我需要在c++中加载和使用CSV文件数据。在这一点上,它实际上只是一个以逗号分隔的解析器(即不用担心转义新行和逗号)。主要需要的是逐行解析器,它将在每次调用方法时为下一行返回一个向量。
我发现这篇文章看起来很有前途: http://www.boost.org/doc/libs/1_35_0/libs/spirit/example/fundamental/list_parser.cpp
我从未使用过Boost's Spirit,但我愿意尝试一下。但前提是我忽略了一个更直接的解决方案。
我需要在c++中加载和使用CSV文件数据。在这一点上,它实际上只是一个以逗号分隔的解析器(即不用担心转义新行和逗号)。主要需要的是逐行解析器,它将在每次调用方法时为下一行返回一个向量。
我发现这篇文章看起来很有前途: http://www.boost.org/doc/libs/1_35_0/libs/spirit/example/fundamental/list_parser.cpp
我从未使用过Boost's Spirit,但我愿意尝试一下。但前提是我忽略了一个更直接的解决方案。
当前回答
如果您所需要的只是加载一个双精度数据文件(没有整数,没有文本),那么这里有一个随时可用的函数。
#include <sstream>
#include <fstream>
#include <iterator>
#include <string>
#include <vector>
#include <algorithm>
using namespace std;
/**
* Parse a CSV data file and fill the 2d STL vector "data".
* Limits: only "pure datas" of doubles, not encapsulated by " and without \n inside.
* Further no formatting in the data (e.g. scientific notation)
* It however handles both dots and commas as decimal separators and removes thousand separator.
*
* returnCodes[0]: file access 0-> ok 1-> not able to read; 2-> decimal separator equal to comma separator
* returnCodes[1]: number of records
* returnCodes[2]: number of fields. -1 If rows have different field size
*
*/
vector<int>
readCsvData (vector <vector <double>>& data, const string& filename, const string& delimiter, const string& decseparator){
int vv[3] = { 0,0,0 };
vector<int> returnCodes(&vv[0], &vv[0]+3);
string rowstring, stringtoken;
double doubletoken;
int rowcount=0;
int fieldcount=0;
data.clear();
ifstream iFile(filename, ios_base::in);
if (!iFile.is_open()){
returnCodes[0] = 1;
return returnCodes;
}
while (getline(iFile, rowstring)) {
if (rowstring=="") continue; // empty line
rowcount ++; //let's start with 1
if(delimiter == decseparator){
returnCodes[0] = 2;
return returnCodes;
}
if(decseparator != "."){
// remove dots (used as thousand separators)
string::iterator end_pos = remove(rowstring.begin(), rowstring.end(), '.');
rowstring.erase(end_pos, rowstring.end());
// replace decimal separator with dots.
replace(rowstring.begin(), rowstring.end(),decseparator.c_str()[0], '.');
} else {
// remove commas (used as thousand separators)
string::iterator end_pos = remove(rowstring.begin(), rowstring.end(), ',');
rowstring.erase(end_pos, rowstring.end());
}
// tokenize..
vector<double> tokens;
// Skip delimiters at beginning.
string::size_type lastPos = rowstring.find_first_not_of(delimiter, 0);
// Find first "non-delimiter".
string::size_type pos = rowstring.find_first_of(delimiter, lastPos);
while (string::npos != pos || string::npos != lastPos){
// Found a token, convert it to double add it to the vector.
stringtoken = rowstring.substr(lastPos, pos - lastPos);
if (stringtoken == "") {
tokens.push_back(0.0);
} else {
istringstream totalSString(stringtoken);
totalSString >> doubletoken;
tokens.push_back(doubletoken);
}
// Skip delimiters. Note the "not_of"
lastPos = rowstring.find_first_not_of(delimiter, pos);
// Find next "non-delimiter"
pos = rowstring.find_first_of(delimiter, lastPos);
}
if(rowcount == 1){
fieldcount = tokens.size();
returnCodes[2] = tokens.size();
} else {
if ( tokens.size() != fieldcount){
returnCodes[2] = -1;
}
}
data.push_back(tokens);
}
iFile.close();
returnCodes[1] = rowcount;
return returnCodes;
}
其他回答
不好意思,但是为了隐藏几行代码,这似乎是非常复杂的语法。
为什么不这样呢:
/**
Read line from a CSV file
@param[in] fp file pointer to open file
@param[in] vls reference to vector of strings to hold next line
*/
void readCSV( FILE *fp, std::vector<std::string>& vls )
{
vls.clear();
if( ! fp )
return;
char buf[10000];
if( ! fgets( buf,999,fp) )
return;
std::string s = buf;
int p,q;
q = -1;
// loop over columns
while( 1 ) {
p = q;
q = s.find_first_of(",\n",p+1);
if( q == -1 )
break;
vls.push_back( s.substr(p+1,q-p-1) );
}
}
int _tmain(int argc, _TCHAR* argv[])
{
std::vector<std::string> vls;
FILE * fp = fopen( argv[1], "r" );
if( ! fp )
return 1;
readCSV( fp, vls );
readCSV( fp, vls );
readCSV( fp, vls );
std::cout << "row 3, col 4 is " << vls[3].c_str() << "\n";
return 0;
}
@sastanin的解决方案的一个小版本,以便它可以处理引号中的换行。
std::vector<std::vector<std::string>> readCSV(std::istream &in) {
std::vector<std::vector<std::string>> table;
while (!in.eof()) {
CSVState state = CSVState::UnquotedField;
std::vector<std::string> fields {""};
size_t i = 0; // index of the current field
for (char c : row) {
switch (state) {
case CSVState::UnquotedField:
switch (c) {
case ',': // end of field
fields.push_back(""); i++;
break;
case '"': state = CSVState::QuotedField;
break;
default: fields[i].push_back(c);
break; }
break;
case CSVState::QuotedField:
switch (c) {
case '"': state = CSVState::QuotedQuote;
break;
default: fields[i].push_back(c);
break; }
break;
case CSVState::QuotedQuote:
switch (c) {
case ',': // , after closing quote
fields.push_back(""); i++;
state = CSVState::UnquotedField;
break;
case '"': // "" -> "
fields[i].push_back('"');
state = CSVState::QuotedField;
break;
case '\n': // newline
table.push_back(fields);
state = CSVState::UnquotedField;
fields = vector<string>{""};
i = 0;
default: // end of quote
state = CSVState::UnquotedField;
break; }
break;
}
}
}
return table;
}
c++ String工具箱库(StrTk)有一个令牌网格类,它允许你从文本文件、字符串或字符缓冲区加载数据,并以行-列的方式解析/处理它们。
您可以指定行分隔符和列分隔符,或者只使用默认值。
void foo()
{
std::string data = "1,2,3,4,5\n"
"0,2,4,6,8\n"
"1,3,5,7,9\n";
strtk::token_grid grid(data,data.size(),",");
for(std::size_t i = 0; i < grid.row_count(); ++i)
{
strtk::token_grid::row_type r = grid.row(i);
for(std::size_t j = 0; j < r.size(); ++j)
{
std::cout << r.get<int>(j) << "\t";
}
std::cout << std::endl;
}
std::cout << std::endl;
}
更多的例子可以在这里找到
您还可以看看Qt库的功能。
它有正则表达式支持,QString类有很好的方法,例如split()返回QStringList,通过使用提供的分隔符分割原始字符串获得的字符串列表。应该足以为csv文件..
要获得具有给定标题名的列,我使用以下方法:c++继承Qt问题qstring
使用Boost Tokenizer的解决方案:
std::vector<std::string> vec;
using namespace boost;
tokenizer<escaped_list_separator<char> > tk(
line, escaped_list_separator<char>('\\', ',', '\"'));
for (tokenizer<escaped_list_separator<char> >::iterator i(tk.begin());
i!=tk.end();++i)
{
vec.push_back(*i);
}