我需要在c++中加载和使用CSV文件数据。在这一点上，它实际上只是一个以逗号分隔的解析器(即不用担心转义新行和逗号)。主要需要的是逐行解析器，它将在每次调用方法时为下一行返回一个向量。
我发现这篇文章看起来很有前途: http://www.boost.org/doc/libs/1_35_0/libs/spirit/example/fundamental/list_parser.cpp
我从未使用过Boost's Spirit，但我愿意尝试一下。但前提是我忽略了一个更直接的解决方案。
当前回答
由于我现在不习惯boost，我将建议一个更简单的解决方案。假设您的.csv文件有100行，每行有10个数字，用“，”分隔。你可以用下面的代码以数组的形式加载这个数据:
#include <iostream>
#include <fstream>
#include <sstream>
#include <string>
using namespace std;
int main()
{
int A[100][10];
ifstream ifs;
ifs.open("name_of_file.csv");
string s1;
char c;
for(int k=0; k<100; k++)
{
getline(ifs,s1);
stringstream stream(s1);
int j=0;
while(1)
{
stream >>A[k][j];
stream >> c;
j++;
if(!stream) {break;}
}
}
}
其他回答
当你使用boost::spirit这样漂亮的东西时，你应该感到自豪
这里我的一个解析器的尝试(几乎)符合这个链接的CSV规范(我不需要在字段中换行)。逗号周围的空格也被省略了)。
在你克服了编译这段代码需要等待10秒的令人震惊的经历之后:)，你就可以坐下来享受了。
// csvparser.cpp
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
#include <iostream>
#include <string>
namespace qi = boost::spirit::qi;
namespace bascii = boost::spirit::ascii;
template <typename Iterator>
struct csv_parser : qi::grammar<Iterator, std::vector<std::string>(),
bascii::space_type>
{
qi::rule<Iterator, char() > COMMA;
qi::rule<Iterator, char() > DDQUOTE;
qi::rule<Iterator, std::string(), bascii::space_type > non_escaped;
qi::rule<Iterator, std::string(), bascii::space_type > escaped;
qi::rule<Iterator, std::string(), bascii::space_type > field;
qi::rule<Iterator, std::vector<std::string>(), bascii::space_type > start;
csv_parser() : csv_parser::base_type(start)
{
using namespace qi;
using qi::lit;
using qi::lexeme;
using bascii::char_;
start = field % ',';
field = escaped | non_escaped;
escaped = lexeme['"' >> *( char_ -(char_('"') | ',') | COMMA | DDQUOTE) >> '"'];
non_escaped = lexeme[ *( char_ -(char_('"') | ',') ) ];
DDQUOTE = lit("\"\"") [_val = '"'];
COMMA = lit(",") [_val = ','];
}
};
int main()
{
std::cout << "Enter CSV lines [empty] to quit\n";
using bascii::space;
typedef std::string::const_iterator iterator_type;
typedef csv_parser<iterator_type> csv_parser;
csv_parser grammar;
std::string str;
int fid;
while (getline(std::cin, str))
{
fid = 0;
if (str.empty())
break;
std::vector<std::string> csv;
std::string::const_iterator it_beg = str.begin();
std::string::const_iterator it_end = str.end();
bool r = phrase_parse(it_beg, it_end, grammar, space, csv);
if (r && it_beg == it_end)
{
std::cout << "Parsing succeeded\n";
for (auto& field: csv)
{
std::cout << "field " << ++fid << ": " << field << std::endl;
}
}
else
{
std::cout << "Parsing failed\n";
}
}
return 0;
}
编译:
make csvparser
测试(例子摘自维基百科):
./csvparser
Enter CSV lines [empty] to quit
1999,Chevy,"Venture ""Extended Edition, Very Large""",,5000.00
Parsing succeeded
field 1: 1999
field 2: Chevy
field 3: Venture "Extended Edition, Very Large"
field 4:
field 5: 5000.00
1999,Chevy,"Venture ""Extended Edition, Very Large""",,5000.00"
Parsing failed
这是一个旧线程，但它仍然在搜索结果的顶部，所以我添加我的解决方案使用std::stringstream和一个简单的字符串替换方法由Yves Baumes我在这里找到。
下面的例子将逐行读取文件，忽略以//开头的注释行，并将其他行解析为字符串、int和double的组合。Stringstream进行解析，但希望字段由空格分隔，因此我使用stringreplace首先将逗号转换为空格。它可以处理制表符，但不处理带引号的字符串。
坏的或丢失的输入被简单地忽略，这可能是好事，也可能不是好事，这取决于您的情况。
#include <string>
#include <sstream>
#include <fstream>
void StringReplace(std::string& str, const std::string& oldStr, const std::string& newStr)
// code by Yves Baumes
// http://stackoverflow.com/questions/1494399/how-do-i-search-find-and-replace-in-a-standard-string
{
size_t pos = 0;
while((pos = str.find(oldStr, pos)) != std::string::npos)
{
str.replace(pos, oldStr.length(), newStr);
pos += newStr.length();
}
}
void LoadCSV(std::string &filename) {
std::ifstream stream(filename);
std::string in_line;
std::string Field;
std::string Chan;
int ChanType;
double Scale;
int Import;
while (std::getline(stream, in_line)) {
StringReplace(in_line, ",", " ");
std::stringstream line(in_line);
line >> Field >> Chan >> ChanType >> Scale >> Import;
if (Field.substr(0,2)!="//") {
// do your stuff
// this is CBuilder code for demonstration, sorry
ShowMessage((String)Field.c_str() + "\n" + Chan.c_str() + "\n" + IntToStr(ChanType) + "\n" +FloatToStr(Scale) + "\n" +IntToStr(Import));
}
}
}
你可能想看看我的自由/开源软件项目CSVfix(更新链接)，这是一个用c++编写的CSV流编辑器。CSV解析器不是什么好东西，但它完成了工作，整个包可以在不编写任何代码的情况下满足您的需要。
CSV解析器请参见alib/src/a_csv.cpp，使用示例请参见csvlib/src/csved_ioman.cpp (IOManager::ReadCSV)。
不管怎样，下面是我的实现。它处理wstring输入，但是可以很容易地调整为string。它不处理字段中的换行符(因为我的应用程序也不这样做，但添加它的支持并不太难)，它不符合RFC中的“\r\n”行尾(假设您使用std::getline)，但它确实正确地处理空格修剪和双引号(希望如此)。
using namespace std;
// trim whitespaces around field or double-quotes, remove double-quotes and replace escaped double-quotes (double double-quotes)
wstring trimquote(const wstring& str, const wstring& whitespace, const wchar_t quotChar)
{
wstring ws;
wstring::size_type strBegin = str.find_first_not_of(whitespace);
if (strBegin == wstring::npos)
return L"";
wstring::size_type strEnd = str.find_last_not_of(whitespace);
wstring::size_type strRange = strEnd - strBegin + 1;
if((str[strBegin] == quotChar) && (str[strEnd] == quotChar))
{
ws = str.substr(strBegin+1, strRange-2);
strBegin = 0;
while((strEnd = ws.find(quotChar, strBegin)) != wstring::npos)
{
ws.erase(strEnd, 1);
strBegin = strEnd+1;
}
}
else
ws = str.substr(strBegin, strRange);
return ws;
}
pair<unsigned, unsigned> nextCSVQuotePair(const wstring& line, const wchar_t quotChar, unsigned ofs = 0)
{
pair<unsigned, unsigned> r;
r.first = line.find(quotChar, ofs);
r.second = wstring::npos;
if(r.first != wstring::npos)
{
r.second = r.first;
while(((r.second = line.find(quotChar, r.second+1)) != wstring::npos)
&& (line[r.second+1] == quotChar)) // WARNING: assumes null-terminated string such that line[r.second+1] always exist
r.second++;
}
return r;
}
unsigned parseLine(vector<wstring>& fields, const wstring& line)
{
unsigned ofs, ofs0, np;
const wchar_t delim = L',';
const wstring whitespace = L" \t\xa0\x3000\x2000\x2001\x2002\x2003\x2004\x2005\x2006\x2007\x2008\x2009\x200a\x202f\x205f";
const wchar_t quotChar = L'\"';
pair<unsigned, unsigned> quot;
fields.clear();
ofs = ofs0 = 0;
quot = nextCSVQuotePair(line, quotChar);
while((np = line.find(delim, ofs)) != wstring::npos)
{
if((np > quot.first) && (np < quot.second))
{ // skip delimiter inside quoted field
ofs = quot.second+1;
quot = nextCSVQuotePair(line, quotChar, ofs);
continue;
}
fields.push_back( trimquote(line.substr(ofs0, np-ofs0), whitespace, quotChar) );
ofs = ofs0 = np+1;
}
fields.push_back( trimquote(line.substr(ofs0), whitespace, quotChar) );
return fields.size();
}
就像每个人都把他的解决方案，这里是我的使用模板，lambda和tuple。
它可以将任何具有所需列的CSV转换为tuple的c++向量。
它通过在元组中定义每个CSV行元素类型来工作。
您还需要为每个元素定义std::string到类型转换Formatter lambda(例如使用std::atod)。
然后你就得到了这个结构的一个向量，对应于你的CSV数据。
您可以很容易地重用它来匹配任何CSV结构。
StringsHelpers.hpp
#include <string>
#include <fstream>
#include <vector>
#include <functional>
namespace StringHelpers
{
template<typename Tuple>
using Formatter = std::function<Tuple(const std::vector<std::string> &)>;
std::vector<std::string> split(const std::string &string, const std::string &delimiter);
template<typename Tuple>
std::vector<Tuple> readCsv(const std::string &path, const std::string &delimiter, Formatter<Tuple> formatter);
};
StringsHelpers.cpp
#include "StringHelpers.hpp"
namespace StringHelpers
{
/**
* Split a string with the given delimiter into several strings
*
* @param string - The string to extract the substrings from
* @param delimiter - The substrings delimiter
*
* @return The substrings
*/
std::vector<std::string> split(const std::string &string, const std::string &delimiter)
{
std::vector<std::string> result;
size_t last = 0,
next = 0;
while ((next = string.find(delimiter, last)) != std::string::npos) {
result.emplace_back(string.substr(last, next - last));
last = next + 1;
}
result.emplace_back(string.substr(last));
return result;
}
/**
* Read a CSV file and store its values into the given structure (Tuple with Formatter constructor)
*
* @tparam Tuple - The CSV line structure format
*
* @param path - The CSV file path
* @param delimiter - The CSV values delimiter
* @param formatter - The CSV values formatter that take a vector of strings in input and return a Tuple
*
* @return The CSV as vector of Tuple
*/
template<typename Tuple>
std::vector<Tuple> readCsv(const std::string &path, const std::string &delimiter, Formatter<Tuple> formatter)
{
std::ifstream file(path, std::ifstream::in);
std::string line;
std::vector<Tuple> result;
if (file.fail()) {
throw std::runtime_error("The file " + path + " could not be opened");
}
while (std::getline(file, line)) {
result.emplace_back(formatter(split(line, delimiter)));
}
file.close();
return result;
}
// Forward template declarations
template std::vector<std::tuple<double, double, double>> readCsv<std::tuple<double, double, double>>(const std::string &, const std::string &, Formatter<std::tuple<double, double, double>>);
} // End of StringHelpers namespace
Main.cpp(一些用法)
#include "StringHelpers.hpp"
/**
* Example of use with a CSV file which have (number,Red,Green,Blue) as line values. We do not want to use the 1st value
* of the line.
*/
int main(int argc, char **argv)
{
// Declare CSV line type, formatter and template type
typedef std::tuple<double, double, double> CSV_format;
typedef std::function<CSV_format(const std::vector<std::string> &)> formatterT;
enum RGB { Red = 1, Green, Blue };
const std::string COLOR_MAP_PATH = "/some/absolute/path";
// Load the color map
auto colorMap = StringHelpers::readCsv<CSV_format>(COLOR_MAP_PATH, ",", [](const std::vector<std::string> &values) {
return CSV_format {
// Here is the formatter lambda that convert each value from string to what you want
std::strtod(values[Red].c_str(), nullptr),
std::strtod(values[Green].c_str(), nullptr),
std::strtod(values[Blue].c_str(), nullptr)
};
});
// Use your colorMap as you wish...
}
