我如何以编程方式设置一个故事板的InitialViewController ?我想打开我的故事板到一个不同的视图这取决于不同的启动条件。
当前回答
使用Swift 3和Swift 4避免强制铸造的另一个解决方案是这样的
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
self.window = UIWindow(frame: UIScreen.main.bounds)
let storyboard = UIStoryboard(name: "Main", bundle: nil)
guard let viewController = storyboard.instantiateViewController(withIdentifier: "YourViewController") as? YourViewController else {
return false
}
self.window?.rootViewController = viewController
self.window?.makeKeyAndVisible()
return true
}
下面是使用UINavigationController
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
self.window = UIWindow(frame: UIScreen.main.bounds)
let storyboard = UIStoryboard(name: "Main", bundle: nil)
guard let viewController = storyboard.instantiateViewController(withIdentifier: "YourViewController") as? YourViewController else {
return false
}
let navigationController = UINavigationController(rootViewController: viewController)
self.window?.rootViewController = navigationController
self.window?.makeKeyAndVisible()
return true
}
其他回答
几天前我也遇到了同样的情况。一个非常简单的技巧解决了这个问题。 我设置在launch2之前隐藏我的初始视图控制器。如果初始视图控制器是正确的控制器,它在viewDidLoad中被设置为可见。否则,执行一个segue到所需的视图控制器。它在iOS 6.1及以上版本运行良好。我确信它适用于早期版本的iOS。
选择要首先打开的视图控制器,然后转到属性检查器。 转到初始场景,检查初始视图控制器选项。
这是你的初始视图控制器在应用启动时首先打开。
使用storyboard(而不是Main)设置初始ViewController
[Swift 5和Xcode 11]
主要。>属性检查器->取消勾选初始视图控制器 应用程序目标->通用->删除所有从主界面 编辑App委托
@main
class AppDelegate: UIResponder, UIApplicationDelegate {
var window: UIWindow?
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {
// Override point for customization after application launch.
self.window = UIWindow(frame: UIScreen.main.bounds)
let storyboard: UIStoryboard = UIStoryboard(name: "SomeStoryboard", bundle: nil) //SomeStoryboard is name of .storyboard
let viewController: ViewController = storyboard.instantiateViewController(withIdentifier: "someStoryboardId") as! ViewController //someStoryboardId is Storyboard ID
self.window?.rootViewController = viewController
self.window?.makeKeyAndVisible()
return true
}
}
在AppDelegate.swift中,你可以添加以下代码:
let sb = UIStoryboard(name: "Main", bundle: nil)
let vc = sb.instantiateViewController(withIdentifier: "YourViewController_StorboardID")
self.window?.rootViewController = vc
self.window?.makeKeyAndVisible()
当然,你需要实现你的逻辑,基于什么标准你将选择一个合适的视图控制器。
另外,不要忘记添加一个标识(select storyboard -> Controller Scene -> Show the identity inspector -> assign StorboardID)。
Swift 3:更新到@victor-sigler的代码
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
self.window = UIWindow(frame: UIScreen.main.bounds)
// Assuming your storyboard is named "Main"
let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
// Add code here (e.g. if/else) to determine which view controller class (chooseViewControllerA or chooseViewControllerB) and storyboard ID (chooseStoryboardA or chooseStoryboardB) to send the user to
if(condition){
let initialViewController: chooseViewControllerA = mainStoryboard.instantiateViewController(withIdentifier: "chooseStoryboardA") as! chooseViewControllerA
self.window?.rootViewController = initialViewController
)
}else{
let initialViewController: chooseViewControllerB = mainStoryboard.instantiateViewController(withIdentifier: "chooseStoryboardB") as! chooseViewControllerB
self.window?.rootViewController = initialViewController
)
self.window?.makeKeyAndVisible(
return true
}
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