谁能告诉我如何在Swift中舍入一个双数值到x位小数点后数位?

我有:

var totalWorkTimeInHours = (totalWorkTime/60/60)

totalWorkTime是一个NSTimeInterval (double),单位为秒。

totalWorkTimeInHours会给我小时数,但它给我的时间量是如此长的精确数字,例如1.543240952039......

当我打印totalWorkTimeInHours时,我如何将其四舍五入到1.543 ?


当前回答

我会用

print(String(format: "%.3f", totalWorkTimeInHours))

然后把。3f改成任何你需要的十进制数

其他回答

Swift 4, Xcode 10

yourLabel.text =  String(format:"%.2f", yourDecimalValue)

在Swift 5.5和Xcode 13.2中:

let pi: Double = 3.14159265358979
String(format:"%.2f", pi)

例子:

附注:自Swift 2.0和Xcode 7.2以来一直如此

你可以添加这个扩展:

extension Double {
    var clean: String {
        return self.truncatingRemainder(dividingBy: 1) == 0 ? String(format: "%.0f", self) : String(format: "%.2f", self)
    }
}

像这样叫它:

let ex: Double = 10.123546789
print(ex.clean) // 10.12
//find the distance between two points
let coordinateSource = CLLocation(latitude: 30.7717625, longitude:76.5741449 )
let coordinateDestination = CLLocation(latitude: 29.9810859, longitude: 76.5663599)
let distanceInMeters = coordinateSource.distance(from: coordinateDestination)
let valueInKms = distanceInMeters/1000
let preciseValueUptoThreeDigit = Double(round(1000*valueInKms)/1000)
self.lblTotalDistance.text = "Distance is : \(preciseValueUptoThreeDigit) kms"

小数点后特定数字的代码为:

var a = 1.543240952039
var roundedString = String(format: "%.3f", a)

这里是%。3f告诉swift将这个数字四舍五入到小数点后3位。如果你想要双倍的数字,你可以使用这个代码:

//字符串为Double

var rounded弦= Double(字符串)(格式:%)。3f”,b型)