非常直截了当。在javascript中,我需要检查字符串是否包含数组中持有的任何子字符串。


当前回答

如果数组不大,可以使用indexOf()循环并逐个检查每个子字符串。或者,您可以构造一个带有子字符串作为替代的正则表达式,这可能更有效,也可能不更有效。

其他回答

Javascript函数使用搜索字符串或搜索字符串数组搜索标签或关键字数组。(使用ES5的一些数组方法和ES6的箭头函数)

// returns true for 1 or more matches, where 'a' is an array and 'b' is a search string or an array of multiple search strings
function contains(a, b) {
    // array matches
    if (Array.isArray(b)) {
        return b.some(x => a.indexOf(x) > -1);
    }
    // string match
    return a.indexOf(b) > -1;
}

使用示例:

var a = ["a","b","c","d","e"];
var b = ["a","b"];
if ( contains(a, b) ) {
    // 1 or more matches found
}

对于用谷歌搜索的人来说,

确切的答案应该是。

const substrings = ['connect', 'ready'];
const str = 'disconnect';
if (substrings.some(v => str === v)) {
   // Will only return when the `str` is included in the `substrings`
}
convert_to_array = function (sentence) {
     return sentence.trim().split(" ");
};

let ages = convert_to_array ("I'm a programmer in javascript writing script");

function confirmEnding(string) {
let target = "ipt";
    return  (string.substr(-target.length) === target) ? true : false;
}

function mySearchResult() {
return ages.filter(confirmEnding);
}

mySearchResult();

您可以像这样检查并使用过滤器返回匹配单词的数组

你可以这样检查:

<!DOCTYPE html>
<html>
   <head>
      <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
      <script>
         $(document).ready(function(){
         var list = ["bad", "words", "include"] 
         var sentence = $("#comments_text").val()

         $.each(list, function( index, value ) {
           if (sentence.indexOf(value) > -1) {
                console.log(value)
            }
         });
         });
      </script>
   </head>
   <body>
      <input id="comments_text" value="This is a bad, with include test"> 
   </body>
</html>

使用underscore.js或lodash.js,你可以对字符串数组执行以下操作:

var contacts = ['Billy Bob', 'John', 'Bill', 'Sarah'];

var filters = ['Bill', 'Sarah'];

contacts = _.filter(contacts, function(contact) {
    return _.every(filters, function(filter) { return (contact.indexOf(filter) === -1); });
});

// ['John']

在一个字符串上:

var contact = 'Billy';
var filters = ['Bill', 'Sarah'];

_.every(filters, function(filter) { return (contact.indexOf(filter) >= 0); });

// true