我如何以编程方式设置一个故事板的InitialViewController ?我想打开我的故事板到一个不同的视图这取决于不同的启动条件。


当前回答

对于所有喜欢霉霉的人,下面是@Travis用Swift翻译的答案:

做@Travis在Objective C代码之前解释的事情。然后,

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {

    self.window = UIWindow(frame: UIScreen.mainScreen().bounds)
    let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
    var exampleViewController: ExampleViewController = mainStoryboard.instantiateViewControllerWithIdentifier("ExampleController") as! ExampleViewController

    self.window?.rootViewController = exampleViewController

    self.window?.makeKeyAndVisible()

    return true
}

ExampleViewController将是您想要显示的新的初始视图控制器。

步骤解释如下:

创建一个与当前窗口大小相同的新窗口,并将其设置为主窗口 实例化一个故事板,我们可以用它来创建新的初始视图控制器 基于Storyboard ID实例化我们新的初始视图控制器 将新窗口的根视图控制器设置为我们刚刚启动的新控制器 使新窗口可见

享受和快乐的编程!

其他回答

您可以使用接口生成器以及编程方式设置初始视图控制器。

下面是编程使用的方法。

objective - c:

        self.window = [[UIWindow alloc] initWithFrame:UIScreen.mainScreen.bounds];
        UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil];

        UIViewController *viewController = [storyboard instantiateViewControllerWithIdentifier:@"HomeViewController"]; // <storyboard id>

        self.window.rootViewController = viewController;
        [self.window makeKeyAndVisible];

        return YES;

迅速:

        self.window = UIWindow(frame: UIScreen.mainScreen().bounds)
        let mainStoryboard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)

        var objMainViewController: MainViewController = mainStoryboard.instantiateViewControllerWithIdentifier("MainController") as! MainViewController

        self.window?.rootViewController = objMainViewController

        self.window?.makeKeyAndVisible()

        return true

斯威夫特5

如果你没有一个ViewController设置为storyboard中的初始ViewController,你需要做两件事:

进入你的项目TARGETS,选择你的项目-> General ->清除Main Interface字段。 总是在项目TARGETS中,现在转到Info ->应用场景清单->场景配置->应用程序会话角色-> Item0(默认配置)->删除故事板名称字段。

最后,你现在可以在SceneDelegate中添加你的代码:

func scene(_ scene: UIScene, willConnectTo session: UISceneSession, options connectionOptions: UIScene.ConnectionOptions) {
    // Use this method to optionally configure and attach the UIWindow `window` to the provided UIWindowScene `scene`.
    // If using a storyboard, the `window` property will automatically be initialized and attached to the scene.
    // This delegate does not imply the connecting scene or session are new (see `application:configurationForConnectingSceneSession` instead).
    guard let windowScene = (scene as? UIWindowScene) else { return }

    window = UIWindow(windowScene: windowScene)


    let storyboard = UIStoryboard(name: "Main", bundle: nil)
    // Make sure you set an Storyboard ID for the view controller you want to instantiate
    window?.rootViewController = storyboard.instantiateViewController(withIdentifier: identifier)
    window?.makeKeyAndVisible()

}
let mainStoryboard = UIStoryboard(name: "Main", bundle: nil)
let vc = mainStoryboard.instantiateViewController(withIdentifier: "storyBoardid") as! ViewController
let navigationController = UINavigationController(rootViewController: vc)
UIApplication.shared.delegate.window?.rootViewController = navigationController

另一种方法是present viewController,

let mainStoryboard = UIStoryboard(name: "Main", bundle: nil)
let vc = mainStoryboard.instantiateViewController(withIdentifier: "storyBoardid") as! ViewController
self.present(vc,animated:true,completion:nil)

首先你需要创建storyboard的对象然后改变根(如果需要)然后你引用特定的视图控制器它会被推送当前视图控制器(如果你改变根)否则它会呈现新的视图控制器

选择要首先打开的视图控制器,然后转到属性检查器。 转到初始场景,检查初始视图控制器选项。

这是你的初始视图控制器在应用启动时首先打开。

Swift 5或以上版本#创建路由视图控制器 如果你使用xcode 11或以上版本,首先初始化var window: UIWindow?在AppDelegate

let rootVC = mainStoryboard.instantiateViewController(withIdentifier: "YOURCONTROLLER") as! YOURCONTROLLER

        navigationController.setNavigationBarHidden(true, animated: true)
        UIApplication.shared.windows.first?.rootViewController = UINavigationController.init(rootViewController: rootVC)
        UIApplication.shared.windows.first?.makeKeyAndVisible()