如何使用带有函数名称的字符串调用函数?例如:

import foo
func_name = "bar"
call(foo, func_name)  # calls foo.bar()

当前回答

虽然getattr()是一种优雅的(大约快7倍)方法,但您可以使用eval从函数(local、class方法、模块)获得返回值,其优雅程度与x=eval('fo.bar')()相同。当您实现一些错误处理时,就会非常安全(getattr也可以使用相同的原理)。模块导入和类示例:

# import module, call module function, pass parameters and print retured value with eval():
import random
bar = 'random.randint'
randint = eval(bar)(0,100)
print(randint) # will print random int from <0;100)

# also class method returning (or not) value(s) can be used with eval: 
class Say:
    def say(something='nothing'):
        return something

bar = 'Say.say'
print(eval(bar)('nice to meet you too')) # will print 'nice to meet you' 

当模块或类不存在(键入错误或其他更好的错误)时,就会引发NameError。如果函数不存在,则引发AttributeError。这可用于处理错误:

# try/except block can be used to catch both errors
try:
    eval('Say.talk')() # raises AttributeError because function does not exist
    eval('Says.say')() # raises NameError because the class does not exist
    # or the same with getattr:
    getattr(Say, 'talk')() # raises AttributeError
    getattr(Says, 'say')() # raises NameError
except AttributeError:
    # do domething or just...
    print('Function does not exist')
except NameError:
    # do domething or just...
    print('Module does not exist')

其他回答

虽然getattr()是一种优雅的(大约快7倍)方法,但您可以使用eval从函数(local、class方法、模块)获得返回值,其优雅程度与x=eval('fo.bar')()相同。当您实现一些错误处理时,就会非常安全(getattr也可以使用相同的原理)。模块导入和类示例:

# import module, call module function, pass parameters and print retured value with eval():
import random
bar = 'random.randint'
randint = eval(bar)(0,100)
print(randint) # will print random int from <0;100)

# also class method returning (or not) value(s) can be used with eval: 
class Say:
    def say(something='nothing'):
        return something

bar = 'Say.say'
print(eval(bar)('nice to meet you too')) # will print 'nice to meet you' 

当模块或类不存在(键入错误或其他更好的错误)时,就会引发NameError。如果函数不存在,则引发AttributeError。这可用于处理错误:

# try/except block can be used to catch both errors
try:
    eval('Say.talk')() # raises AttributeError because function does not exist
    eval('Says.say')() # raises NameError because the class does not exist
    # or the same with getattr:
    getattr(Say, 'talk')() # raises AttributeError
    getattr(Says, 'say')() # raises NameError
except AttributeError:
    # do domething or just...
    print('Function does not exist')
except NameError:
    # do domething or just...
    print('Module does not exist')

试试这个。虽然这仍然使用eval,但它只使用它从当前上下文调用函数。然后,您就可以随心所欲地使用真正的函数了。

这对我的主要好处是,在调用函数时,您将得到任何与eval相关的错误。然后,当您调用时,只会得到与函数相关的错误。

def say_hello(name):
    print 'Hello {}!'.format(name)

# get the function by name
method_name = 'say_hello'
method = eval(method_name)

# call it like a regular function later
args = ['friend']
kwargs = {}
method(*args, **kwargs)

根据Python编程常见问题解答,最好的答案是:

functions = {'myfoo': foo.bar}

mystring = 'myfoo'
if mystring in functions:
    functions[mystring]()

这种技术的主要优点是字符串不需要与函数的名称匹配。这也是用于模拟案例构造的主要技术

这些建议对我都没有帮助。但我确实发现了这一点。

<object>.__getattribute__(<string name>)(<params>)

我使用的是python 2.66

希望这有帮助

答案(我希望)从来没有人想要

Eval样行为

getattr(locals().get("foo") or globals().get("foo"), "bar")()

为什么不添加自动导入

getattr(
    locals().get("foo") or 
    globals().get("foo") or
    __import__("foo"), 
"bar")()

万一我们有多余的字典要查

getattr(next((x for x in (f("foo") for f in 
                          [locals().get, globals().get, 
                           self.__dict__.get, __import__]) 
              if x)),
"bar")()

我们需要更深入

getattr(next((x for x in (f("foo") for f in 
              ([locals().get, globals().get, self.__dict__.get] +
               [d.get for d in (list(dd.values()) for dd in 
                                [locals(),globals(),self.__dict__]
                                if isinstance(dd,dict))
                if isinstance(d,dict)] + 
               [__import__])) 
        if x)),
"bar")()