是否有任何方法关闭我的JavaScript代码中的所有console.log语句,用于测试目的?


当前回答

当使用React时,你可以利用钩子来管理它,这样它就被限制在你的组件范围内

import { useEffect, useRef } from "react";

type LoggingReplacements = {
  debug?: typeof console["debug"];
  error?: typeof console["error"];
  info?: typeof console["info"];
  log?: typeof console["log"];
  warn?: typeof console["warn"];
};
/**
 * This replaces console.XXX loggers with custom implementations.  It will restore console log on unmount of the component.
 * @param replacements a map of replacement loggers.  They're all optional and only the functions defined will be replaced.
 */
export function useReplaceLogging({
  debug,
  error,
  info,
  log,
  warn,
}: LoggingReplacements): void {
  const originalConsoleDebug = useRef(console.debug);
  const originalConsoleError = useRef(console.error);
  const originalConsoleInfo = useRef(console.info);
  const originalConsoleLog = useRef(console.log);
  const originalConsoleWarn = useRef(console.warn);
  if (debug) {
    console.debug = debug;
  }
  if (error) {
    console.error = error;
  }
  if (info) {
    console.info = info;
  }
  if (log) {
    console.log = log;
  }
  if (warn) {
    console.warn = warn;
  }
  useEffect(() => {
    return function restoreConsoleLog() {
      console.debug = originalConsoleDebug.current;
      console.error = originalConsoleError.current;
      console.info = originalConsoleInfo.current;
      console.log = originalConsoleLog.current;
      console.warn = originalConsoleWarn.current;
    };
  }, []);
}

在https://github.com/trajano/react-hooks/tree/master/src/useReplaceLogging上编写测试代码

其他回答

当使用React时,你可以利用钩子来管理它,这样它就被限制在你的组件范围内

import { useEffect, useRef } from "react";

type LoggingReplacements = {
  debug?: typeof console["debug"];
  error?: typeof console["error"];
  info?: typeof console["info"];
  log?: typeof console["log"];
  warn?: typeof console["warn"];
};
/**
 * This replaces console.XXX loggers with custom implementations.  It will restore console log on unmount of the component.
 * @param replacements a map of replacement loggers.  They're all optional and only the functions defined will be replaced.
 */
export function useReplaceLogging({
  debug,
  error,
  info,
  log,
  warn,
}: LoggingReplacements): void {
  const originalConsoleDebug = useRef(console.debug);
  const originalConsoleError = useRef(console.error);
  const originalConsoleInfo = useRef(console.info);
  const originalConsoleLog = useRef(console.log);
  const originalConsoleWarn = useRef(console.warn);
  if (debug) {
    console.debug = debug;
  }
  if (error) {
    console.error = error;
  }
  if (info) {
    console.info = info;
  }
  if (log) {
    console.log = log;
  }
  if (warn) {
    console.warn = warn;
  }
  useEffect(() => {
    return function restoreConsoleLog() {
      console.debug = originalConsoleDebug.current;
      console.error = originalConsoleError.current;
      console.info = originalConsoleInfo.current;
      console.log = originalConsoleLog.current;
      console.warn = originalConsoleWarn.current;
    };
  }, []);
}

在https://github.com/trajano/react-hooks/tree/master/src/useReplaceLogging上编写测试代码

我之前用过温斯顿记录器。

现在,我使用以下简单的代码从经验:

从cmd/命令行设置环境变量(在Windows上): cmd setx LOG_LEVEL信息

或者,如果你愿意,你可以在你的代码中有一个变量,但上面更好。

Restart cmd/ command line, or, IDE/ editor like Netbeans Have below like code: console.debug = console.log; // define debug function console.silly = console.log; // define silly function switch (process.env.LOG_LEVEL) { case 'debug': case 'silly': // print everything break; case 'dir': case 'log': console.debug = function () {}; console.silly = function () {}; break; case 'info': console.debug = function () {}; console.silly = function () {}; console.dir = function () {}; console.log = function () {}; break; case 'trace': // similar to error, both may print stack trace/ frames case 'warn': // since warn() function is an alias for error() case 'error': console.debug = function () {}; console.silly = function () {}; console.dir = function () {}; console.log = function () {}; console.info = function () {}; break; } Now use all console.* as below: console.error(' this is a error message '); // will print console.warn(' this is a warn message '); // will print console.trace(' this is a trace message '); // will print console.info(' this is a info message '); // will print, LOG_LEVEL is set to this console.log(' this is a log message '); // will NOT print console.dir(' this is a dir message '); // will NOT print console.silly(' this is a silly message '); // will NOT print console.debug(' this is a debug message '); // will NOT print

现在,根据点1中的LOG_LEVEL设置(例如,setx LOG_LEVEL日志和重新启动命令行),上面的一些将打印,其他将不打印

希望这有帮助。

我知道你问如何禁用console.log,但这可能是你真正想要的。这样就不必显式地启用或禁用控制台。它只是为那些没有打开或安装它的人防止那些讨厌的控制台错误。

if(typeof(console) === 'undefined') {
    var console = {};
    console.log = console.error = console.info = console.debug = console.warn = console.trace = console.dir = console.dirxml = console.group = console.groupEnd = console.time = console.timeEnd = console.assert = console.profile = function() {};
}
console.log('pre');
/* pre content */ 
// define a new console
let preconsole = Object.assign({}, window.console);
let aftconsole = Object.assign({}, window.console, {
    log: function(text){
        preconsole.log(text);
        preconsole.log('log');
    }
});
console = aftconsole;
/* content */

console.log('content');

/* end of content */
console = preconsole;
console.log('aft');

令我惊讶的是,在所有这些答案中,没有人把它们结合起来:

没有jquery 匿名函数不污染全局命名空间 窗口的句柄情况。控制台未定义 只需修改控制台的.log函数

我会选这个:

(function () {

    var debug = false

    if (debug === false) {
        if ( typeof(window.console) === 'undefined') { window.console = {}; }
        window.console.log = function () {};
    }
})()