如何使用带有函数名称的字符串调用函数?例如:

import foo
func_name = "bar"
call(foo, func_name)  # calls foo.bar()

当前回答

试试这个。虽然这仍然使用eval,但它只使用它从当前上下文调用函数。然后,您就可以随心所欲地使用真正的函数了。

这对我的主要好处是,在调用函数时,您将得到任何与eval相关的错误。然后,当您调用时,只会得到与函数相关的错误。

def say_hello(name):
    print 'Hello {}!'.format(name)

# get the function by name
method_name = 'say_hello'
method = eval(method_name)

# call it like a regular function later
args = ['friend']
kwargs = {}
method(*args, **kwargs)

其他回答

还没有人提到operator.attrgetter:

>>> from operator import attrgetter
>>> l = [1, 2, 3]
>>> attrgetter('reverse')(l)()
>>> l
[3, 2, 1]
>>> 

getattr根据对象的名称调用方法。但此对象应该是调用类的父对象。父类可以由super(self.__class__,self)获取

class Base:
    def call_base(func):
        """This does not work"""
        def new_func(self, *args, **kwargs):
            name = func.__name__
            getattr(super(self.__class__, self), name)(*args, **kwargs)
        return new_func

    def f(self, *args):
        print(f"BASE method invoked.")

    def g(self, *args):
        print(f"BASE method invoked.")

class Inherit(Base):
    @Base.call_base
    def f(self, *args):
        """function body will be ignored by the decorator."""
        pass

    @Base.call_base
    def g(self, *args):
        """function body will be ignored by the decorator."""
        pass

Inherit().f() # The goal is to print "BASE method invoked."

给定带有方法栏的模块foo:

import foo
bar = getattr(foo, 'bar')
result = bar()

getattr可以类似地用于类实例绑定方法、模块级方法、类方法。。。名单还在继续。

虽然getattr()是一种优雅的(大约快7倍)方法,但您可以使用eval从函数(local、class方法、模块)获得返回值,其优雅程度与x=eval('fo.bar')()相同。当您实现一些错误处理时,就会非常安全(getattr也可以使用相同的原理)。模块导入和类示例:

# import module, call module function, pass parameters and print retured value with eval():
import random
bar = 'random.randint'
randint = eval(bar)(0,100)
print(randint) # will print random int from <0;100)

# also class method returning (or not) value(s) can be used with eval: 
class Say:
    def say(something='nothing'):
        return something

bar = 'Say.say'
print(eval(bar)('nice to meet you too')) # will print 'nice to meet you' 

当模块或类不存在(键入错误或其他更好的错误)时,就会引发NameError。如果函数不存在,则引发AttributeError。这可用于处理错误:

# try/except block can be used to catch both errors
try:
    eval('Say.talk')() # raises AttributeError because function does not exist
    eval('Says.say')() # raises NameError because the class does not exist
    # or the same with getattr:
    getattr(Say, 'talk')() # raises AttributeError
    getattr(Says, 'say')() # raises NameError
except AttributeError:
    # do domething or just...
    print('Function does not exist')
except NameError:
    # do domething or just...
    print('Module does not exist')

试试这个。虽然这仍然使用eval,但它只使用它从当前上下文调用函数。然后,您就可以随心所欲地使用真正的函数了。

这对我的主要好处是,在调用函数时,您将得到任何与eval相关的错误。然后,当您调用时,只会得到与函数相关的错误。

def say_hello(name):
    print 'Hello {}!'.format(name)

# get the function by name
method_name = 'say_hello'
method = eval(method_name)

# call it like a regular function later
args = ['friend']
kwargs = {}
method(*args, **kwargs)