一种无重复的随机生成器函数，使用一个集合来存储以前生成的值。注意，如果字符串或数量非常大，这将消耗一些内存，而且可能会稍微慢一点。发电机将在给定量或达到最大可能组合时停止。

代码：

#!/usr/bin/env python

from typing import Generator
from random import SystemRandom as RND
from string import ascii_uppercase, digits


def string_generator(size: int = 1, amount: int = 1) -> Generator[str, None, None]:
    """
    Return x random strings of a fixed length.

    :param size: string length, defaults to 1
    :type size: int, optional
    :param amount: amount of random strings to generate, defaults to 1
    :type amount: int, optional
    :yield: Yield composed random string if unique
    :rtype: Generator[str, None, None]
    """
    CHARS = list(ascii_uppercase + digits)
    LIMIT = len(CHARS) ** size
    count, check, string = 0, set(), ''
    while LIMIT > count < amount:
        string = ''.join(RND().choices(CHARS, k=size))
        if string not in check:
            check.add(string)
            yield string
            count += 1


for my_count, my_string in enumerate(string_generator(6, 20)):
    print(my_count, my_string)

输出：

0 RS9N3P
1 S0GDGR
2 ZNBLFV
3 96FF97
4 38JJZ3
5 Q3214A
6 VLWNK1
7 QMT05E
8 X1ZFP0
9 MZF442
10 10L9AZ
11 GE8HIQ
12 S7PA43
13 MVLXO9
14 YX7Y0G
15 GIIKPF
16 3KCUQA
17 XHIXFV
18 BJQ5VG
19 HQF01Q

如果字符串始终需要包含字母和数字，请使用以下命令：

#!/usr/bin/env python

from typing import Generator
from random import SystemRandom as RND
from string import ascii_uppercase, digits


def string_generator(size: int = 2, amount: int = 1) -> Generator[str, None, None]:
    """
    Return x random strings of a fixed length.

    :param size: string length, defaults to 1
    :type size: int, optional
    :param amount: amount of random strings to generate, defaults to 1
    :type amount: int, optional
    :yield: Yield composed random string if unique
    :rtype: Generator[str, None, None]
    """
    if size < 2:
        print(
            'Since the string must contain letters and numbers,',
            'its size must be at least two characters',
        )
        return
    CHARS = list(ascii_uppercase + digits)
    LIMIT = len(CHARS) ** size
    count, check, string = 0, set(), ''
    while LIMIT > count < amount:
        while 1:
            string = ''.join(RND().choices(CHARS, k=size))
            if not (string.isalpha() or string.isnumeric()):
                break
        if string not in check:
            check.add(string)
            yield string
            count += 1


for my_count, my_string in enumerate(string_generator(6, 20)):
    print(my_count, my_string)

输出：

0 5JIITL
1 3W7AI1
2 8QMO10
3 ETHAI8
4 BLFPP9
5 50X2CC
6 1LI8WA
7 39CKET
8 R4IM0E
9 Q3KHGS
10 65CBIU
11 XTRHO4
12 N2XIGO
13 06VFCW
14 VE9MJ8
15 A9ADHK
16 Y5ROJ0
17 OH7EJF
18 TQ709S
19 P0DDNJ

只需使用Python的内置uuid：

如果uuid适合您的用途，请使用内置的uuid包。

单线解决方案：

导入uuid；uuid.uuid4（）.hhex.upper（）[0:6]

深度版本：

例子：

import uuid
uuid.uuid4() #uuid4 => full random uuid
# Outputs something like: UUID('0172fc9a-1dac-4414-b88d-6b9a6feb91ea')

如果您完全需要您的格式（例如，“6U1S75”），可以这样做：

import uuid

def my_random_string(string_length=10):
    """Returns a random string of length string_length."""
    random = str(uuid.uuid4()) # Convert UUID format to a Python string.
    random = random.upper() # Make all characters uppercase.
    random = random.replace("-","") # Remove the UUID '-'.
    return random[0:string_length] # Return the random string.

print(my_random_string(6)) # For example, D9E50C

从Python 3.6开始，如果你需要密码安全，你应该使用secrets模块，而不是随机模块（否则这个答案与@Ignacio Vazquez Abrams的答案相同）：

from secrets import choice
import string

''.join([choice(string.ascii_uppercase + string.digits) for _ in range(N)])

还有一点需要注意：在str.join的情况下，列表理解比使用生成器表达式更快！

对于那些喜欢功能python的人：

from itertools import imap, starmap, islice, repeat
from functools import partial
from string import letters, digits, join
from random import choice

join_chars = partial(join, sep='')
identity = lambda o: o

def irand_seqs(symbols=join_chars((letters, digits)), length=6, join=join_chars, select=choice, breakup=islice):
    """ Generates an indefinite sequence of joined random symbols each of a specific length
    :param symbols: symbols to select,
        [defaults to string.letters + string.digits, digits 0 - 9, lower and upper case English letters.]
    :param length: the length of each sequence,
        [defaults to 6]
    :param join: method used to join selected symbol, 
        [defaults to ''.join generating a string.]
    :param select: method used to select a random element from the giving population. 
        [defaults to random.choice, which selects a single element randomly]
    :return: indefinite iterator generating random sequences of giving [:param length]
    >>> from tools import irand_seqs
    >>> strings = irand_seqs()
    >>> a = next(strings)
    >>> assert isinstance(a, (str, unicode))
    >>> assert len(a) == 6
    >>> assert next(strings) != next(strings)
    """
    return imap(join, starmap(breakup, repeat((imap(select, repeat(symbols)), None, length))))

它生成一个不定[无限]迭代器，由连接的随机序列组成，首先从给定的池中生成一个随机选择的符号的不定序列，然后将该序列分解为长度部分，然后进行连接，它应该与支持getitem的任何序列一起工作，默认情况下，它只生成一个字母数字字母的随机序列，尽管您可以轻松修改以生成其他内容：

例如生成数字的随机元组：

>>> irand_tuples = irand_seqs(xrange(10), join=tuple)
>>> next(irand_tuples)
(0, 5, 5, 7, 2, 8)
>>> next(irand_tuples)
(3, 2, 2, 0, 3, 1)

如果您不想使用next for generation，您可以简单地将其设置为可调用：

>>> irand_tuples = irand_seqs(xrange(10), join=tuple)
>>> make_rand_tuples = partial(next, irand_tuples) 
>>> make_rand_tuples()
(1, 6, 2, 8, 1, 9)

如果您想动态生成序列，只需将join设置为identity即可。

>>> irand_tuples = irand_seqs(xrange(10), join=identity)
>>> selections = next(irand_tuples)
>>> next(selections)
8
>>> list(selections)
[6, 3, 8, 2, 2]

正如其他人所提到的，如果您需要更多的安全性，请设置相应的选择功能：

>>> from random import SystemRandom
>>> rand_strs = irand_seqs(select=SystemRandom().choice)
'QsaDxQ'

默认选择器是choice，它可以为每个块多次选择相同的符号，如果相反，您希望为每个块最多选择一次相同的成员，则有一种可能的用法：

>>> from random import sample
>>> irand_samples = irand_seqs(xrange(10), length=1, join=next, select=lambda pool: sample(pool, 6))
>>> next(irand_samples)
[0, 9, 2, 3, 1, 6]

我们使用sample作为选择器，进行完整的选择，因此块的长度实际上是1，为了加入，我们只需调用next，它获取下一个完全生成的块，当然这个示例看起来有点麻烦，而且它。。。

>>> import string 
>>> import random

以下逻辑仍然生成6个字符的随机样本

>>> print ''.join(random.sample((string.ascii_uppercase+string.digits),6))
JT7K3Q

无需乘以6

>>> print ''.join(random.sample((string.ascii_uppercase+string.digits)*6,6))

TK82HK

一种无重复的随机生成器函数，使用一个集合来存储以前生成的值。注意，如果字符串或数量非常大，这将消耗一些内存，而且可能会稍微慢一点。发电机将在给定量或达到最大可能组合时停止。

代码：

#!/usr/bin/env python

from typing import Generator
from random import SystemRandom as RND
from string import ascii_uppercase, digits


def string_generator(size: int = 1, amount: int = 1) -> Generator[str, None, None]:
    """
    Return x random strings of a fixed length.

    :param size: string length, defaults to 1
    :type size: int, optional
    :param amount: amount of random strings to generate, defaults to 1
    :type amount: int, optional
    :yield: Yield composed random string if unique
    :rtype: Generator[str, None, None]
    """
    CHARS = list(ascii_uppercase + digits)
    LIMIT = len(CHARS) ** size
    count, check, string = 0, set(), ''
    while LIMIT > count < amount:
        string = ''.join(RND().choices(CHARS, k=size))
        if string not in check:
            check.add(string)
            yield string
            count += 1


for my_count, my_string in enumerate(string_generator(6, 20)):
    print(my_count, my_string)

输出：

0 RS9N3P
1 S0GDGR
2 ZNBLFV
3 96FF97
4 38JJZ3
5 Q3214A
6 VLWNK1
7 QMT05E
8 X1ZFP0
9 MZF442
10 10L9AZ
11 GE8HIQ
12 S7PA43
13 MVLXO9
14 YX7Y0G
15 GIIKPF
16 3KCUQA
17 XHIXFV
18 BJQ5VG
19 HQF01Q

如果字符串始终需要包含字母和数字，请使用以下命令：

#!/usr/bin/env python

from typing import Generator
from random import SystemRandom as RND
from string import ascii_uppercase, digits


def string_generator(size: int = 2, amount: int = 1) -> Generator[str, None, None]:
    """
    Return x random strings of a fixed length.

    :param size: string length, defaults to 1
    :type size: int, optional
    :param amount: amount of random strings to generate, defaults to 1
    :type amount: int, optional
    :yield: Yield composed random string if unique
    :rtype: Generator[str, None, None]
    """
    if size < 2:
        print(
            'Since the string must contain letters and numbers,',
            'its size must be at least two characters',
        )
        return
    CHARS = list(ascii_uppercase + digits)
    LIMIT = len(CHARS) ** size
    count, check, string = 0, set(), ''
    while LIMIT > count < amount:
        while 1:
            string = ''.join(RND().choices(CHARS, k=size))
            if not (string.isalpha() or string.isnumeric()):
                break
        if string not in check:
            check.add(string)
            yield string
            count += 1


for my_count, my_string in enumerate(string_generator(6, 20)):
    print(my_count, my_string)

输出：

0 5JIITL
1 3W7AI1
2 8QMO10
3 ETHAI8
4 BLFPP9
5 50X2CC
6 1LI8WA
7 39CKET
8 R4IM0E
9 Q3KHGS
10 65CBIU
11 XTRHO4
12 N2XIGO
13 06VFCW
14 VE9MJ8
15 A9ADHK
16 Y5ROJ0
17 OH7EJF
18 TQ709S
19 P0DDNJ