非常直截了当。在javascript中,我需要检查字符串是否包含数组中持有的任何子字符串。


当前回答

function containsAny(str, substrings) {
    for (var i = 0; i != substrings.length; i++) {
       var substring = substrings[i];
       if (str.indexOf(substring) != - 1) {
         return substring;
       }
    }
    return null; 
}

var result = containsAny("defg", ["ab", "cd", "ef"]);
console.log("String was found in substring " + result);

其他回答

convert_to_array = function (sentence) {
     return sentence.trim().split(" ");
};

let ages = convert_to_array ("I'm a programmer in javascript writing script");

function confirmEnding(string) {
let target = "ipt";
    return  (string.substr(-target.length) === target) ? true : false;
}

function mySearchResult() {
return ages.filter(confirmEnding);
}

mySearchResult();

您可以像这样检查并使用过滤器返回匹配单词的数组

以下是目前为止(在我看来)最好的解决方案。这是一个现代的(ES6)解决方案,它:

是高效的(一行!) 避免for循环 与其他答案中使用的some()函数不同,这个函数不仅返回一个布尔值(true/false) 相反,它要么返回子字符串(如果它在数组中找到),要么返回undefined 更进一步,允许您选择是否需要部分子字符串匹配(示例如下)

享受吧!



const arrayOfStrings = ['abc', 'def', 'xyz'];
const str = 'abc';
const found = arrayOfStrings.find(v => (str === v));

在这里,found将被设置为'abc'。这将适用于精确的字符串匹配。

如果你用:

const found = arrayOfStrings.find(v => str.includes(v));

同样,found在本例中被设置为'abc'。这不允许部分匹配,所以如果str被设置为'ab', found将是未定义的。


And, if you want partial matches to work, simply flip it so you're doing:
const found = arrayOfStrings.find(v => v.includes(str));

代替。如果str被设为'ab' found就会被设为'abc'

容易peasy !



var str = "texttexttext";
var arr = ["asd", "ghj", "xtte"];
for (var i = 0, len = arr.length; i < len; ++i) {
    if (str.indexOf(arr[i]) != -1) {
        // str contains arr[i]
    }
}

编辑: 如果测试的顺序不重要,你可以使用这个(只有一个循环变量):

var str = "texttexttext";
var arr = ["asd", "ghj", "xtte"];
for (var i = arr.length - 1; i >= 0; --i) {
    if (str.indexOf(arr[i]) != -1) {
        // str contains arr[i]
    }
}

使用underscore.js或lodash.js,你可以对字符串数组执行以下操作:

var contacts = ['Billy Bob', 'John', 'Bill', 'Sarah'];

var filters = ['Bill', 'Sarah'];

contacts = _.filter(contacts, function(contact) {
    return _.every(filters, function(filter) { return (contact.indexOf(filter) === -1); });
});

// ['John']

在一个字符串上:

var contact = 'Billy';
var filters = ['Bill', 'Sarah'];

_.every(filters, function(filter) { return (contact.indexOf(filter) >= 0); });

// true

我并不是建议你去扩展/修改String的原型,但这是我所做的:

String.prototype.includes ()

String.prototype.includes = function (includes) { console.warn("String.prototype.includes() has been modified."); return function (searchString, position) { if (searchString instanceof Array) { for (var i = 0; i < searchString.length; i++) { if (includes.call(this, searchString[i], position)) { return true; } } return false; } else { return includes.call(this, searchString, position); } } }(String.prototype.includes); console.log('"Hello, World!".includes("foo");', "Hello, World!".includes("foo") ); // false console.log('"Hello, World!".includes(",");', "Hello, World!".includes(",") ); // true console.log('"Hello, World!".includes(["foo", ","])', "Hello, World!".includes(["foo", ","]) ); // true console.log('"Hello, World!".includes(["foo", ","], 6)', "Hello, World!".includes(["foo", ","], 6) ); // false