我创建了一些自定义元素,并希望以编程方式将它们放置在右上角(距离上边缘n个像素,距离右边缘m个像素)。因此,我需要获得屏幕宽度和屏幕高度,然后设置位置:

int px = screenWidth - m;
int py = screenHeight - n;

如何在主活动中获取screenWidth和screenHeight?


当前回答

以上代码已在API级别30中弃用。现在您可以使用以下代码

 val width = windowManager.currentWindowMetrics.bounds.width()
 val height = windowManager.currentWindowMetrics.bounds.height()

此方法报告包括所有系统栏区域的窗口大小,而Display#getSize(Point)报告不包括导航栏和显示剪切区域的区域。Display#getSize(Point)报告的值可通过以下方式获得:

 val metrics = windowManager.currentWindowMetrics
 // Gets all excluding insets
 val windowInsets = metrics.windowInsets
 var insets: Insets = windowInsets.getInsets(WindowInsets.Type.navigationBars())
 val cutout = windowInsets.displayCutout
 if (cutout != null) {
    val cutoutSafeInsets = Insets.of(cutout.safeInsetLeft, cutout.safeInsetTop, cutout.safeInsetRight, cutout.safeInsetBottom)
    insets = Insets.max(insets, cutoutSafeInsets)
 }

 val insetsWidth = insets.right + insets.left
 val insetsHeight = insets.top + insets.bottom

 // Legacy size that Display#getSize reports
 val legacySize =  Size(metrics.bounds.width() - insetsWidth, metrics.bounds.height() - insetsHeight)

来源:WindowManager#getCurrentWindowMetrics()

其他回答

如果您不想增加WindowManagers、Points或Displays的开销,可以获取XML中最顶层View项的高度和宽度属性,前提是其高度和宽度设置为match_parent。(只要您的布局占据整个屏幕,这是正确的。)

例如,如果您的XML以以下内容开头:

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:id="@+id/entireLayout"
    android:layout_width="match_parent"
    android:layout_height="match_parent" >

然后findViewById(R.id.entireLayout).getWidth()将返回屏幕的宽度,findViewById(R.id.entireLayout).getHeight()将显示屏幕的高度。

这不是OP的答案,因为他希望以真实像素显示尺寸。我想要“设备无关像素”的尺寸,并从这里汇总答案https://stackoverflow.com/a/17880012/253938在这里https://stackoverflow.com/a/6656774/253938我想到了这个:

    DisplayMetrics displayMetrics = Resources.getSystem().getDisplayMetrics();
    int dpHeight = (int)(displayMetrics.heightPixels / displayMetrics.density + 0.5);
    int dpWidth = (int)(displayMetrics.widthPixels / displayMetrics.density + 0.5);

有一种使用DisplayMetrics(API 1)来实现这一点的方法并不过时,它可以避免try/catch混乱:

 // initialize the DisplayMetrics object
 DisplayMetrics deviceDisplayMetrics = new DisplayMetrics();

 // populate the DisplayMetrics object with the display characteristics
 getWindowManager().getDefaultDisplay().getMetrics(deviceDisplayMetrics);

 // get the width and height
 screenWidth = deviceDisplayMetrics.widthPixels;
 screenHeight = deviceDisplayMetrics.heightPixels;
DisplayMetrics dimension = new DisplayMetrics();
getWindowManager().getDefaultDisplay().getMetrics(dimension);
int w = dimension.widthPixels;
int h = dimension.heightPixels;

此函数以英寸为单位返回近似屏幕大小。

public double getScreenSize()
{
        DisplayMetrics dm = new DisplayMetrics();
        getWindowManager().getDefaultDisplay().getMetrics(dm);
        int width=dm.widthPixels;
        int height=dm.heightPixels;
        int dens=dm.densityDpi;
        double wi=(double)width/(double)dens;
        double hi=(double)height/(double)dens;
        double x = Math.pow(wi,2);
        double y = Math.pow(hi,2);
        double screenInches = Math.sqrt(x+y);
        return screenInches;
}