main]
如果您可以在开头插入逗号并使用子字符串跳过第一个逗号,那么您可以以更紧凑的方式执行相同的操作,这样就不需要执行子查询:
SELECT DISTINCT ST2.SubjectID,
SUBSTRING(
(
SELECT ','+ST1.StudentName AS [text()]
FROM dbo.Students ST1
WHERE ST1.SubjectID = ST2.SubjectID
ORDER BY ST1.SubjectID
FOR XML PATH (''), TYPE
).value('text()[1]','nvarchar(max)'), 2, 1000) [Students]
FROM dbo.Students ST2
以下是实现这一目标的完整解决方案:
-- Table Creation
CREATE TABLE Tbl
( CustomerCode VARCHAR(50)
, CustomerName VARCHAR(50)
, Type VARCHAR(50)
,Items VARCHAR(50)
)
insert into Tbl
SELECT 'C0001','Thomas','BREAKFAST','Milk'
union SELECT 'C0001','Thomas','BREAKFAST','Bread'
union SELECT 'C0001','Thomas','BREAKFAST','Egg'
union SELECT 'C0001','Thomas','LUNCH','Rice'
union SELECT 'C0001','Thomas','LUNCH','Fish Curry'
union SELECT 'C0001','Thomas','LUNCH','Lessy'
union SELECT 'C0002','JOSEPH','BREAKFAST','Bread'
union SELECT 'C0002','JOSEPH','BREAKFAST','Jam'
union SELECT 'C0002','JOSEPH','BREAKFAST','Tea'
union SELECT 'C0002','JOSEPH','Supper','Tea'
union SELECT 'C0002','JOSEPH','Brunch','Roti'
-- function creation
GO
CREATE FUNCTION [dbo].[fn_GetItemsByType]
(
@CustomerCode VARCHAR(50)
,@Type VARCHAR(50)
)
RETURNS @ItemType TABLE ( Items VARCHAR(5000) )
AS
BEGIN
INSERT INTO @ItemType(Items)
SELECT STUFF((SELECT distinct ',' + [Items]
FROM Tbl
WHERE CustomerCode = @CustomerCode
AND Type=@Type
FOR XML PATH(''))
,1,1,'') as Items
RETURN
END
GO
-- fianl Query
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ',' + QUOTENAME(Type)
from Tbl
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT CustomerCode,CustomerName,' + @cols + '
from
(
select
distinct CustomerCode
,CustomerName
,Type
,F.Items
FROM Tbl T
CROSS APPLY [fn_GetItemsByType] (T.CustomerCode,T.Type) F
) x
pivot
(
max(Items)
for Type in (' + @cols + ')
) p '
execute(@query)
这对我有用(SQL Server 2016):
SELECT CarNamesString = STUFF((
SELECT ',' + [Name]
FROM tbl_cars
FOR XML PATH('')
), 1, 1, '')
来源如下:https://www.mytecbits.com/
还有一个针对MySQL的解决方案(因为该页面显示在Google for MySQL中):
SELECT [Name],
GROUP_CONCAT(DISTINCT [Name] SEPARATOR ',')
FROM tbl_cars
来自MySQL文档。
首先,您应该声明一个表变量并用表数据填充它,然后,使用WHILE循环,逐个选择行并将其值添加到nvarchar(max)变量中。
Go
declare @temp table(
title nvarchar(50)
)
insert into @temp(title)
select p.Title from dbo.person p
--
declare @mainString nvarchar(max)
set @mainString = '';
--
while ((select count(*) from @temp) != 0)
begin
declare @itemTitle nvarchar(50)
set @itemTitle = (select top(1) t.Title from @temp t)
if @mainString = ''
begin
set @mainString = @itemTitle
end
else
begin
set @mainString = concat(@mainString,',',@itemTitle)
end
delete top(1) from @temp
end
print @mainString