使用Hibernate保存对象时收到以下错误

object references an unsaved transient instance - save the transient instance before flushing

当前回答

此错误的可能性非常多,其他一些可能性也出现在添加页或编辑页上。在我的案例中,我试图保存一个对象AdvanceSalary。问题是,在编辑AdvanceSalary employee.employee_id时为空,因为在编辑时我没有设置employee。

    @Entity(name = "ic_advance_salary")
    @Table(name = "ic_advance_salary")
    public class AdvanceSalary extends BaseDO{

        @Id
        @GeneratedValue(strategy = GenerationType.IDENTITY)
        @Column(name = "id")
        private Integer id;

        @ManyToOne(fetch = FetchType.EAGER)
        @JoinColumn(name = "employee_id", nullable = false)
        private Employee employee;

        @Column(name = "employee_id", insertable=false, updatable=false)
        @NotNull(message="Please enter employee Id")
        private Long employee_id;

        @Column(name = "advance_date")
        @DateTimeFormat(pattern = "dd-MMM-yyyy")
        @NotNull(message="Please enter advance date")
        private Date advance_date;

        @Column(name = "amount")
        @NotNull(message="Please enter Paid Amount")
        private Double amount;

        @Column(name = "cheque_date")
        @DateTimeFormat(pattern = "dd-MMM-yyyy")
        private Date cheque_date;

        @Column(name = "cheque_no")
        private String cheque_no;

        @Column(name = "remarks")
        private String remarks;

        public AdvanceSalary() {
        }

        public AdvanceSalary(Integer advance_salary_id) {
            this.id = advance_salary_id;
        }

        public Integer getId() {
            return id;
        }

        public void setId(Integer id) {
            this.id = id;
        }

        public Employee getEmployee() {
            return employee;
        }

        public void setEmployee(Employee employee) {
            this.employee = employee;
        }


        public Long getEmployee_id() {
            return employee_id;
        }

        public void setEmployee_id(Long employee_id) {
            this.employee_id = employee_id;
        }

    }

其他回答

不要使用Cascade.All,除非你真的需要。角色和权限具有双向manyToMany关系。那么下面的代码就可以正常工作了

    Permission p = new Permission();
    p.setName("help");
    Permission p2 = new Permission();
    p2.setName("self_info");
    p = (Permission)crudRepository.save(p); // returned p has id filled in.
    p2 = (Permission)crudRepository.save(p2); // so does p2.
    Role role = new Role();
    role.setAvailable(true);
    role.setDescription("a test role");
    role.setRole("admin");
    List<Permission> pList = new ArrayList<Permission>();
    pList.add(p);
    pList.add(p2);
    role.setPermissions(pList);
    crudRepository.save(role);

而如果对象只是一个“新”对象,那么它将抛出相同的错误。

我刚刚收到这个错误,因为我在保存之前设置了一个未代理的实体而不是另一个实体。

我应该链接一个代理实体实例。

参见以下说明:

Child saved = childRepository.save(child);

// INCORRECT
parent.setChild(child);  // <-- 'child' is NOT managed (not proxied)

// CORRECT
parent.setChild(saved);  // <-- 'saved' is managed (proxied)

在我的例子中,这是由于双向关系的@ManyToOne一侧没有CascadeType导致的。更准确地说,我在@OneToMany端有CascadeType.ALL,而在@ManyToOne端没有。将CascadeType.ALL添加到@ManyToOne解决了该问题。一对多:

@OneToMany(cascade = CascadeType.ALL, mappedBy="globalConfig", orphanRemoval = true)
private Set<GlobalConfigScope>gcScopeSet;

多对一(导致问题)

@ManyToOne
@JoinColumn(name="global_config_id")
private GlobalConfig globalConfig;

多对一(通过添加CascadeType.PERSIST修复)

@ManyToOne(cascade = CascadeType.PERSIST)
@JoinColumn(name="global_config_id")
private GlobalConfig globalConfig;

如果您的集合可以为null,请尝试:object.SetYouColaction(null);

就我而言,问题完全不同。我有两节课,比如c1和c2。C1和C2之间的依赖关系是OneToMany。现在,如果我在DB中保存C1,它将抛出上述错误。

解决这个问题的方法是从消费者请求中获取第一个C2的id,然后通过存储库调用找到C2。然后将C2保存到C1对象中。现在,如果我保存C1,它可以正常工作。