使用Hibernate保存对象时收到以下错误
object references an unsaved transient instance - save the transient instance before flushing
使用Hibernate保存对象时收到以下错误
object references an unsaved transient instance - save the transient instance before flushing
当前回答
此错误的可能性非常多,其他一些可能性也出现在添加页或编辑页上。在我的案例中,我试图保存一个对象AdvanceSalary。问题是,在编辑AdvanceSalary employee.employee_id时为空,因为在编辑时我没有设置employee。
@Entity(name = "ic_advance_salary")
@Table(name = "ic_advance_salary")
public class AdvanceSalary extends BaseDO{
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Integer id;
@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name = "employee_id", nullable = false)
private Employee employee;
@Column(name = "employee_id", insertable=false, updatable=false)
@NotNull(message="Please enter employee Id")
private Long employee_id;
@Column(name = "advance_date")
@DateTimeFormat(pattern = "dd-MMM-yyyy")
@NotNull(message="Please enter advance date")
private Date advance_date;
@Column(name = "amount")
@NotNull(message="Please enter Paid Amount")
private Double amount;
@Column(name = "cheque_date")
@DateTimeFormat(pattern = "dd-MMM-yyyy")
private Date cheque_date;
@Column(name = "cheque_no")
private String cheque_no;
@Column(name = "remarks")
private String remarks;
public AdvanceSalary() {
}
public AdvanceSalary(Integer advance_salary_id) {
this.id = advance_salary_id;
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public Employee getEmployee() {
return employee;
}
public void setEmployee(Employee employee) {
this.employee = employee;
}
public Long getEmployee_id() {
return employee_id;
}
public void setEmployee_id(Long employee_id) {
this.employee_id = employee_id;
}
}
其他回答
不要使用Cascade.All,除非你真的需要。角色和权限具有双向manyToMany关系。那么下面的代码就可以正常工作了
Permission p = new Permission();
p.setName("help");
Permission p2 = new Permission();
p2.setName("self_info");
p = (Permission)crudRepository.save(p); // returned p has id filled in.
p2 = (Permission)crudRepository.save(p2); // so does p2.
Role role = new Role();
role.setAvailable(true);
role.setDescription("a test role");
role.setRole("admin");
List<Permission> pList = new ArrayList<Permission>();
pList.add(p);
pList.add(p2);
role.setPermissions(pList);
crudRepository.save(role);
而如果对象只是一个“新”对象,那么它将抛出相同的错误。
我刚刚收到这个错误,因为我在保存之前设置了一个未代理的实体而不是另一个实体。
我应该链接一个代理实体实例。
参见以下说明:
Child saved = childRepository.save(child);
// INCORRECT
parent.setChild(child); // <-- 'child' is NOT managed (not proxied)
// CORRECT
parent.setChild(saved); // <-- 'saved' is managed (proxied)
在我的例子中,这是由于双向关系的@ManyToOne一侧没有CascadeType导致的。更准确地说,我在@OneToMany端有CascadeType.ALL,而在@ManyToOne端没有。将CascadeType.ALL添加到@ManyToOne解决了该问题。一对多:
@OneToMany(cascade = CascadeType.ALL, mappedBy="globalConfig", orphanRemoval = true)
private Set<GlobalConfigScope>gcScopeSet;
多对一(导致问题)
@ManyToOne
@JoinColumn(name="global_config_id")
private GlobalConfig globalConfig;
多对一(通过添加CascadeType.PERSIST修复)
@ManyToOne(cascade = CascadeType.PERSIST)
@JoinColumn(name="global_config_id")
private GlobalConfig globalConfig;
如果您的集合可以为null,请尝试:object.SetYouColaction(null);
就我而言,问题完全不同。我有两节课,比如c1和c2。C1和C2之间的依赖关系是OneToMany。现在,如果我在DB中保存C1,它将抛出上述错误。
解决这个问题的方法是从消费者请求中获取第一个C2的id,然后通过存储库调用找到C2。然后将C2保存到C1对象中。现在,如果我保存C1,它可以正常工作。