如何生成大小为N的字符串,由数字和大写英文字母组成,例如:
6个754z4英国U911K4型
如何生成大小为N的字符串,由数字和大写英文字母组成,例如:
6个754z4英国U911K4型
当前回答
一种无重复的随机生成器函数,使用一个集合来存储以前生成的值。注意,如果字符串或数量非常大,这将消耗一些内存,而且可能会稍微慢一点。发电机将在给定量或达到最大可能组合时停止。
代码:
#!/usr/bin/env python
from typing import Generator
from random import SystemRandom as RND
from string import ascii_uppercase, digits
def string_generator(size: int = 1, amount: int = 1) -> Generator[str, None, None]:
"""
Return x random strings of a fixed length.
:param size: string length, defaults to 1
:type size: int, optional
:param amount: amount of random strings to generate, defaults to 1
:type amount: int, optional
:yield: Yield composed random string if unique
:rtype: Generator[str, None, None]
"""
CHARS = list(ascii_uppercase + digits)
LIMIT = len(CHARS) ** size
count, check, string = 0, set(), ''
while LIMIT > count < amount:
string = ''.join(RND().choices(CHARS, k=size))
if string not in check:
check.add(string)
yield string
count += 1
for my_count, my_string in enumerate(string_generator(6, 20)):
print(my_count, my_string)
输出:
0 RS9N3P
1 S0GDGR
2 ZNBLFV
3 96FF97
4 38JJZ3
5 Q3214A
6 VLWNK1
7 QMT05E
8 X1ZFP0
9 MZF442
10 10L9AZ
11 GE8HIQ
12 S7PA43
13 MVLXO9
14 YX7Y0G
15 GIIKPF
16 3KCUQA
17 XHIXFV
18 BJQ5VG
19 HQF01Q
如果字符串始终需要包含字母和数字,请使用以下命令:
#!/usr/bin/env python
from typing import Generator
from random import SystemRandom as RND
from string import ascii_uppercase, digits
def string_generator(size: int = 2, amount: int = 1) -> Generator[str, None, None]:
"""
Return x random strings of a fixed length.
:param size: string length, defaults to 1
:type size: int, optional
:param amount: amount of random strings to generate, defaults to 1
:type amount: int, optional
:yield: Yield composed random string if unique
:rtype: Generator[str, None, None]
"""
if size < 2:
print(
'Since the string must contain letters and numbers,',
'its size must be at least two characters',
)
return
CHARS = list(ascii_uppercase + digits)
LIMIT = len(CHARS) ** size
count, check, string = 0, set(), ''
while LIMIT > count < amount:
while 1:
string = ''.join(RND().choices(CHARS, k=size))
if not (string.isalpha() or string.isnumeric()):
break
if string not in check:
check.add(string)
yield string
count += 1
for my_count, my_string in enumerate(string_generator(6, 20)):
print(my_count, my_string)
输出:
0 5JIITL
1 3W7AI1
2 8QMO10
3 ETHAI8
4 BLFPP9
5 50X2CC
6 1LI8WA
7 39CKET
8 R4IM0E
9 Q3KHGS
10 65CBIU
11 XTRHO4
12 N2XIGO
13 06VFCW
14 VE9MJ8
15 A9ADHK
16 Y5ROJ0
17 OH7EJF
18 TQ709S
19 P0DDNJ
其他回答
这是对Anurak Uniyal的回应的一种理解,也是我自己在研究的东西。
import random
import string
oneFile = open('Numbers.txt', 'w')
userInput = 0
key_count = 0
value_count = 0
chars = string.ascii_uppercase + string.digits + string.punctuation
for userInput in range(int(input('How many 12 digit keys do you want?'))):
while key_count <= userInput:
key_count += 1
number = random.randint(1, 999)
key = number
text = str(key) + ": " + str(''.join(random.sample(chars*6, 12)))
oneFile.write(text + "\n")
oneFile.close()
我会这样做:
import random
from string import digits, ascii_uppercase
legals = digits + ascii_uppercase
def rand_string(length, char_set=legals):
output = ''
for _ in range(length): output += random.choice(char_set)
return output
或者只是:
def rand_string(length, char_set=legals):
return ''.join( random.choice(char_set) for _ in range(length) )
(1) 这将为您提供所有大写和数字:
import string, random
passkey=''
for x in range(8):
if random.choice([1,2]) == 1:
passkey += passkey.join(random.choice(string.ascii_uppercase))
else:
passkey += passkey.join(random.choice(string.digits))
print passkey
(2) 如果您以后想在密钥中包含小写字母,那么这也可以:
import string, random
passkey=''
for x in range(8):
if random.choice([1,2]) == 1:
passkey += passkey.join(random.choice(string.ascii_letters))
else:
passkey += passkey.join(random.choice(string.digits))
print passkey
>>> import string
>>> import random
以下逻辑仍然生成6个字符的随机样本
>>> print ''.join(random.sample((string.ascii_uppercase+string.digits),6))
JT7K3Q
无需乘以6
>>> print ''.join(random.sample((string.ascii_uppercase+string.digits)*6,6))
TK82HK
生成包含字母、数字、“_”和“-”的随机16字节ID
os.urantom(16).translate((f'{string.ascii_letters}{string.digitals}-'*4).encode('ascii'))