a can only be final here. Why? How can I reassign a in onClick() method without keeping it as private member? private void f(Button b, final int a){ b.addClickHandler(new ClickHandler() { @Override public void onClick(ClickEvent event) { int b = a*5; } }); } How can I return the 5 * a when it clicked? I mean, private void f(Button b, final int a){ b.addClickHandler(new ClickHandler() { @Override public void onClick(ClickEvent event) { int b = a*5; return b; // but return type is void } }); }


当前回答

要理解这种限制的基本原理,请考虑以下程序:

public class Program {

    interface Interface {
        public void printInteger();
    }
    static Interface interfaceInstance = null;

    static void initialize(int val) {
        class Impl implements Interface {
            @Override
            public void printInteger() {
                System.out.println(val);
            }
        }
        interfaceInstance = new Impl();
    }

    public static void main(String[] args) {
        initialize(12345);
        interfaceInstance.printInteger();
    }
}

The interfaceInstance remains in memory after the initialize method returns, but the parameter val does not. The JVM can’t access a local variable outside its scope, so Java makes the subsequent call to printInteger work by copying the value of val to an implicit field of the same name within interfaceInstance. The interfaceInstance is said to have captured the value of the local parameter. If the parameter weren’t final (or effectively final) its value could change, becoming out of sync with the captured value, potentially causing unintuitive behavior.

其他回答

在Java中,变量不仅可以作为参数,还可以作为类级字段,例如

public class Test
{
 public final int a = 3;

或者作为一个局部变量

public static void main(String[] args)
{
 final int a = 3;

如果希望访问和修改匿名类中的变量,则可能希望将该变量设置为外围类中的类级变量。

public class Test
{
 public int a;
 public void doSomething()
 {
  Runnable runnable =
   new Runnable()
   {
    public void run()
    {
     System.out.println(a);
     a = a+1;
    }
   };
 }
}

你不能把一个变量作为final,然后给它一个新值。Final的意思就是:值是不可改变的和Final的。

由于它是最终的,Java可以安全地将其复制到本地匿名类。你没有得到对int的引用(特别是因为你在Java中不能有对int这样的原语的引用,只能引用对象)。

它只是将a的值复制到一个隐式int,在匿名类中称为a。

Java内部类中的final变量[关于]

内部类只能使用

外部类引用 final局部变量来自范围外的引用类型(例如Object…) 值(原语)(例如int…)类型可以由最终引用类型包装。IntelliJ IDEA可以帮助您将其转换为一个元素数组

当编译器生成一个非静态嵌套(内部类)时-一个新类- <OuterClass>$<InnerClass>.class创建并将有界参数传递给构造函数[堆栈上的局部变量],它类似于闭包[Swift about]

Final变量是不能重新赋值的变量。最终引用变量仍然可以通过修改状态来更改

如果这是可能的,那就奇怪了,因为作为一个程序员,你可以做出这样的东西

//Not possible 
private void foo() {

    MyClass myClass = new MyClass(); //Case 1: myClass address is 1
    int a = 5;                       //Case 2: a = 5

    //just as an example
    new Button().addClickHandler(new ClickHandler() {
        
        @Override
        public void onClick(ClickEvent event) {

            /*
            myClass.something(); //<- what is the address - 1 or 2?
            int b = a; //<- what is the value - 5 or 10 ?

            //illusion that next changes are visible for Outer class
            myClass = new MyClass();
            a = 15;
            */
        }
    });

    myClass = new MyClass(); //Case 1: myClass address is 2
    int a = 10; //Case 2: a = 10
}

也许这个把戏能给你启发

Boolean var= new anonymousClass(){
    private String myVar; //String for example
    @Overriden public Boolean method(int i){
          //use myVar and i
    }
    public String setVar(String var){myVar=var; return this;} //Returns self instane
}.setVar("Hello").method(3);

要理解这种限制的基本原理,请考虑以下程序:

public class Program {

    interface Interface {
        public void printInteger();
    }
    static Interface interfaceInstance = null;

    static void initialize(int val) {
        class Impl implements Interface {
            @Override
            public void printInteger() {
                System.out.println(val);
            }
        }
        interfaceInstance = new Impl();
    }

    public static void main(String[] args) {
        initialize(12345);
        interfaceInstance.printInteger();
    }
}

The interfaceInstance remains in memory after the initialize method returns, but the parameter val does not. The JVM can’t access a local variable outside its scope, so Java makes the subsequent call to printInteger work by copying the value of val to an implicit field of the same name within interfaceInstance. The interfaceInstance is said to have captured the value of the local parameter. If the parameter weren’t final (or effectively final) its value could change, becoming out of sync with the captured value, potentially causing unintuitive behavior.

有一个技巧允许匿名类在外部作用域中更新数据。

private void f(Button b, final int a) {
    final int[] res = new int[1];
    b.addClickHandler(new ClickHandler() {
        @Override
        public void onClick(ClickEvent event) {
            res[0] = a * 5;
        }
    });

    // But at this point handler is most likely not executed yet!
    // How should we now res[0] is ready?
}

然而,由于同步问题,这个技巧不是很好。如果处理程序稍后被调用,你需要1)同步访问res,如果处理程序从不同的线程调用2)需要有某种标志或指示res被更新

但是,如果匿名类在同一个线程中立即被调用,这个技巧就可以工作。如:

// ...

final int[] res = new int[1];
Runnable r = new Runnable() { public void run() { res[0] = 123; } };
r.run();
System.out.println(res[0]);

// ...