如果你在iOS 13+中使用场景委托:

在你的信息中确认。Plist文件你发现行在:

Application Scene Manifest > Scene Configuration > Application Session Role > Item 0

并在那里删除对Main Storyboard的引用。否则，您将得到关于从storyboard实例化失败的相同警告。

同样，将代码从应用程序委托移动到场景委托方法scene(_:willConnectTo:options:)，因为这是现在处理生命周期事件的地方。

使用Swift 3和Swift 4避免强制铸造的另一个解决方案是这样的

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    self.window = UIWindow(frame: UIScreen.main.bounds)
    let storyboard = UIStoryboard(name: "Main", bundle: nil)
    guard let viewController = storyboard.instantiateViewController(withIdentifier: "YourViewController") as? YourViewController else {
        return false
    }
    self.window?.rootViewController = viewController
    self.window?.makeKeyAndVisible()
    return true
}

下面是使用UINavigationController

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    self.window = UIWindow(frame: UIScreen.main.bounds)
    let storyboard = UIStoryboard(name: "Main", bundle: nil)
    guard let viewController = storyboard.instantiateViewController(withIdentifier: "YourViewController") as? YourViewController else {
        return false
    }
    let navigationController = UINavigationController(rootViewController: viewController)
    self.window?.rootViewController = navigationController
    self.window?.makeKeyAndVisible()
    return true
}

我认为这是不可能的。 相反，你可以有一个初始控制器它有segue到不同的视图控制器。在启动时，您可以决定以编程方式执行哪个segue。

(UIApplication *)application willFinishLaunchingWithOptions:(NSDictionary *)launchOptions你可以通过编程方式设置(BOOL)应用程序中的关键窗口的rootViewController

例如:

- (BOOL)application:(UIApplication *)application willFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
    if (shouldShowAnotherViewControllerAsRoot) {
        UIStoryboard *storyboard = self.window.rootViewController.storyboard;
        UIViewController *rootViewController = [storyboard instantiateViewControllerWithIdentifier:@"rootNavigationController"];
        self.window.rootViewController = rootViewController;
        [self.window makeKeyAndVisible];
    }

    return YES;
}

let mainStoryboard = UIStoryboard(name: "Main", bundle: nil)
let vc = mainStoryboard.instantiateViewController(withIdentifier: "storyBoardid") as! ViewController
let navigationController = UINavigationController(rootViewController: vc)
UIApplication.shared.delegate.window?.rootViewController = navigationController

另一种方法是present viewController，

let mainStoryboard = UIStoryboard(name: "Main", bundle: nil)
let vc = mainStoryboard.instantiateViewController(withIdentifier: "storyBoardid") as! ViewController
self.present(vc,animated:true,completion:nil)

首先你需要创建storyboard的对象然后改变根(如果需要)然后你引用特定的视图控制器它会被推送当前视图控制器(如果你改变根)否则它会呈现新的视图控制器

几天前我也遇到了同样的情况。一个非常简单的技巧解决了这个问题。 我设置在launch2之前隐藏我的初始视图控制器。如果初始视图控制器是正确的控制器，它在viewDidLoad中被设置为可见。否则，执行一个segue到所需的视图控制器。它在iOS 6.1及以上版本运行良好。我确信它适用于早期版本的iOS。