This is what I did. What I've done differently is use the same name and the new keyword on the "consuming" enum. Since the name of the enum is the same, you can just mindlessly use it and it will be right. Plus you get intellisense. You just have to manually take care when setting it up that the values are copied over from the base and keep them sync'ed. You can help that along with code comments. This is another reason why in the database when storing enum values I always store the string, not the value. Because if you are using automatically assigned increasing integer values those can change over time.

// Base Class for balls 
public class Ball
{
    // keep synced with subclasses!
    public enum Sizes
    {
        Small,
        Medium,
        Large
    }
}

public class VolleyBall : Ball
{
    // keep synced with base class!
    public new enum Sizes
    {
        Small  = Ball.Sizes.Small,
        Medium = Ball.Sizes.Medium,
        Large  = Ball.Sizes.Large,
        SmallMedium,
        MediumLarge,
        Ginormous
    }
}

上述使用int常量类的解决方案缺乏类型安全。也就是说，你可以发明一些在课堂上没有定义的新值。 此外，举例来说，编写以这些类之一作为输入的方法是不可能的。

你需要写

public void DoSomethingMeaningFull(int consumeValue) ...

但是，在以前的Java中有一个基于类的解决方案，当时没有可用的枚举。这提供了几乎类似枚举的行为。唯一需要注意的是，这些常量不能在switch语句中使用。

public class MyBaseEnum
{
    public static readonly MyBaseEnum A = new MyBaseEnum( 1 );
    public static readonly MyBaseEnum B = new MyBaseEnum( 2 );
    public static readonly MyBaseEnum C = new MyBaseEnum( 3 );

    public int InternalValue { get; protected set; }

    protected MyBaseEnum( int internalValue )
    {
        this.InternalValue = internalValue;
    }
}

public class MyEnum : MyBaseEnum
{
    public static readonly MyEnum D = new MyEnum( 4 );
    public static readonly MyEnum E = new MyEnum( 5 );

    protected MyEnum( int internalValue ) : base( internalValue )
    {
        // Nothing
    }
}

[TestMethod]
public void EnumTest()
{
    this.DoSomethingMeaningful( MyEnum.A );
}

private void DoSomethingMeaningful( MyBaseEnum enumValue )
{
    // ...
    if( enumValue == MyEnum.A ) { /* ... */ }
    else if (enumValue == MyEnum.B) { /* ... */ }
    // ...
}

你可以通过类实现你想要的:

public class Base
{
    public const int A = 1;
    public const int B = 2;
    public const int C = 3;
}
public class Consume : Base
{
    public const int D = 4;
    public const int E = 5;
}

现在你可以像使用枚举一样使用这些类:

int i = Consume.B;

更新(在您更新问题后):

如果你将相同的int值赋给现有枚举中定义的常量，那么你可以在枚举和常量之间进行类型转换，例如:

public enum SomeEnum // this is the existing enum (from WSDL)
{
    A = 1,
    B = 2,
    ...
}
public class Base
{
    public const int A = (int)SomeEnum.A;
    //...
}
public class Consume : Base
{
    public const int D = 4;
    public const int E = 5;
}

// where you have to use the enum, use a cast:
SomeEnum e = (SomeEnum)Consume.B;

这是不可能的(正如@JaredPar已经提到的)。试图用逻辑来解决这个问题是一种糟糕的做法。如果你有一个有枚举的基类，你应该列出所有可能的枚举值，并且类的实现应该使用它知道的值。

例如:假设你有一个基类BaseCatalog，它有一个枚举ProductFormats (Digital, Physical)。然后，您可以有一个MusicCatalog或BookCatalog，可以包含数字和物理产品，但如果类是ClothingCatalog，它应该只包含物理产品。

我知道这个回答有点晚了，但这就是我最后做的:

public class BaseAnimal : IEquatable<BaseAnimal>
{
    public string Name { private set; get; }
    public int Value { private set; get; }

    public BaseAnimal(int value, String name)
    {
        this.Name = name;
        this.Value = value;
    }

    public override String ToString()
    {
        return Name;
    }

    public bool Equals(BaseAnimal other)
    {
        return other.Name == this.Name && other.Value == this.Value;
    }
}

public class AnimalType : BaseAnimal
{
    public static readonly BaseAnimal Invertebrate = new BaseAnimal(1, "Invertebrate");

    public static readonly BaseAnimal Amphibians = new BaseAnimal(2, "Amphibians");

    // etc        
}

public class DogType : AnimalType
{
    public static readonly BaseAnimal Golden_Retriever = new BaseAnimal(3, "Golden_Retriever");

    public static readonly BaseAnimal Great_Dane = new BaseAnimal(4, "Great_Dane");

    // etc        
}

然后我就可以做这样的事情:

public void SomeMethod()
{
    var a = AnimalType.Amphibians;
    var b = AnimalType.Amphibians;

    if (a == b)
    {
        // should be equal
    }

    // call method as
    Foo(a);

    // using ifs
    if (a == AnimalType.Amphibians)
    {
    }
    else if (a == AnimalType.Invertebrate)
    {
    }
    else if (a == DogType.Golden_Retriever)
    {
    }
    // etc          
}

public void Foo(BaseAnimal typeOfAnimal)
{
}

简短的回答是否定的。如果你想，你可以玩一点:

你可以这样做:

private enum Base
{
    A,
    B,
    C
}

private enum Consume
{
    A = Base.A,
    B = Base.B,
    C = Base.C,
    D,
    E
}

但是，它并没有那么好，因为Base。A !=消费。一个

不过，你总是可以这样做:

public static class Extensions
{
    public static T As<T>(this Consume c) where T : struct
    {
        return (T)System.Enum.Parse(typeof(T), c.ToString(), false);
    }
}

为了在基础和消费之间交叉…

你也可以将枚举的值转换为整数，并将它们比较为整数而不是enum，但这也很糟糕。

扩展方法return应该将其类型转换为T类型。