这实际上很简单，dateutil.relativelta.day=31将始终返回该月的最后一天：

import datetime
from dateutil.relativedelta import relativedelta

date_in_feb = datetime.datetime(2013, 2, 21)
print(datetime.datetime(2013, 2, 21) + relativedelta(day=31))  # End-of-month
# datetime.datetime(2013, 2, 28, 0, 0)

使用安装dateutil

pip install python-datetutil

你可以使用relativeltahttps://dateutil.readthedocs.io/en/stable/relativedelta.htmlmonth_end=<您当月的datetime值>+relativelta（day=31）这将给你最后一天。

最简单的方法（不必导入日历）是获取下个月的第一天，然后从中减去一天。

import datetime as dt
from dateutil.relativedelta import relativedelta

thisDate = dt.datetime(2017, 11, 17)

last_day_of_the_month = dt.datetime(thisDate.year, (thisDate + relativedelta(months=1)).month, 1) - dt.timedelta(days=1)
print last_day_of_the_month

输出：

datetime.datetime(2017, 11, 30, 0, 0)

PS：与导入日历方法相比，此代码运行速度更快；见下文：

import datetime as dt
import calendar
from dateutil.relativedelta import relativedelta

someDates = [dt.datetime.today() - dt.timedelta(days=x) for x in range(0, 10000)]

start1 = dt.datetime.now()
for thisDate in someDates:
    lastDay = dt.datetime(thisDate.year, (thisDate + relativedelta(months=1)).month, 1) - dt.timedelta(days=1)

print ('Time Spent= ', dt.datetime.now() - start1)


start2 = dt.datetime.now()
for thisDate in someDates:
    lastDay = dt.datetime(thisDate.year, 
                          thisDate.month, 
                          calendar.monthrange(thisDate.year, thisDate.month)[1])

print ('Time Spent= ', dt.datetime.now() - start2)

输出：

Time Spent=  0:00:00.097814
Time Spent=  0:00:00.109791

此代码假设您希望获得当月最后一天的日期（即，不只是DD部分，而是整个YYYYMMDD日期）

如果您需要获得一个月的第一天的0:00时间，并且不想导入任何特殊的库，您可以这样写

import pytz
from datetime import datetime, timedelta

# get now time with timezone (optional)
now = datetime.now(pytz.UTC)

# get first day on this month, get last day on prev month and after get first day on prev month with min time
fist_day_with_time = datetime.combine((now.replace(day=1) - timedelta(days=1)).replace(day=1), datetime.min.time())

2月28日至29日，12月至1月，以及另一个问题日期，工作正常。

对我来说，这是最简单的方法：

selected_date = date(some_year, some_month, some_day)

if selected_date.month == 12: # December
     last_day_selected_month = date(selected_date.year, selected_date.month, 31)
else:
     last_day_selected_month = date(selected_date.year, selected_date.month + 1, 1) - timedelta(days=1)

这是一个很长（容易理解）的版本，但考虑了闰年。

def last_day_month(year, month):
    leap_year_flag = 0
    end_dates = {
        1: 31,
        2: 28,
        3: 31,
        4: 30,
        5: 31,
        6: 30,
        7: 31,
        8: 31,
        9: 30,
        10: 31,
        11: 30,
        12: 31
    }

    # Checking for regular leap year    
    if year % 4 == 0:
        leap_year_flag = 1
    else:
        leap_year_flag = 0

    # Checking for century leap year    
    if year % 100 == 0:
        if year % 400 == 0:
            leap_year_flag = 1
        else:
            leap_year_flag = 0
    else:
        pass

    # return end date of the year-month
    if leap_year_flag == 1 and month == 2:
        return 29
    elif leap_year_flag == 1 and month != 2:
        return end_dates[month]
    else:
        return end_dates[month]